%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM750^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n024.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:14 PM UTC 2025 % Result : Theorem 3.35s 3.56s % Output : Proof 3.35s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.12 % Problem : NUM750^1 : TPTP v9.2.0. Released v3.7.0. % 0.11/0.14 % Command : duper %s % 0.14/0.35 % Computer : n024.cluster.edu % 0.14/0.35 % Model : x86_64 x86_64 % 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.35 % Memory : 8042.1875MB % 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.35 % CPULimit : 300 % 0.14/0.35 % WCLimit : 300 % 0.14/0.35 % DateTime : Fri Oct 3 08:26:38 EDT 2025 % 0.14/0.35 % CPUTime : % 3.35/3.56 SZS status Theorem for theBenchmark.p % 3.35/3.56 SZS output start Proof for theBenchmark.p % 3.35/3.56 Clause #0 (by assumption #[]): Eq (eq x y) True % 3.35/3.56 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : frac), eq Xx Xy → eq Xz Xu → eq (pf Xx Xz) (pf Xy Xu)) True % 3.35/3.56 Clause #2 (by assumption #[]): Eq (∀ (Xx : frac), eq Xx Xx) True % 3.35/3.56 Clause #3 (by assumption #[]): Eq (Not (eq (pf x z) (pf y z))) True % 3.35/3.56 Clause #4 (by clausification #[2]): ∀ (a : frac), Eq (eq a a) True % 3.35/3.56 Clause #5 (by clausification #[3]): Eq (eq (pf x z) (pf y z)) False % 3.35/3.56 Clause #6 (by clausification #[1]): ∀ (a : frac), Eq (∀ (Xy Xz Xu : frac), eq a Xy → eq Xz Xu → eq (pf a Xz) (pf Xy Xu)) True % 3.35/3.56 Clause #7 (by clausification #[6]): ∀ (a a_1 : frac), Eq (∀ (Xz Xu : frac), eq a a_1 → eq Xz Xu → eq (pf a Xz) (pf a_1 Xu)) True % 3.35/3.56 Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : frac), Eq (∀ (Xu : frac), eq a a_1 → eq a_2 Xu → eq (pf a a_2) (pf a_1 Xu)) True % 3.35/3.56 Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 a_3 : frac), Eq (eq a a_1 → eq a_2 a_3 → eq (pf a a_2) (pf a_1 a_3)) True % 3.35/3.56 Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 a_3 : frac), Or (Eq (eq a a_1) False) (Eq (eq a_2 a_3 → eq (pf a a_2) (pf a_1 a_3)) True) % 3.35/3.56 Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 a_3 : frac), Or (Eq (eq a a_1) False) (Or (Eq (eq a_2 a_3) False) (Eq (eq (pf a a_2) (pf a_1 a_3)) True)) % 3.35/3.56 Clause #12 (by superposition #[11, 0]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Or (Eq (eq (pf x a) (pf y a_1)) True) (Eq False True)) % 3.35/3.56 Clause #17 (by clausification #[12]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Eq (eq (pf x a) (pf y a_1)) True) % 3.35/3.56 Clause #19 (by superposition #[17, 4]): ∀ (a : frac), Or (Eq (eq (pf x a) (pf y a)) True) (Eq False True) % 3.35/3.56 Clause #20 (by clausification #[19]): ∀ (a : frac), Eq (eq (pf x a) (pf y a)) True % 3.35/3.56 Clause #21 (by superposition #[20, 5]): Eq True False % 3.35/3.56 Clause #25 (by clausification #[21]): False % 3.35/3.56 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------