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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM713^1 : TPTP v9.2.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:57:10 PM UTC 2025

% Result   : Theorem 3.47s 3.67s
% Output   : Proof 3.47s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : NUM713^1 : TPTP v9.2.0. Released v3.7.0.
% 0.07/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Oct  3 07:32:53 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 3.47/3.67  SZS status Theorem for theBenchmark.p
% 3.47/3.67  SZS output start Proof for theBenchmark.p
% 3.47/3.67  Clause #0 (by assumption #[]): Eq (Not (∀ (Xx_0 : nat), Ne x (pl y Xx_0))) True
% 3.47/3.67  Clause #2 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (ts Xx Xy) (ts Xy Xx)) True
% 3.47/3.67  Clause #3 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), Eq (ts Xx (pl Xy Xz)) (pl (ts Xx Xy) (ts Xx Xz))) True
% 3.47/3.67  Clause #4 (by assumption #[]): Eq (Not (Not (∀ (Xx_0 : nat), Ne (ts x z) (pl (ts y z) Xx_0)))) True
% 3.47/3.67  Clause #9 (by clausification #[0]): Eq (∀ (Xx_0 : nat), Ne x (pl y Xx_0)) False
% 3.47/3.67  Clause #10 (by clausification #[9]): ∀ (a : nat), Eq (Not (Ne x (pl y (skS.0 0 a)))) True
% 3.47/3.67  Clause #11 (by clausification #[10]): ∀ (a : nat), Eq (Ne x (pl y (skS.0 0 a))) False
% 3.47/3.67  Clause #12 (by clausification #[11]): ∀ (a : nat), Eq x (pl y (skS.0 0 a))
% 3.47/3.67  Clause #13 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (ts a Xy) (ts Xy a)) True
% 3.47/3.67  Clause #14 (by clausification #[13]): ∀ (a a_1 : nat), Eq (Eq (ts a a_1) (ts a_1 a)) True
% 3.47/3.67  Clause #15 (by clausification #[14]): ∀ (a a_1 : nat), Eq (ts a a_1) (ts a_1 a)
% 3.47/3.67  Clause #16 (by clausification #[4]): Eq (Not (∀ (Xx_0 : nat), Ne (ts x z) (pl (ts y z) Xx_0))) False
% 3.47/3.67  Clause #17 (by clausification #[16]): Eq (∀ (Xx_0 : nat), Ne (ts x z) (pl (ts y z) Xx_0)) True
% 3.47/3.67  Clause #18 (by clausification #[17]): ∀ (a : nat), Eq (Ne (ts x z) (pl (ts y z) a)) True
% 3.47/3.67  Clause #19 (by clausification #[18]): ∀ (a : nat), Ne (ts x z) (pl (ts y z) a)
% 3.47/3.67  Clause #20 (by forward demodulation #[19, 15]): ∀ (a : nat), Ne (ts z x) (pl (ts y z) a)
% 3.47/3.67  Clause #21 (by forward demodulation #[20, 15]): ∀ (a : nat), Ne (ts z x) (pl (ts z y) a)
% 3.47/3.67  Clause #22 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), Eq (ts a (pl Xy Xz)) (pl (ts a Xy) (ts a Xz))) True
% 3.47/3.67  Clause #23 (by clausification #[22]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), Eq (ts a (pl a_1 Xz)) (pl (ts a a_1) (ts a Xz))) True
% 3.47/3.67  Clause #24 (by clausification #[23]): ∀ (a a_1 a_2 : nat), Eq (Eq (ts a (pl a_1 a_2)) (pl (ts a a_1) (ts a a_2))) True
% 3.47/3.67  Clause #25 (by clausification #[24]): ∀ (a a_1 a_2 : nat), Eq (ts a (pl a_1 a_2)) (pl (ts a a_1) (ts a a_2))
% 3.47/3.67  Clause #26 (by superposition #[25, 21]): ∀ (a : nat), Ne (ts z x) (ts z (pl y a))
% 3.47/3.67  Clause #29 (by superposition #[26, 12]): Ne (ts z x) (ts z x)
% 3.47/3.67  Clause #30 (by eliminate resolved literals #[29]): False
% 3.47/3.67  SZS output end Proof for theBenchmark.p
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