%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM844+2 : TPTP v9.2.0. Released v4.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n006.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:26 PM UTC 2025 % Result : Theorem 3.75s 3.93s % Output : Proof 3.75s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.10/0.11 % Problem : NUM844+2 : TPTP v9.2.0. Released v4.1.0. % 0.10/0.13 % Command : duper %s % 0.13/0.33 % Computer : n006.cluster.edu % 0.13/0.33 % Model : x86_64 x86_64 % 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.33 % Memory : 8042.1875MB % 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 08:38:08 EDT 2025 % 0.13/0.34 % CPUTime : % 3.75/3.93 SZS status Theorem for theBenchmark.p % 3.75/3.93 SZS output start Proof for theBenchmark.p % 3.75/3.93 Clause #0 (by assumption #[]): Eq % 3.75/3.93 (Not % 3.75/3.93 (Eq (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413)))) % 3.75/3.93 True % 3.75/3.93 Clause #12 (by assumption #[]): Eq (∀ (Vd78 Vd79 : Iota), Eq (vplus Vd79 Vd78) (vplus Vd78 Vd79)) True % 3.75/3.93 Clause #31 (by clausification #[0]): Eq (Eq (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413))) % 3.75/3.93 False % 3.75/3.93 Clause #32 (by clausification #[31]): Ne (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413)) % 3.75/3.93 Clause #143 (by clausification #[12]): ∀ (a : Iota), Eq (∀ (Vd79 : Iota), Eq (vplus Vd79 a) (vplus a Vd79)) True % 3.75/3.93 Clause #144 (by clausification #[143]): ∀ (a a_1 : Iota), Eq (Eq (vplus a a_1) (vplus a_1 a)) True % 3.75/3.93 Clause #145 (by clausification #[144]): ∀ (a a_1 : Iota), Eq (vplus a a_1) (vplus a_1 a) % 3.75/3.93 Clause #146 (by backward positive simplify reflect #[145, 32]): False % 3.75/3.93 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------