%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM736^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n013.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:11 PM UTC 2025 % Result : Theorem 3.52s 3.71s % Output : Proof 3.52s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : NUM736^1 : TPTP v9.2.0. Released v3.7.0. % 0.07/0.13 % Command : duper %s % 0.13/0.34 % Computer : n013.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.35 % WCLimit : 300 % 0.13/0.35 % DateTime : Fri Oct 3 07:38:08 EDT 2025 % 0.13/0.35 % CPUTime : % 3.52/3.71 SZS status Theorem for theBenchmark.p % 3.52/3.71 SZS output start Proof for theBenchmark.p % 3.52/3.71 Clause #0 (by assumption #[]): Eq (more (ts (num x) (den y)) (ts (num y) (den x))) True % 3.52/3.71 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy : nat), more Xx Xy → less Xy Xx) True % 3.52/3.71 Clause #2 (by assumption #[]): Eq (Not (less (ts (num y) (den x)) (ts (num x) (den y)))) True % 3.52/3.71 Clause #3 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy : nat), more a Xy → less Xy a) True % 3.52/3.71 Clause #4 (by clausification #[3]): ∀ (a a_1 : nat), Eq (more a a_1 → less a_1 a) True % 3.52/3.71 Clause #5 (by clausification #[4]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Eq (less a_1 a) True) % 3.52/3.71 Clause #6 (by superposition #[0, 5]): Or (Eq (less (ts (num y) (den x)) (ts (num x) (den y))) True) (Eq False True) % 3.52/3.71 Clause #7 (by clausification #[2]): Eq (less (ts (num y) (den x)) (ts (num x) (den y))) False % 3.52/3.71 Clause #8 (by clausification #[6]): Eq (less (ts (num y) (den x)) (ts (num x) (den y))) True % 3.52/3.71 Clause #9 (by superposition #[8, 7]): Eq True False % 3.52/3.71 Clause #10 (by clausification #[9]): False % 3.52/3.71 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------