%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM781^2 : TPTP v9.2.0. Released v5.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n008.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:18 PM UTC 2025 % Result : Theorem 3.43s 3.67s % Output : Proof 3.43s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.08/0.12 % Problem : NUM781^2 : TPTP v9.2.0. Released v5.1.0. % 0.08/0.14 % Command : duper %s % 0.14/0.35 % Computer : n008.cluster.edu % 0.14/0.35 % Model : x86_64 x86_64 % 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.35 % Memory : 8042.1875MB % 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.35 % CPULimit : 300 % 0.14/0.35 % WCLimit : 300 % 0.14/0.35 % DateTime : Fri Oct 3 08:09:23 EDT 2025 % 0.14/0.35 % CPUTime : % 3.43/3.67 SZS status Theorem for theBenchmark.p % 3.43/3.67 SZS output start Proof for theBenchmark.p % 3.43/3.67 Clause #0 (by assumption #[]): Eq (Not (∀ (A B : a), Eq A B → Eq B A)) True % 3.43/3.67 Clause #1 (by clausification #[0]): Eq (∀ (A B : a), Eq A B → Eq B A) False % 3.43/3.67 Clause #2 (by clausification #[1]): ∀ (a_1 : a), Eq (Not (∀ (B : a), Eq (skS.0 0 a_1) B → Eq B (skS.0 0 a_1))) True % 3.43/3.67 Clause #3 (by clausification #[2]): ∀ (a_1 : a), Eq (∀ (B : a), Eq (skS.0 0 a_1) B → Eq B (skS.0 0 a_1)) False % 3.43/3.67 Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : a), Eq (Not (Eq (skS.0 0 a_1) (skS.0 1 a_1 a_2) → Eq (skS.0 1 a_1 a_2) (skS.0 0 a_1))) True % 3.43/3.67 Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : a), Eq (Eq (skS.0 0 a_1) (skS.0 1 a_1 a_2) → Eq (skS.0 1 a_1 a_2) (skS.0 0 a_1)) False % 3.43/3.67 Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : a), Eq (Eq (skS.0 0 a_1) (skS.0 1 a_1 a_2)) True % 3.43/3.67 Clause #7 (by clausification #[5]): ∀ (a_1 a_2 : a), Eq (Eq (skS.0 1 a_1 a_2) (skS.0 0 a_1)) False % 3.43/3.67 Clause #8 (by clausification #[6]): ∀ (a_1 a_2 : a), Eq (skS.0 0 a_1) (skS.0 1 a_1 a_2) % 3.43/3.67 Clause #9 (by clausification #[7]): ∀ (a_1 a_2 : a), Ne (skS.0 1 a_1 a_2) (skS.0 0 a_1) % 3.43/3.67 Clause #10 (by forward demodulation #[9, 8]): ∀ (a_1 : a), Ne (skS.0 0 a_1) (skS.0 0 a_1) % 3.43/3.67 Clause #11 (by eliminate resolved literals #[10]): False % 3.43/3.67 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------