%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM728^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n015.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:10 PM UTC 2025 % Result : Theorem 3.70s 3.88s % Output : Proof 3.70s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.12/0.12 % Problem : NUM728^1 : TPTP v9.2.0. Released v3.7.0. % 0.12/0.13 % Command : duper %s % 0.13/0.34 % Computer : n015.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 07:25:38 EDT 2025 % 0.13/0.34 % CPUTime : % 3.70/3.88 SZS status Theorem for theBenchmark.p % 3.70/3.88 SZS output start Proof for theBenchmark.p % 3.70/3.88 Clause #0 (by assumption #[]): Eq (∀ (Xx Xy : frac), eq Xx Xy → eq Xy Xx) True % 3.70/3.88 Clause #1 (by assumption #[]): Eq (∀ (Xx : frac) (Xn : nat), eq Xx (fr (ts (c1x Xx) Xn) (ts (c2x Xx) Xn))) True % 3.70/3.88 Clause #2 (by assumption #[]): Eq (Not (eq (fr (ts (c1x x) n) (ts (c2x x) n)) x)) True % 3.70/3.88 Clause #3 (by clausification #[0]): ∀ (a : frac), Eq (∀ (Xy : frac), eq a Xy → eq Xy a) True % 3.70/3.88 Clause #4 (by clausification #[3]): ∀ (a a_1 : frac), Eq (eq a a_1 → eq a_1 a) True % 3.70/3.88 Clause #5 (by clausification #[4]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Eq (eq a_1 a) True) % 3.70/3.88 Clause #6 (by clausification #[2]): Eq (eq (fr (ts (c1x x) n) (ts (c2x x) n)) x) False % 3.70/3.88 Clause #7 (by clausification #[1]): ∀ (a : frac), Eq (∀ (Xn : nat), eq a (fr (ts (c1x a) Xn) (ts (c2x a) Xn))) True % 3.70/3.88 Clause #8 (by clausification #[7]): ∀ (a : frac) (a_1 : nat), Eq (eq a (fr (ts (c1x a) a_1) (ts (c2x a) a_1))) True % 3.70/3.88 Clause #9 (by superposition #[8, 5]): ∀ (a : frac) (a_1 : nat), Or (Eq True False) (Eq (eq (fr (ts (c1x a) a_1) (ts (c2x a) a_1)) a) True) % 3.70/3.88 Clause #10 (by clausification #[9]): ∀ (a : frac) (a_1 : nat), Eq (eq (fr (ts (c1x a) a_1) (ts (c2x a) a_1)) a) True % 3.70/3.88 Clause #11 (by superposition #[10, 6]): Eq True False % 3.70/3.88 Clause #13 (by clausification #[11]): False % 3.70/3.88 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------