%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM729^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n021.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:11 PM UTC 2025 % Result : Theorem 3.65s 3.80s % Output : Proof 3.65s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.12 % Problem : NUM729^1 : TPTP v9.2.0. Released v3.7.0. % 0.11/0.13 % Command : duper %s % 0.13/0.34 % Computer : n021.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 07:53:23 EDT 2025 % 0.13/0.34 % CPUTime : % 3.65/3.80 SZS status Theorem for theBenchmark.p % 3.65/3.80 SZS output start Proof for theBenchmark.p % 3.65/3.80 Clause #0 (by assumption #[]): Eq (∀ (Xx Xy : frac), eq Xx Xy → eq Xy Xx) True % 3.65/3.80 Clause #1 (by assumption #[]): Eq (∀ (Xx1 Xx2 Xn : nat), eq (fr Xx1 Xx2) (fr (ts Xx1 Xn) (ts Xx2 Xn))) True % 3.65/3.80 Clause #2 (by assumption #[]): Eq (Not (eq (fr (ts x1 n) (ts x2 n)) (fr x1 x2))) True % 3.65/3.80 Clause #3 (by clausification #[0]): ∀ (a : frac), Eq (∀ (Xy : frac), eq a Xy → eq Xy a) True % 3.65/3.80 Clause #4 (by clausification #[3]): ∀ (a a_1 : frac), Eq (eq a a_1 → eq a_1 a) True % 3.65/3.80 Clause #5 (by clausification #[4]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Eq (eq a_1 a) True) % 3.65/3.80 Clause #6 (by clausification #[2]): Eq (eq (fr (ts x1 n) (ts x2 n)) (fr x1 x2)) False % 3.65/3.80 Clause #7 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xx2 Xn : nat), eq (fr a Xx2) (fr (ts a Xn) (ts Xx2 Xn))) True % 3.65/3.80 Clause #8 (by clausification #[7]): ∀ (a a_1 : nat), Eq (∀ (Xn : nat), eq (fr a a_1) (fr (ts a Xn) (ts a_1 Xn))) True % 3.65/3.80 Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : nat), Eq (eq (fr a a_1) (fr (ts a a_2) (ts a_1 a_2))) True % 3.65/3.80 Clause #10 (by superposition #[9, 5]): ∀ (a a_1 a_2 : nat), Or (Eq True False) (Eq (eq (fr (ts a a_1) (ts a_2 a_1)) (fr a a_2)) True) % 3.65/3.80 Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 : nat), Eq (eq (fr (ts a a_1) (ts a_2 a_1)) (fr a a_2)) True % 3.65/3.80 Clause #12 (by superposition #[11, 6]): Eq True False % 3.65/3.80 Clause #14 (by clausification #[12]): False % 3.65/3.80 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------