%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM781^2 : TPTP v7.0.0. Released v5.1.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n164.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:42 EST 2018 % Result : Theorem 0.37s % Output : Proof 0.37s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM781^2 : TPTP v7.0.0. Released v5.1.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.03/0.23 % Computer : n164.star.cs.uiowa.edu % 0.03/0.23 % Model : x86_64 x86_64 % 0.03/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.23 % Memory : 32218.625MB % 0.03/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.23 % CPULimit : 300 % 0.03/0.23 % DateTime : Fri Jan 5 14:08:34 CST 2018 % 0.06/0.23 % CPUTime : % 0.07/0.25 Python 2.7.13 % 0.37/0.56 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.37/0.56 FOF formula (<kernel.Constant object at 0x2acd39e00fc8>, <kernel.Type object at 0x2acd39e04cb0>) of role type named a_type % 0.37/0.56 Using role type % 0.37/0.56 Declaring a:Type % 0.37/0.56 FOF formula (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))) of role conjecture named cES_eq_ % 0.37/0.56 Conjecture to prove = (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))):Prop % 0.37/0.56 Parameter a_DUMMY:a. % 0.37/0.56 We need to prove ['(forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A)))'] % 0.37/0.56 Parameter a:Type. % 0.37/0.56 Trying to prove (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))) % 0.37/0.56 Found eq_sym0:=(eq_sym a):(forall (a0:a) (b:a), ((((eq a) a0) b)->(((eq a) b) a0))) % 0.37/0.56 Found (eq_sym a) as proof of (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))) % 0.37/0.56 Found (eq_sym a) as proof of (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))) % 0.37/0.56 Got proof (eq_sym a) % 0.37/0.56 Time elapsed = 0.050991s % 0.37/0.56 node=2 cost=-97.000000 depth=1 % 0.37/0.56:::::::::::::::::::::: % 0.37/0.56 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.37/0.56 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.37/0.56 (eq_sym a) % 0.37/0.56 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------