%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM721^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n069.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:33 EST 2018 % Result : Theorem 0.43s % Output : Proof 0.43s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM721^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n069.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 13:14:21 CST 2018 % 0.02/0.23 % CPUTime : % 0.02/0.25 Python 2.7.13 % 0.43/0.62 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc098>, <kernel.Type object at 0x2b494f7dc200>) of role type named nat_type % 0.43/0.62 Using role type % 0.43/0.62 Declaring nat:Type % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc2d8>, <kernel.Constant object at 0x2b494f0cacb0>) of role type named x % 0.43/0.62 Using role type % 0.43/0.62 Declaring x:nat % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f0cabd8>, <kernel.Constant object at 0x2b494f7dc2d8>) of role type named y % 0.43/0.62 Using role type % 0.43/0.62 Declaring y:nat % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f0cabd8>, <kernel.Constant object at 0x2b494f7dc0e0>) of role type named z % 0.43/0.62 Using role type % 0.43/0.62 Declaring z:nat % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc248>, <kernel.Constant object at 0x2b494f7e78c0>) of role type named u % 0.43/0.62 Using role type % 0.43/0.62 Declaring u:nat % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc0e0>, <kernel.DependentProduct object at 0x2b494f7e79e0>) of role type named some % 0.43/0.62 Using role type % 0.43/0.62 Declaring some:((nat->Prop)->Prop) % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc248>, <kernel.DependentProduct object at 0x2b494f7e78c0>) of role type named diffprop % 0.43/0.62 Using role type % 0.43/0.62 Declaring diffprop:(nat->(nat->(nat->Prop))) % 0.43/0.62 FOF formula (some (fun (Xv:nat)=> (((diffprop y) x) Xv))) of role axiom named l % 0.43/0.62 A new axiom: (some (fun (Xv:nat)=> (((diffprop y) x) Xv))) % 0.43/0.62 FOF formula (some (fun (Xv:nat)=> (((diffprop u) z) Xv))) of role axiom named k % 0.43/0.62 A new axiom: (some (fun (Xv:nat)=> (((diffprop u) z) Xv))) % 0.43/0.62 FOF formula (<kernel.Constant object at 0x2b494f7dc0e0>, <kernel.DependentProduct object at 0x2b494f7e7710>) of role type named ts % 0.43/0.62 Using role type % 0.43/0.62 Declaring ts:(nat->(nat->nat)) % 0.43/0.62 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat) (Xu:nat), ((some (fun (Xu:nat)=> (((diffprop Xx) Xy) Xu)))->((some (fun (Xu_0:nat)=> (((diffprop Xz) Xu) Xu_0)))->(some (fun (Xu_0:nat)=> (((diffprop ((ts Xx) Xz)) ((ts Xy) Xu)) Xu_0)))))) of role axiom named satz34 % 0.43/0.62 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat) (Xu:nat), ((some (fun (Xu:nat)=> (((diffprop Xx) Xy) Xu)))->((some (fun (Xu_0:nat)=> (((diffprop Xz) Xu) Xu_0)))->(some (fun (Xu_0:nat)=> (((diffprop ((ts Xx) Xz)) ((ts Xy) Xu)) Xu_0)))))) % 0.43/0.62 FOF formula (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) of role conjecture named satz34a % 0.43/0.62 Conjecture to prove = (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))):Prop % 0.43/0.62 We need to prove ['(some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv)))'] % 0.43/0.62 Parameter nat:Type. % 0.43/0.62 Parameter x:nat. % 0.43/0.62 Parameter y:nat. % 0.43/0.62 Parameter z:nat. % 0.43/0.62 Parameter u:nat. % 0.43/0.62 Parameter some:((nat->Prop)->Prop). % 0.43/0.62 Parameter diffprop:(nat->(nat->(nat->Prop))). % 0.43/0.62 Axiom l:(some (fun (Xv:nat)=> (((diffprop y) x) Xv))). % 0.43/0.62 Axiom k:(some (fun (Xv:nat)=> (((diffprop u) z) Xv))). % 0.43/0.62 Parameter ts:(nat->(nat->nat)). % 0.43/0.62 Axiom satz34:(forall (Xx:nat) (Xy:nat) (Xz:nat) (Xu:nat), ((some (fun (Xu:nat)=> (((diffprop Xx) Xy) Xu)))->((some (fun (Xu_0:nat)=> (((diffprop Xz) Xu) Xu_0)))->(some (fun (Xu_0:nat)=> (((diffprop ((ts Xx) Xz)) ((ts Xy) Xu)) Xu_0)))))). % 0.43/0.62 Trying to prove (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found k:(some (fun (Xv:nat)=> (((diffprop u) z) Xv))) % 0.43/0.62 Found k as proof of (some (fun (Xu_0:nat)=> (((diffprop u) z) Xu_0))) % 0.43/0.62 Found (satz3400000 k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found ((satz340000 z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found (((satz34000 u) z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found ((((fun (Xz:nat) (Xu:nat)=> (((satz3400 Xz) Xu) l)) u) z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found ((((fun (Xz:nat) (Xu:nat)=> ((((satz340 x) Xz) Xu) l)) u) z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found ((((fun (Xz:nat) (Xu:nat)=> (((((satz34 y) x) Xz) Xu) l)) u) z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.62 Found ((((fun (Xz:nat) (Xu:nat)=> (((((satz34 y) x) Xz) Xu) l)) u) z) k) as proof of (some (fun (Xv:nat)=> (((diffprop ((ts y) u)) ((ts x) z)) Xv))) % 0.43/0.63 Got proof ((((fun (Xz:nat) (Xu:nat)=> (((((satz34 y) x) Xz) Xu) l)) u) z) k) % 0.43/0.63 Time elapsed = 0.090728s % 0.43/0.63 node=18 cost=101.000000 depth=7 % 0.43/0.63:::::::::::::::::::::: % 0.43/0.63 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.43/0.63 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.43/0.63 ((((fun (Xz:nat) (Xu:nat)=> (((((satz34 y) x) Xz) Xu) l)) u) z) k) % 0.43/0.63 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------