%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM752^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n172.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:38 EST 2018 % Result : Theorem 0.36s % Output : Proof 0.36s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.04 % Problem : NUM752^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.03/0.24 % Computer : n172.star.cs.uiowa.edu % 0.03/0.24 % Model : x86_64 x86_64 % 0.03/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.24 % Memory : 32218.625MB % 0.03/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.24 % CPULimit : 300 % 0.03/0.24 % DateTime : Fri Jan 5 13:41:34 CST 2018 % 0.03/0.24 % CPUTime : % 0.03/0.27 Python 2.7.13 % 0.36/0.86 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b4a878>, <kernel.Type object at 0x2b4748b4a4d0>) of role type named frac_type % 0.36/0.86 Using role type % 0.36/0.86 Declaring frac:Type % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b3f050>, <kernel.Constant object at 0x2b4748b4ab48>) of role type named x % 0.36/0.86 Using role type % 0.36/0.86 Declaring x:frac % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b4ae18>, <kernel.Constant object at 0x2b4748b4ab48>) of role type named y % 0.36/0.86 Using role type % 0.36/0.86 Declaring y:frac % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b4a878>, <kernel.Constant object at 0x2b4748b4ab48>) of role type named z % 0.36/0.86 Using role type % 0.36/0.86 Declaring z:frac % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b4a3f8>, <kernel.DependentProduct object at 0x2b4748b4a5f0>) of role type named eq % 0.36/0.86 Using role type % 0.36/0.86 Declaring _TPTP_eq:(frac->(frac->Prop)) % 0.36/0.86 FOF formula ((_TPTP_eq x) y) of role axiom named e % 0.36/0.86 A new axiom: ((_TPTP_eq x) y) % 0.36/0.86 FOF formula (<kernel.Constant object at 0x2b4748b4ab48>, <kernel.DependentProduct object at 0x2b4748b4a878>) of role type named pf % 0.36/0.86 Using role type % 0.36/0.86 Declaring pf:(frac->(frac->frac)) % 0.36/0.86 FOF formula (forall (Xx:frac) (Xy:frac) (Xz:frac) (Xu:frac), (((_TPTP_eq Xx) Xy)->(((_TPTP_eq Xz) Xu)->((_TPTP_eq ((pf Xx) Xz)) ((pf Xy) Xu))))) of role axiom named satz56 % 0.36/0.86 A new axiom: (forall (Xx:frac) (Xy:frac) (Xz:frac) (Xu:frac), (((_TPTP_eq Xx) Xy)->(((_TPTP_eq Xz) Xu)->((_TPTP_eq ((pf Xx) Xz)) ((pf Xy) Xu))))) % 0.36/0.86 FOF formula (forall (Xx:frac), ((_TPTP_eq Xx) Xx)) of role axiom named satz37 % 0.36/0.86 A new axiom: (forall (Xx:frac), ((_TPTP_eq Xx) Xx)) % 0.36/0.86 FOF formula ((_TPTP_eq ((pf z) x)) ((pf z) y)) of role conjecture named satz62e % 0.36/0.86 Conjecture to prove = ((_TPTP_eq ((pf z) x)) ((pf z) y)):Prop % 0.36/0.86 We need to prove ['((_TPTP_eq ((pf z) x)) ((pf z) y))'] % 0.36/0.86 Parameter frac:Type. % 0.36/0.86 Parameter x:frac. % 0.36/0.86 Parameter y:frac. % 0.36/0.86 Parameter z:frac. % 0.36/0.86 Parameter _TPTP_eq:(frac->(frac->Prop)). % 0.36/0.86 Axiom e:((_TPTP_eq x) y). % 0.36/0.86 Parameter pf:(frac->(frac->frac)). % 0.36/0.86 Axiom satz56:(forall (Xx:frac) (Xy:frac) (Xz:frac) (Xu:frac), (((_TPTP_eq Xx) Xy)->(((_TPTP_eq Xz) Xu)->((_TPTP_eq ((pf Xx) Xz)) ((pf Xy) Xu))))). % 0.36/0.86 Axiom satz37:(forall (Xx:frac), ((_TPTP_eq Xx) Xx)). % 0.36/0.86 Trying to prove ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found satz370:=(satz37 z):((_TPTP_eq z) z) % 0.36/0.86 Found (satz37 z) as proof of ((_TPTP_eq z) z) % 0.36/0.86 Found (satz37 z) as proof of ((_TPTP_eq z) z) % 0.36/0.86 Found (satz5600000 (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> ((satz560000 x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> (((satz56000 y) x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> ((((satz5600 x) y) x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> (((((satz560 z) x) y) x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> ((((((satz56 z) z) x) y) x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Found ((fun (x0:((_TPTP_eq z) z))=> ((((((satz56 z) z) x) y) x0) e)) (satz37 z)) as proof of ((_TPTP_eq ((pf z) x)) ((pf z) y)) % 0.36/0.86 Got proof ((fun (x0:((_TPTP_eq z) z))=> ((((((satz56 z) z) x) y) x0) e)) (satz37 z)) % 0.36/0.86 Time elapsed = 0.045374s % 0.36/0.86 node=9 cost=9.000000 depth=8 % 0.36/0.86:::::::::::::::::::::: % 0.36/0.86 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.36/0.86 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.36/0.86 ((fun (x0:((_TPTP_eq z) z))=> ((((((satz56 z) z) x) y) x0) e)) (satz37 z)) % 0.36/0.86 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------