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cocATP---0.2.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : NUM695^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n129.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:28 EST 2018

% Result   : Theorem 0.99s
% Output   : Proof 0.99s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM695^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.23  % Computer : n129.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.625MB
% 0.02/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Jan  5 13:00:49 CST 2018
% 0.02/0.23  % CPUTime  : 
% 0.06/0.25  Python 2.7.13
% 0.99/1.20  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124efb4a70>, <kernel.Type object at 0x2b124efb4368>) of role type named nat_type
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring nat:Type
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124ebc2d88>, <kernel.Constant object at 0x2b124efb4ef0>) of role type named x
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring x:nat
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124ebc2d88>, <kernel.DependentProduct object at 0x2b124efb4320>) of role type named more
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring more:(nat->(nat->Prop))
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124efb4638>, <kernel.DependentProduct object at 0x2b124efb4cb0>) of role type named suc
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring suc:(nat->nat)
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124efb4ef0>, <kernel.Constant object at 0x2b124efb4cb0>) of role type named n_1
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring n_1:nat
% 0.99/1.20  FOF formula (forall (Xa:Prop), (((Xa->False)->False)->Xa)) of role axiom named et
% 0.99/1.20  A new axiom: (forall (Xa:Prop), (((Xa->False)->False)->Xa))
% 0.99/1.20  FOF formula (forall (Xx:nat), ((not (((eq nat) Xx) n_1))->((forall (Xx_0:nat), (not (((eq nat) Xx) (suc Xx_0))))->False))) of role axiom named satz3
% 0.99/1.20  A new axiom: (forall (Xx:nat), ((not (((eq nat) Xx) n_1))->((forall (Xx_0:nat), (not (((eq nat) Xx) (suc Xx_0))))->False)))
% 0.99/1.20  FOF formula (forall (Xx:nat), (not (((eq nat) (suc Xx)) n_1))) of role axiom named ax3
% 0.99/1.20  A new axiom: (forall (Xx:nat), (not (((eq nat) (suc Xx)) n_1)))
% 0.99/1.20  FOF formula (<kernel.Constant object at 0x2b124efb46c8>, <kernel.DependentProduct object at 0x2b124efb4710>) of role type named pl
% 0.99/1.20  Using role type
% 0.99/1.20  Declaring pl:(nat->(nat->nat))
% 0.99/1.20  FOF formula (forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx)) of role axiom named satz18
% 0.99/1.20  A new axiom: (forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx))
% 0.99/1.20  FOF formula (forall (Xx:nat), (((eq nat) (suc Xx)) ((pl n_1) Xx))) of role axiom named satz4g
% 0.99/1.20  A new axiom: (forall (Xx:nat), (((eq nat) (suc Xx)) ((pl n_1) Xx)))
% 0.99/1.20  FOF formula ((more (suc x)) n_1) of role conjecture named satz24b
% 0.99/1.20  Conjecture to prove = ((more (suc x)) n_1):Prop
% 0.99/1.20  We need to prove ['((more (suc x)) n_1)']
% 0.99/1.20  Parameter nat:Type.
% 0.99/1.20  Parameter x:nat.
% 0.99/1.20  Parameter more:(nat->(nat->Prop)).
% 0.99/1.20  Parameter suc:(nat->nat).
% 0.99/1.20  Parameter n_1:nat.
% 0.99/1.20  Axiom et:(forall (Xa:Prop), (((Xa->False)->False)->Xa)).
% 0.99/1.20  Axiom satz3:(forall (Xx:nat), ((not (((eq nat) Xx) n_1))->((forall (Xx_0:nat), (not (((eq nat) Xx) (suc Xx_0))))->False))).
% 0.99/1.20  Axiom ax3:(forall (Xx:nat), (not (((eq nat) (suc Xx)) n_1))).
% 0.99/1.20  Parameter pl:(nat->(nat->nat)).
% 0.99/1.20  Axiom satz18:(forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx)).
% 0.99/1.20  Axiom satz4g:(forall (Xx:nat), (((eq nat) (suc Xx)) ((pl n_1) Xx))).
% 0.99/1.20  Trying to prove ((more (suc x)) n_1)
% 0.99/1.20  Found satz1800:=(satz180 x):((more ((pl n_1) x)) n_1)
% 0.99/1.20  Found (satz180 x) as proof of ((more ((pl n_1) x)) n_1)
% 0.99/1.20  Found ((satz18 n_1) x) as proof of ((more ((pl n_1) x)) n_1)
% 0.99/1.20  Found ((satz18 n_1) x) as proof of ((more ((pl n_1) x)) n_1)
% 0.99/1.20  Found (satz4g__eq_sym00 ((satz18 n_1) x)) as proof of ((more (suc x)) n_1)
% 0.99/1.20  Found ((satz4g__eq_sym0 (fun (x1:nat)=> ((more x1) n_1))) ((satz18 n_1) x)) as proof of ((more (suc x)) n_1)
% 0.99/1.20  Found (((satz4g__eq_sym x) (fun (x1:nat)=> ((more x1) n_1))) ((satz18 n_1) x)) as proof of ((more (suc x)) n_1)
% 0.99/1.20  Found (((satz4g__eq_sym x) (fun (x1:nat)=> ((more x1) n_1))) ((satz18 n_1) x)) as proof of ((more (suc x)) n_1)
% 0.99/1.20  Got proof ((((fun (Xx:nat)=> ((((eq_sym nat) (suc Xx)) ((pl n_1) Xx)) (satz4g Xx))) x) (fun (x1:nat)=> ((more x1) n_1))) ((satz18 n_1) x))
% 0.99/1.20  Time elapsed = 0.670488s
% 0.99/1.20  node=148 cost=348.000000 depth=6
% 0.99/1.20::::::::::::::::::::::
% 0.99/1.20  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.99/1.20  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.99/1.20  ((((fun (Xx:nat)=> ((((eq_sym nat) (suc Xx)) ((pl n_1) Xx)) (satz4g Xx))) x) (fun (x1:nat)=> ((more x1) n_1))) ((satz18 n_1) x))
% 0.99/1.20  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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