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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM977_5 : TPTP v9.2.0. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:57:41 PM UTC 2025

% Result   : Theorem 13.18s 13.37s
% Output   : Proof 13.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.14  % Problem    : NUM977_5 : TPTP v9.2.0. Released v6.0.0.
% 0.15/0.15  % Command    : duper %s
% 0.16/0.37  % Computer : n012.cluster.edu
% 0.16/0.37  % Model    : x86_64 x86_64
% 0.16/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37  % Memory   : 8042.1875MB
% 0.16/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37  % CPULimit   : 300
% 0.16/0.37  % WCLimit    : 300
% 0.16/0.37  % DateTime   : Fri Oct  3 08:18:08 EDT 2025
% 0.23/0.37  % CPUTime    : 
% 13.18/13.37  SZS status Theorem for theBenchmark.p
% 13.18/13.37  SZS output start Proof for theBenchmark.p
% 13.18/13.37  Clause #1 (by assumption #[]): Eq
% 13.18/13.37    (Not
% 13.18/13.37      (twoSqu1567020053sum2sq
% 13.18/13.37        (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37          (plus_plus int (one_one int) (semiring_1_of_nat int (zero_zero nat))))))
% 13.18/13.37    True
% 13.18/13.37  Clause #79 (by assumption #[]): Eq (Eq pls (zero_zero int)) True
% 13.18/13.37  Clause #91 (by assumption #[]): Eq (Eq (semiring_1_of_nat int (zero_zero nat)) (zero_zero int)) True
% 13.18/13.37  Clause #112 (by assumption #[]): Eq
% 13.18/13.37    (Not
% 13.18/13.37      (Not
% 13.18/13.37        (twoSqu1567020053sum2sq
% 13.18/13.37          (times_times int
% 13.18/13.37            (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37            (plus_plus int (one_one int) (semiring_1_of_nat int (zero_zero nat)))))))
% 13.18/13.37    True
% 13.18/13.37  Clause #113 (by clausification #[1]): Eq
% 13.18/13.37    (twoSqu1567020053sum2sq
% 13.18/13.37      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37        (plus_plus int (one_one int) (semiring_1_of_nat int (zero_zero nat)))))
% 13.18/13.37    False
% 13.18/13.37  Clause #115 (by clausification #[79]): Eq pls (zero_zero int)
% 13.18/13.37  Clause #192 (by clausification #[91]): Eq (semiring_1_of_nat int (zero_zero nat)) (zero_zero int)
% 13.18/13.37  Clause #193 (by forward demodulation #[192, 115]): Eq (semiring_1_of_nat int (zero_zero nat)) pls
% 13.18/13.37  Clause #194 (by backward demodulation #[193, 113]): Eq
% 13.18/13.37    (twoSqu1567020053sum2sq
% 13.18/13.37      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37        (plus_plus int (one_one int) pls)))
% 13.18/13.37    False
% 13.18/13.37  Clause #1379 (by clausification #[112]): Eq
% 13.18/13.37    (Not
% 13.18/13.37      (twoSqu1567020053sum2sq
% 13.18/13.37        (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37          (plus_plus int (one_one int) (semiring_1_of_nat int (zero_zero nat))))))
% 13.18/13.37    False
% 13.18/13.37  Clause #1380 (by clausification #[1379]): Eq
% 13.18/13.37    (twoSqu1567020053sum2sq
% 13.18/13.37      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37        (plus_plus int (one_one int) (semiring_1_of_nat int (zero_zero nat)))))
% 13.18/13.37    True
% 13.18/13.37  Clause #1381 (by forward demodulation #[1380, 193]): Eq
% 13.18/13.37    (twoSqu1567020053sum2sq
% 13.18/13.37      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 13.18/13.37        (plus_plus int (one_one int) pls)))
% 13.18/13.37    True
% 13.18/13.37  Clause #1875 (by superposition #[194, 1381]): Eq True False
% 13.18/13.37  Clause #1876 (by clausification #[1875]): False
% 13.18/13.37  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------