%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM707^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n171.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:31 EST 2018 % Result : Theorem 0.51s % Output : Proof 0.51s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM707^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.03/0.23 % Computer : n171.star.cs.uiowa.edu % 0.03/0.23 % Model : x86_64 x86_64 % 0.03/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.23 % Memory : 32218.625MB % 0.03/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.23 % CPULimit : 300 % 0.03/0.23 % DateTime : Fri Jan 5 13:07:50 CST 2018 % 0.03/0.23 % CPUTime : % 0.03/0.25 Python 2.7.13 % 0.51/0.70 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.Type object at 0x2b782a22fe18>) of role type named nat_type % 0.51/0.70 Using role type % 0.51/0.70 Declaring nat:Type % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22fcf8>, <kernel.Constant object at 0x2b782a22fea8>) of role type named x % 0.51/0.70 Using role type % 0.51/0.70 Declaring x:nat % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a30df38>, <kernel.Constant object at 0x2b782a22fea8>) of role type named y % 0.51/0.70 Using role type % 0.51/0.70 Declaring y:nat % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.DependentProduct object at 0x2b782a5facf8>) of role type named pl % 0.51/0.70 Using role type % 0.51/0.70 Declaring pl:(nat->(nat->nat)) % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22fcf8>, <kernel.DependentProduct object at 0x2b782a5faf38>) of role type named ts % 0.51/0.70 Using role type % 0.51/0.70 Declaring ts:(nat->(nat->nat)) % 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.DependentProduct object at 0x2b782a5facb0>) of role type named suc % 0.51/0.70 Using role type % 0.51/0.70 Declaring suc:(nat->nat) % 0.51/0.70 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx))) of role axiom named satz28b % 0.51/0.70 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx))) % 0.51/0.70 FOF formula (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) of role conjecture named satz28f % 0.51/0.70 Conjecture to prove = (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))):Prop % 0.51/0.70 We need to prove ['(((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))'] % 0.51/0.70 Parameter nat:Type. % 0.51/0.70 Parameter x:nat. % 0.51/0.70 Parameter y:nat. % 0.51/0.70 Parameter pl:(nat->(nat->nat)). % 0.51/0.70 Parameter ts:(nat->(nat->nat)). % 0.51/0.70 Parameter suc:(nat->nat). % 0.51/0.70 Axiom satz28b:(forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx))). % 0.51/0.70 Trying to prove (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Found eq_ref00:=(eq_ref0 ((ts x) (suc y))):(((eq nat) ((ts x) (suc y))) ((ts x) (suc y))) % 0.51/0.70 Found (eq_ref0 ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y))) % 0.51/0.70 Found ((eq_ref nat) ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y))) % 0.51/0.70 Found ((eq_ref nat) ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y))) % 0.51/0.70 Found (satz28b000 ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Found ((satz28b00 (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Found (((satz28b0 y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Found ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Found ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) % 0.51/0.70 Got proof ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) % 0.51/0.70 Time elapsed = 0.176334s % 0.51/0.70 node=27 cost=-103.000000 depth=7 % 0.51/0.70:::::::::::::::::::::: % 0.51/0.70 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.51/0.70 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.51/0.70 ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) % 0.51/0.70 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------