↑ Up

SPASS---3.9.THM-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUN070+2 : TPTP v8.1.0. Released v7.3.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 16:38:45 EDT 2022

% Result   : Theorem 0.26s 0.64s
% Output   : Refutation 0.26s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   14 (   7 unt;   1 nHn;  14 RR)
%            Number of literals    :   29 (   0 equ;  20 neg)
%            Maximal clause size   :    6 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   1 prp; 0-3 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    r1(skf22(u)),
    file('NUN070+2.p',unknown),
    [] ).

cnf(6,axiom,
    r2(u,skf20(v,u)),
    file('NUN070+2.p',unknown),
    [] ).

cnf(7,axiom,
    r3(u,skf22(u),u),
    file('NUN070+2.p',unknown),
    [] ).

cnf(8,axiom,
    ( equal(u,skc1)
    | skP0(skc1,u) ),
    file('NUN070+2.p',unknown),
    [] ).

cnf(13,axiom,
    ( ~ r1(u)
    | ~ skP0(v,u) ),
    file('NUN070+2.p',unknown),
    [] ).

cnf(33,axiom,
    ( ~ r1(u)
    | ~ r1(v)
    | ~ r1(w)
    | ~ r2(v,x)
    | ~ r3(x,u,y)
    | ~ r2(w,y) ),
    file('NUN070+2.p',unknown),
    [] ).

cnf(46,plain,
    ( ~ r1(skf22(u))
    | ~ r1(v)
    | ~ r1(w)
    | ~ r2(v,u)
    | ~ r2(w,u) ),
    inference(res,[status(thm),theory(equality)],[7,33]),
    [iquote('0:Res:7.0,33.4')] ).

cnf(53,plain,
    ( ~ r1(skf22(u))
    | ~ r1(v)
    | ~ r2(v,u) ),
    inference(con,[status(thm)],[46]),
    [iquote('0:Con:46.2')] ).

cnf(54,plain,
    ( ~ r1(u)
    | ~ r2(u,v) ),
    inference(mrr,[status(thm)],[53,1]),
    [iquote('0:MRR:53.0,1.0')] ).

cnf(55,plain,
    ( ~ r1(u)
    | equal(u,skc1) ),
    inference(res,[status(thm),theory(equality)],[8,13]),
    [iquote('0:Res:8.1,13.1')] ).

cnf(57,plain,
    equal(skf22(u),skc1),
    inference(ems,[status(thm)],[55,1]),
    [iquote('0:EmS:55.0,1.0')] ).

cnf(60,plain,
    r1(skc1),
    inference(rew,[status(thm),theory(equality)],[57,1]),
    [iquote('0:Rew:57.0,1.0')] ).

cnf(73,plain,
    ~ r1(u),
    inference(res,[status(thm),theory(equality)],[6,54]),
    [iquote('0:Res:6.0,54.1')] ).

cnf(76,plain,
    $false,
    inference(unc,[status(thm)],[73,60]),
    [iquote('0:UnC:73.0,60.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.32  % Problem  : NUN070+2 : TPTP v8.1.0. Released v7.3.0.
% 0.11/0.32  % Command  : run_spass %d %s
% 0.12/0.53  % Computer : n020.cluster.edu
% 0.12/0.53  % Model    : x86_64 x86_64
% 0.12/0.53  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.53  % Memory   : 8042.1875MB
% 0.12/0.53  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.53  % CPULimit : 300
% 0.12/0.53  % WCLimit  : 600
% 0.12/0.53  % DateTime : Thu Jun  2 09:53:53 EDT 2022
% 0.12/0.53  % CPUTime  : 
% 0.26/0.64  
% 0.26/0.64  SPASS V 3.9 
% 0.26/0.64  SPASS beiseite: Proof found.
% 0.26/0.64  % SZS status Theorem
% 0.26/0.64  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.26/0.64  SPASS derived 39 clauses, backtracked 0 clauses, performed 0 splits and kept 46 clauses.
% 0.26/0.64  SPASS allocated 97734 KBytes.
% 0.26/0.64  SPASS spent	0:00:00.09 on the problem.
% 0.26/0.64  		0:00:00.03 for the input.
% 0.26/0.64  		0:00:00.03 for the FLOTTER CNF translation.
% 0.26/0.64  		0:00:00.00 for inferences.
% 0.26/0.64  		0:00:00.00 for the backtracking.
% 0.26/0.64  		0:00:00.00 for the reduction.
% 0.26/0.64  
% 0.26/0.64  
% 0.26/0.64  Here is a proof with depth 2, length 14 :
% 0.26/0.64  % SZS output start Refutation
% See solution above
% 0.26/0.64  Formulae used in the proof : axiom_4a axiom_2a axiom_1 onepluszeroeqone
% 0.26/0.64  
%------------------------------------------------------------------------------