%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM726^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n066.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:33 EST 2018 % Result : Theorem 0.08s % Output : Proof 0.08s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM726^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n066.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 13:15:50 CST 2018 % 0.02/0.23 % CPUTime : % 0.08/0.25 Python 2.7.13 % 0.08/0.52 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.Type object at 0x2b627ca5f320>) of role type named frac_type % 0.08/0.52 Using role type % 0.08/0.52 Declaring frac:Type % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f4d0>, <kernel.Constant object at 0x2b627ca5fd40>) of role type named x % 0.08/0.52 Using role type % 0.08/0.52 Declaring x:frac % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627cb437e8>, <kernel.Constant object at 0x2b627ca5fd40>) of role type named y % 0.08/0.52 Using role type % 0.08/0.52 Declaring y:frac % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.Type object at 0x2b627ca5b440>) of role type named nat_type % 0.08/0.52 Using role type % 0.08/0.52 Declaring nat:Type % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f050>, <kernel.DependentProduct object at 0x2b627ca5f320>) of role type named ts % 0.08/0.52 Using role type % 0.08/0.52 Declaring ts:(nat->(nat->nat)) % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5fd40>, <kernel.DependentProduct object at 0x2b627ca5ba70>) of role type named num % 0.08/0.52 Using role type % 0.08/0.52 Declaring num:(frac->nat) % 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.DependentProduct object at 0x2b627ca5b488>) of role type named den % 0.08/0.52 Using role type % 0.08/0.52 Declaring den:(frac->nat) % 0.08/0.52 FOF formula (((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) of role axiom named e % 0.08/0.52 A new axiom: (((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) % 0.08/0.52 FOF formula (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))) of role conjecture named satz38 % 0.08/0.52 Conjecture to prove = (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))):Prop % 0.08/0.52 Parameter nat_DUMMY:nat. % 0.08/0.52 We need to prove ['(((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y)))'] % 0.08/0.52 Parameter frac:Type. % 0.08/0.52 Parameter x:frac. % 0.08/0.52 Parameter y:frac. % 0.08/0.52 Parameter nat:Type. % 0.08/0.52 Parameter ts:(nat->(nat->nat)). % 0.08/0.52 Parameter num:(frac->nat). % 0.08/0.52 Parameter den:(frac->nat). % 0.08/0.52 Axiom e:(((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))). % 0.08/0.52 Trying to prove (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))) % 0.08/0.52 Found e__eq_sym:=((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e):(((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))) % 0.08/0.52 Found e__eq_sym as proof of (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))) % 0.08/0.52 Got proof ((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e) % 0.08/0.52 Time elapsed = 0.003283s % 0.08/0.52 node=0 cost=0.000000 depth=0 % 0.08/0.52:::::::::::::::::::::: % 0.08/0.52 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.08/0.52 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.08/0.52 ((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e) % 0.08/0.52 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------