%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM697^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n183.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:29 EST 2018 % Result : Theorem 0.37s % Output : Proof 0.37s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM697^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n183.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 13:04:04 CST 2018 % 0.02/0.23 % CPUTime : % 0.06/0.25 Python 2.7.13 % 0.37/0.58 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadaf80>, <kernel.Type object at 0x2acb5aadaf38>) of role type named nat_type % 0.37/0.58 Using role type % 0.37/0.58 Declaring nat:Type % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadab48>, <kernel.Constant object at 0x2acb5aadae60>) of role type named x % 0.37/0.58 Using role type % 0.37/0.58 Declaring x:nat % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5a087ea8>, <kernel.Constant object at 0x2acb5aadae60>) of role type named y % 0.37/0.58 Using role type % 0.37/0.58 Declaring y:nat % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadaf80>, <kernel.DependentProduct object at 0x2acb5ab00518>) of role type named more % 0.37/0.58 Using role type % 0.37/0.58 Declaring more:(nat->(nat->Prop)) % 0.37/0.58 FOF formula ((more y) x) of role axiom named m % 0.37/0.58 A new axiom: ((more y) x) % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadaf80>, <kernel.DependentProduct object at 0x2acb5ab00bd8>) of role type named moreis % 0.37/0.58 Using role type % 0.37/0.58 Declaring moreis:(nat->(nat->Prop)) % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadab48>, <kernel.DependentProduct object at 0x2acb5ab003f8>) of role type named suc % 0.37/0.58 Using role type % 0.37/0.58 Declaring suc:(nat->nat) % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadae60>, <kernel.DependentProduct object at 0x2acb5ab000e0>) of role type named pl % 0.37/0.58 Using role type % 0.37/0.58 Declaring pl:(nat->(nat->nat)) % 0.37/0.58 FOF formula (<kernel.Constant object at 0x2acb5aadae60>, <kernel.Constant object at 0x2acb5ab000e0>) of role type named n_1 % 0.37/0.58 Using role type % 0.37/0.58 Declaring n_1:nat % 0.37/0.58 FOF formula (forall (Xx:nat) (Xy:nat), (((more Xy) Xx)->((moreis Xy) ((pl Xx) n_1)))) of role axiom named satz25 % 0.37/0.58 A new axiom: (forall (Xx:nat) (Xy:nat), (((more Xy) Xx)->((moreis Xy) ((pl Xx) n_1)))) % 0.37/0.58 FOF formula (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) of role axiom named satz4a % 0.37/0.58 A new axiom: (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) % 0.37/0.58 FOF formula ((moreis y) (suc x)) of role conjecture named satz25a % 0.37/0.58 Conjecture to prove = ((moreis y) (suc x)):Prop % 0.37/0.58 We need to prove ['((moreis y) (suc x))'] % 0.37/0.58 Parameter nat:Type. % 0.37/0.58 Parameter x:nat. % 0.37/0.58 Parameter y:nat. % 0.37/0.58 Parameter more:(nat->(nat->Prop)). % 0.37/0.58 Axiom m:((more y) x). % 0.37/0.58 Parameter moreis:(nat->(nat->Prop)). % 0.37/0.58 Parameter suc:(nat->nat). % 0.37/0.58 Parameter pl:(nat->(nat->nat)). % 0.37/0.58 Parameter n_1:nat. % 0.37/0.58 Axiom satz25:(forall (Xx:nat) (Xy:nat), (((more Xy) Xx)->((moreis Xy) ((pl Xx) n_1)))). % 0.37/0.58 Axiom satz4a:(forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))). % 0.37/0.58 Trying to prove ((moreis y) (suc x)) % 0.37/0.58 Found m:((more y) x) % 0.37/0.58 Found m as proof of ((more y) x) % 0.37/0.58 Found (satz2500 m) as proof of ((moreis y) ((pl x) n_1)) % 0.37/0.58 Found ((satz250 y) m) as proof of ((moreis y) ((pl x) n_1)) % 0.37/0.58 Found (((satz25 x) y) m) as proof of ((moreis y) ((pl x) n_1)) % 0.37/0.58 Found (((satz25 x) y) m) as proof of ((moreis y) ((pl x) n_1)) % 0.37/0.58 Found (satz4a00 (((satz25 x) y) m)) as proof of ((moreis y) (suc x)) % 0.37/0.58 Found ((satz4a0 (moreis y)) (((satz25 x) y) m)) as proof of ((moreis y) (suc x)) % 0.37/0.58 Found (((satz4a x) (moreis y)) (((satz25 x) y) m)) as proof of ((moreis y) (suc x)) % 0.37/0.58 Found (((satz4a x) (moreis y)) (((satz25 x) y) m)) as proof of ((moreis y) (suc x)) % 0.37/0.58 Got proof (((satz4a x) (moreis y)) (((satz25 x) y) m)) % 0.37/0.58 Time elapsed = 0.048925s % 0.37/0.58 node=15 cost=109.000000 depth=8 % 0.37/0.58:::::::::::::::::::::: % 0.37/0.58 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.37/0.58 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.37/0.58 (((satz4a x) (moreis y)) (((satz25 x) y) m)) % 0.37/0.58 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------