%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUM838+2 : TPTP v8.1.0. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:22:32 EDT 2022
% Result : Theorem 0.12s 0.40s
% Output : Refutation 0.12s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : NUM838+2 : TPTP v8.1.0. Released v4.1.0.
% 0.11/0.12 % Command : sos-script %s
% 0.12/0.33 % Computer : n016.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Wed Jul 6 06:21:19 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.35 ----- Otter 3.2, August 2001 -----
% 0.12/0.35 The process was started by sandbox on n016.cluster.edu,
% 0.12/0.35 Wed Jul 6 06:21:19 2022
% 0.12/0.35 The command was "./sos". The process ID is 27317.
% 0.12/0.35
% 0.12/0.35 set(prolog_style_variables).
% 0.12/0.35 set(auto).
% 0.12/0.35 dependent: set(auto1).
% 0.12/0.35 dependent: set(process_input).
% 0.12/0.35 dependent: clear(print_kept).
% 0.12/0.35 dependent: clear(print_new_demod).
% 0.12/0.35 dependent: clear(print_back_demod).
% 0.12/0.35 dependent: clear(print_back_sub).
% 0.12/0.35 dependent: set(control_memory).
% 0.12/0.35 dependent: assign(max_mem, 12000).
% 0.12/0.35 dependent: assign(pick_given_ratio, 4).
% 0.12/0.35 dependent: assign(stats_level, 1).
% 0.12/0.35 dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35 dependent: assign(sos_limit, 5000).
% 0.12/0.35 dependent: assign(max_weight, 60).
% 0.12/0.35 clear(print_given).
% 0.12/0.35
% 0.12/0.35 formula_list(usable).
% 0.12/0.35
% 0.12/0.35 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 0.12/0.35
% 0.12/0.35 This ia a non-Horn set with equality. The strategy will be
% 0.12/0.35 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35 unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35 clauses in usable.
% 0.12/0.35
% 0.12/0.35 dependent: set(knuth_bendix).
% 0.12/0.35 dependent: set(para_from).
% 0.12/0.35 dependent: set(para_into).
% 0.12/0.35 dependent: clear(para_from_right).
% 0.12/0.35 dependent: clear(para_into_right).
% 0.12/0.35 dependent: set(para_from_vars).
% 0.12/0.35 dependent: set(eq_units_both_ways).
% 0.12/0.35 dependent: set(dynamic_demod_all).
% 0.12/0.35 dependent: set(dynamic_demod).
% 0.12/0.35 dependent: set(order_eq).
% 0.12/0.35 dependent: set(back_demod).
% 0.12/0.35 dependent: set(lrpo).
% 0.12/0.35 dependent: set(hyper_res).
% 0.12/0.35 dependent: set(unit_deletion).
% 0.12/0.35 dependent: set(factor).
% 0.12/0.35
% 0.12/0.35 ------------> process usable:
% 0.12/0.35 Following clause subsumed by 4 during input processing: 0 [] {-} -less(A,B)|greater(B,A).
% 0.12/0.35
% 0.12/0.35 ------------> process sos:
% 0.12/0.35 Following clause subsumed by 35 during input processing: 0 [copy,35,flip.1] {-} vplus(A,B)=vplus(B,A).
% 0.12/0.35 35 back subsumes 7.
% 0.12/0.35 Following clause subsumed by 46 during input processing: 0 [copy,46,flip.1] {-} A=A.
% 0.12/0.35 Following clause subsumed by 50 during input processing: 0 [copy,49,flip.1] {-} vplus(A,vplus(B,v1))=vplus(A,vplus(v1,B)).
% 0.12/0.35 Following clause subsumed by 49 during input processing: 0 [copy,50,flip.1] {-} vplus(A,vplus(v1,B))=vplus(A,vplus(B,v1)).
% 0.12/0.35
% 0.12/0.35 ======= end of input processing =======
% 0.12/0.40
% 0.12/0.40 Model 1 (0.00 seconds, 0 Inserts)
% 0.12/0.40
% 0.12/0.40 Stopped by limit on number of solutions
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40 -------------- Softie stats --------------
% 0.12/0.40
% 0.12/0.40 UPDATE_STOP: 300
% 0.12/0.40 SFINDER_TIME_LIMIT: 2
% 0.12/0.40 SHORT_CLAUSE_CUTOFF: 4
% 0.12/0.40 number of clauses in intial UL: 20
% 0.12/0.40 number of clauses initially in problem: 34
% 0.12/0.40 percentage of clauses intially in UL: 58
% 0.12/0.40 percentage of distinct symbols occuring in initial UL: 73
% 0.12/0.40 percent of all initial clauses that are short: 100
% 0.12/0.40 absolute distinct symbol count: 15
% 0.12/0.40 distinct predicate count: 4
% 0.12/0.40 distinct function count: 7
% 0.12/0.40 distinct constant count: 4
% 0.12/0.40
% 0.12/0.40 ---------- no more Softie stats ----------
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40 =========== start of search ===========
% 0.12/0.40
% 0.12/0.40 -------- PROOF --------
% 0.12/0.40 % SZS status Theorem
% 0.12/0.40 % SZS output start Refutation
% 0.12/0.40
% 0.12/0.40 ----> UNIT CONFLICT at 0.01 sec ----> 57 [binary,56.1,1.1] {-} $F.
% 0.12/0.40
% 0.12/0.40 Length of proof is 1. Level of proof is 1.
% 0.12/0.40
% 0.12/0.40 ---------------- PROOF ----------------
% 0.12/0.40 % SZS status Theorem
% 0.12/0.40 % SZS output start Refutation
% 0.12/0.40
% 0.12/0.40 1 [] {+} -greater(vplus(vd301,vd303),vplus(vd302,vd303)).
% 0.12/0.40 6 [] {+} -greater(A,B)|greater(vplus(A,C),vplus(B,C)).
% 0.12/0.40 30 [] {-} greater(vd301,vd302).
% 0.12/0.40 56 [hyper,30,6] {-} greater(vplus(vd301,A),vplus(vd302,A)).
% 0.12/0.40 57 [binary,56.1,1.1] {-} $F.
% 0.12/0.40
% 0.12/0.40 % SZS output end Refutation
% 0.12/0.40 ------------ end of proof -------------
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40 Search stopped by max_proofs option.
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40 Search stopped by max_proofs option.
% 0.12/0.40
% 0.12/0.40 ============ end of search ============
% 0.12/0.40
% 0.12/0.40 ----------- soft-scott stats ----------
% 0.12/0.40
% 0.12/0.40 true clauses given 0 (0.0%)
% 0.12/0.40 false clauses given 1
% 0.12/0.40
% 0.12/0.40 FALSE TRUE
% 0.12/0.40 3 0 1
% 0.12/0.40 5 0 1
% 0.12/0.40 6 1 0
% 0.12/0.40 7 1 0
% 0.12/0.40 9 0 1
% 0.12/0.40 11 1 2
% 0.12/0.40 14 1 0
% 0.12/0.40 17 0 1
% 0.12/0.40 18 1 0
% 0.12/0.40 tot: 5 6 (54.5% true)
% 0.12/0.40
% 0.12/0.40
% 0.12/0.40 Model 1 (0.00 seconds, 0 Inserts)
% 0.12/0.40
% 0.12/0.40 That finishes the proof of the theorem.
% 0.12/0.40
% 0.12/0.40 Process 27317 finished Wed Jul 6 06:21:19 2022
%------------------------------------------------------------------------------