%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM810^5 : TPTP v7.0.0. Bugfixed v5.2.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n059.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:49 EST 2018 % Result : Unknown 0.90s % Output : None % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----No solution output by system %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.04 % Problem : NUM810^5 : TPTP v7.0.0. Bugfixed v5.2.0. % 0.00/0.05 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.02/0.24 % Computer : n059.star.cs.uiowa.edu % 0.02/0.24 % Model : x86_64 x86_64 % 0.02/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.24 % Memory : 32218.625MB % 0.02/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.24 % CPULimit : 300 % 0.02/0.24 % DateTime : Fri Jan 5 14:41:20 CST 2018 % 0.02/0.24 % CPUTime : % 0.02/0.26 Python 2.7.13 % 0.90/1.11 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.90/1.11 FOF formula (<kernel.Constant object at 0x2acd2548e1b8>, <kernel.Constant object at 0x2acd2548e758>) of role type named c0_type % 0.90/1.11 Using role type % 0.90/1.11 Declaring c0:fofType % 0.90/1.11 FOF formula (<kernel.Constant object at 0x2acd2548e2d8>, <kernel.DependentProduct object at 0x2acd25487488>) of role type named cDOUBLE_type % 0.90/1.11 Using role type % 0.90/1.11 Declaring cDOUBLE:(fofType->(fofType->Prop)) % 0.90/1.11 FOF formula (<kernel.Constant object at 0x2acd2556f5f0>, <kernel.DependentProduct object at 0x2acd25487050>) of role type named cS_type % 0.90/1.11 Using role type % 0.90/1.11 Declaring cS:(fofType->fofType) % 0.90/1.11 FOF formula (<kernel.Constant object at 0x2acd2548e368>, <kernel.Sort object at 0x2acd258daef0>) of role type named cIND_type % 0.90/1.11 Using role type % 0.90/1.11 Declaring cIND:Prop % 0.90/1.11 FOF formula (((eq Prop) cIND) (forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx))))) of role definition named cIND_def % 0.90/1.11 A new definition: (((eq Prop) cIND) (forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx))))) % 0.90/1.11 Defined: cIND:=(forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx)))) % 0.90/1.11 FOF formula (((and ((and cIND) ((cDOUBLE c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((cDOUBLE Xx) Xy)->((cDOUBLE (cS Xx)) (cS (cS Xy))))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((cDOUBLE Xx) Xy))))) of role conjecture named cTHM140 % 0.90/1.11 Conjecture to prove = (((and ((and cIND) ((cDOUBLE c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((cDOUBLE Xx) Xy)->((cDOUBLE (cS Xx)) (cS (cS Xy))))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((cDOUBLE Xx) Xy))))):Prop % 0.90/1.11 We need to prove ['(((and ((and cIND) ((cDOUBLE c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((cDOUBLE Xx) Xy)->((cDOUBLE (cS Xx)) (cS (cS Xy))))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((cDOUBLE Xx) Xy)))))'] % 0.90/1.11 Parameter fofType:Type. % 0.90/1.11 Parameter c0:fofType. % 0.90/1.11 Parameter cDOUBLE:(fofType->(fofType->Prop)). % 0.90/1.11 Parameter cS:(fofType->fofType). % 0.90/1.11 Definition cIND:=(forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx)))):Prop. % 0.90/1.11 Trying to prove (((and ((and cIND) ((cDOUBLE c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((cDOUBLE Xx) Xy)->((cDOUBLE (cS Xx)) (cS (cS Xy))))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((cDOUBLE Xx) Xy))))) % 0.90/1.11 % SZS status GaveUp for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------