%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM781^3 : TPTP v7.0.0. Released v5.1.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n059.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:43 EST 2018 % Result : Theorem 0.35s % Output : Proof 0.35s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM781^3 : TPTP v7.0.0. Released v5.1.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n059.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 14:08:18 CST 2018 % 0.06/0.24 % CPUTime : % 0.06/0.25 Python 2.7.13 % 0.35/0.58 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.35/0.58 FOF formula (<kernel.Constant object at 0x2ae9f45d84d0>, <kernel.Constant object at 0x2ae9f45d8488>) of role type named cY % 0.35/0.58 Using role type % 0.35/0.58 Declaring cY:fofType % 0.35/0.58 FOF formula (<kernel.Constant object at 0x2ae9f45cc128>, <kernel.Single object at 0x2ae9f45d8320>) of role type named cX % 0.35/0.58 Using role type % 0.35/0.58 Declaring cX:fofType % 0.35/0.58 FOF formula ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) of role conjecture named cTHM76 % 0.35/0.58 Conjecture to prove = ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)):Prop % 0.35/0.58 We need to prove ['((((eq fofType) cY) cX)->(((eq fofType) cX) cY))'] % 0.35/0.58 Parameter fofType:Type. % 0.35/0.58 Parameter cY:fofType. % 0.35/0.58 Parameter cX:fofType. % 0.35/0.58 Trying to prove ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Found eq_sym000:=(eq_sym00 cX):((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Found (eq_sym00 cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Found ((eq_sym0 cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % 0.35/0.58 Got proof (((eq_sym fofType) cY) cX) % 0.35/0.58 Time elapsed = 0.067406s % 0.35/0.58 node=4 cost=-290.000000 depth=3 % 0.35/0.58:::::::::::::::::::::: % 0.35/0.58 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.35/0.58 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.35/0.58 (((eq_sym fofType) cY) cX) % 0.35/0.58 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------