%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM699^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n087.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:29 EST 2018 % Result : Theorem 0.39s % Output : Proof 0.39s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.04 % Problem : NUM699^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.02/0.24 % Computer : n087.star.cs.uiowa.edu % 0.02/0.24 % Model : x86_64 x86_64 % 0.02/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.24 % Memory : 32218.625MB % 0.02/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.24 % CPULimit : 300 % 0.02/0.24 % DateTime : Fri Jan 5 13:05:34 CST 2018 % 0.02/0.24 % CPUTime : % 0.02/0.25 Python 2.7.13 % 0.39/0.58 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.Type object at 0x2b2f40130680>) of role type named nat_type % 0.39/0.58 Using role type % 0.39/0.58 Declaring nat:Type % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130200>, <kernel.Constant object at 0x2b2f40130368>) of role type named x % 0.39/0.58 Using role type % 0.39/0.58 Declaring x:nat % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f3889f680>, <kernel.Constant object at 0x2b2f40130368>) of role type named y % 0.39/0.58 Using role type % 0.39/0.58 Declaring y:nat % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.DependentProduct object at 0x2b2f40140fc8>) of role type named less % 0.39/0.58 Using role type % 0.39/0.58 Declaring less:(nat->(nat->Prop)) % 0.39/0.58 FOF formula ((less y) x) of role axiom named l % 0.39/0.58 A new axiom: ((less y) x) % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.DependentProduct object at 0x2b2f40140c20>) of role type named lessis % 0.39/0.58 Using role type % 0.39/0.58 Declaring lessis:(nat->(nat->Prop)) % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130200>, <kernel.DependentProduct object at 0x2b2f40140e18>) of role type named suc % 0.39/0.58 Using role type % 0.39/0.58 Declaring suc:(nat->nat) % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130368>, <kernel.DependentProduct object at 0x2b2f40140950>) of role type named pl % 0.39/0.58 Using role type % 0.39/0.58 Declaring pl:(nat->(nat->nat)) % 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130368>, <kernel.Constant object at 0x2b2f40140950>) of role type named n_1 % 0.39/0.58 Using role type % 0.39/0.58 Declaring n_1:nat % 0.39/0.58 FOF formula (forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx))) of role axiom named satz25b % 0.39/0.58 A new axiom: (forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx))) % 0.39/0.58 FOF formula (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) of role axiom named satz4a % 0.39/0.58 A new axiom: (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) % 0.39/0.58 FOF formula ((lessis (suc y)) x) of role conjecture named satz25c % 0.39/0.58 Conjecture to prove = ((lessis (suc y)) x):Prop % 0.39/0.58 We need to prove ['((lessis (suc y)) x)'] % 0.39/0.58 Parameter nat:Type. % 0.39/0.58 Parameter x:nat. % 0.39/0.58 Parameter y:nat. % 0.39/0.58 Parameter less:(nat->(nat->Prop)). % 0.39/0.58 Axiom l:((less y) x). % 0.39/0.58 Parameter lessis:(nat->(nat->Prop)). % 0.39/0.58 Parameter suc:(nat->nat). % 0.39/0.58 Parameter pl:(nat->(nat->nat)). % 0.39/0.58 Parameter n_1:nat. % 0.39/0.58 Axiom satz25b:(forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx))). % 0.39/0.58 Axiom satz4a:(forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))). % 0.39/0.58 Trying to prove ((lessis (suc y)) x) % 0.39/0.58 Found l:((less y) x) % 0.39/0.58 Found l as proof of ((less y) x) % 0.39/0.58 Found (satz25b00 l) as proof of ((lessis ((pl y) n_1)) x) % 0.39/0.58 Found ((satz25b0 y) l) as proof of ((lessis ((pl y) n_1)) x) % 0.39/0.58 Found (((satz25b x) y) l) as proof of ((lessis ((pl y) n_1)) x) % 0.39/0.58 Found (((satz25b x) y) l) as proof of ((lessis ((pl y) n_1)) x) % 0.39/0.58 Found (satz4a00 (((satz25b x) y) l)) as proof of ((lessis (suc y)) x) % 0.39/0.58 Found ((satz4a0 (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x) % 0.39/0.58 Found (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x) % 0.39/0.58 Found (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x) % 0.39/0.58 Got proof (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) % 0.39/0.58 Time elapsed = 0.047525s % 0.39/0.58 node=14 cost=108.000000 depth=8 % 0.39/0.58:::::::::::::::::::::: % 0.39/0.58 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.39/0.58 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.39/0.58 (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) % 0.39/0.58 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------