%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM707^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n021.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:08 PM UTC 2025 % Result : Theorem 3.50s 3.67s % Output : Proof 3.50s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.02/0.12 % Problem : NUM707^1 : TPTP v9.2.0. Released v3.7.0. % 0.02/0.13 % Command : duper %s % 0.12/0.34 % Computer : n021.cluster.edu % 0.12/0.34 % Model : x86_64 x86_64 % 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.34 % Memory : 8042.1875MB % 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.34 % CPULimit : 300 % 0.12/0.34 % WCLimit : 300 % 0.12/0.34 % DateTime : Fri Oct 3 07:58:23 EDT 2025 % 0.12/0.34 % CPUTime : % 3.50/3.67 SZS status Theorem for theBenchmark.p % 3.50/3.67 SZS output start Proof for theBenchmark.p % 3.50/3.67 Clause #0 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (ts Xx (suc Xy)) (pl (ts Xx Xy) Xx)) True % 3.50/3.67 Clause #1 (by assumption #[]): Eq (Not (Eq (pl (ts x y) x) (ts x (suc y)))) True % 3.50/3.67 Clause #2 (by clausification #[1]): Eq (Eq (pl (ts x y) x) (ts x (suc y))) False % 3.50/3.67 Clause #3 (by clausification #[2]): Ne (pl (ts x y) x) (ts x (suc y)) % 3.50/3.67 Clause #4 (by clausification #[0]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (ts a (suc Xy)) (pl (ts a Xy) a)) True % 3.50/3.67 Clause #5 (by clausification #[4]): ∀ (a a_1 : nat), Eq (Eq (ts a (suc a_1)) (pl (ts a a_1) a)) True % 3.50/3.67 Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (ts a (suc a_1)) (pl (ts a a_1) a) % 3.50/3.67 Clause #8 (by backward contextual literal cutting #[6, 3]): False % 3.50/3.67 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------