%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : PUZ082^1 : TPTP v6.1.0. Released v3.6.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n110.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-431.20.3.el6.x86_64 % CPULimit : 300s % DateTime : Thu Jul 17 13:28:57 EDT 2014 % Result : Theorem 0.36s % Output : Proof 0.36s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----ERROR: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % % Problem : PUZ082^1 : TPTP v6.1.0. Released v3.6.0. % % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % % Computer : n110.star.cs.uiowa.edu % % Model : x86_64 x86_64 % % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % % Memory : 32286.75MB % % OS : Linux 2.6.32-431.20.3.el6.x86_64 % % CPULimit : 300 % % DateTime : Thu Jul 17 08:13:26 CDT 2014 % % CPUTime : 0.36 % Python 2.7.5 % Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % FOF formula (<kernel.Constant object at 0x923ab8>, <kernel.Constant object at 0x9238c0>) of role type named peter % Using role type % Declaring peter:fofType % FOF formula (<kernel.Constant object at 0xb01290>, <kernel.DependentProduct object at 0x923c20>) of role type named says % Using role type % Declaring says:(fofType->(Prop->Prop)) % FOF formula ((says peter) (forall (X:Prop), (((says peter) X)->(X->False)))) of role axiom named ax1 % A new axiom: ((says peter) (forall (X:Prop), (((says peter) X)->(X->False)))) % FOF formula ((forall (X:Prop), (((says peter) X)->(X->False)))->False) of role conjecture named thm % Conjecture to prove = ((forall (X:Prop), (((says peter) X)->(X->False)))->False):Prop % We need to prove ['((forall (X:Prop), (((says peter) X)->(X->False)))->False)'] % Parameter fofType:Type. % Parameter peter:fofType. % Parameter says:(fofType->(Prop->Prop)). % Axiom ax1:((says peter) (forall (X:Prop), (((says peter) X)->(X->False)))). % Trying to prove ((forall (X:Prop), (((says peter) X)->(X->False)))->False) % Found x:(forall (X:Prop), (((says peter) X)->(X->False))) % Found x as proof of (forall (X:Prop), (((says peter) X)->(X->False))) % Found (x00 x) as proof of False % Found ((x0 ax1) x) as proof of False % Found (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x) as proof of False % Found (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) as proof of False % Found (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) as proof of ((forall (X:Prop), (((says peter) X)->(X->False)))->False) % Got proof (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) % Time elapsed = 0.041653s % node=18 cost=240.000000 depth=5 % :::::::::::::::::::::: % % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) % % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % EOF %------------------------------------------------------------------------------