↑ Up

SPASS---3.9.THM-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : PRO011+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 17:53:48 EDT 2022

% Result   : Theorem 0.40s 0.61s
% Output   : Refutation 0.40s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   12 (   4 unt;   1 nHn;  12 RR)
%            Number of literals    :   23 (   0 equ;  13 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-3 aty)
%            Number of functors    :    9 (   9 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(6,axiom,
    occurrence_of(skc1,tptp0),
    file('PRO011+3.p',unknown),
    [] ).

cnf(39,axiom,
    ( ~ occurrence_of(u,tptp0)
    | leaf_occ(skf39(u),u) ),
    file('PRO011+3.p',unknown),
    [] ).

cnf(56,axiom,
    ( skP0(u,v,w)
    | min_precedes(u,skf22(u,x),tptp0) ),
    file('PRO011+3.p',unknown),
    [] ).

cnf(84,axiom,
    ( ~ leaf_occ(u,v)
    | ~ occurrence_of(v,w)
    | ~ min_precedes(u,x,w) ),
    file('PRO011+3.p',unknown),
    [] ).

cnf(87,axiom,
    ( ~ leaf_occ(u,skc1)
    | ~ skP0(v,skc1,u)
    | min_precedes(v,skf21(v),tptp0) ),
    file('PRO011+3.p',unknown),
    [] ).

cnf(120,plain,
    ( ~ leaf_occ(u,skc1)
    | ~ min_precedes(u,v,tptp0) ),
    inference(res,[status(thm),theory(equality)],[6,84]),
    [iquote('0:Res:6.0,84.0')] ).

cnf(130,plain,
    leaf_occ(skf39(skc1),skc1),
    inference(res,[status(thm),theory(equality)],[6,39]),
    [iquote('0:Res:6.0,39.0')] ).

cnf(357,plain,
    ( ~ leaf_occ(u,skc1)
    | skP0(u,v,w) ),
    inference(res,[status(thm),theory(equality)],[56,120]),
    [iquote('0:Res:56.1,120.1')] ).

cnf(947,plain,
    ( ~ leaf_occ(u,skc1)
    | ~ leaf_occ(v,skc1)
    | min_precedes(u,skf21(u),tptp0) ),
    inference(res,[status(thm),theory(equality)],[357,87]),
    [iquote('0:Res:357.1,87.1')] ).

cnf(956,plain,
    ( ~ leaf_occ(u,skc1)
    | min_precedes(u,skf21(u),tptp0) ),
    inference(con,[status(thm)],[947]),
    [iquote('0:Con:947.1')] ).

cnf(957,plain,
    ~ leaf_occ(u,skc1),
    inference(mrr,[status(thm)],[956,120]),
    [iquote('0:MRR:956.1,120.1')] ).

cnf(958,plain,
    $false,
    inference(unc,[status(thm)],[957,130]),
    [iquote('0:UnC:957.0,130.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : PRO011+3 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n024.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jun 13 02:15:18 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.40/0.61  
% 0.40/0.61  SPASS V 3.9 
% 0.40/0.61  SPASS beiseite: Proof found.
% 0.40/0.61  % SZS status Theorem
% 0.40/0.61  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.40/0.61  SPASS derived 757 clauses, backtracked 78 clauses, performed 8 splits and kept 576 clauses.
% 0.40/0.61  SPASS allocated 100002 KBytes.
% 0.40/0.61  SPASS spent	0:00:00.26 on the problem.
% 0.40/0.61  		0:00:00.04 for the input.
% 0.40/0.61  		0:00:00.14 for the FLOTTER CNF translation.
% 0.40/0.61  		0:00:00.01 for inferences.
% 0.40/0.61  		0:00:00.00 for the backtracking.
% 0.40/0.61  		0:00:00.04 for the reduction.
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  Here is a proof with depth 3, length 12 :
% 0.40/0.61  % SZS output start Refutation
% See solution above
% 0.40/0.61  Formulae used in the proof : goals sos_49 sos_37
% 0.40/0.61  
%------------------------------------------------------------------------------