%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : PUZ132+1 : TPTP v9.2.0. Released v4.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n024.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:58:24 PM UTC 2025 % Result : Theorem 3.50s 3.69s % Output : Proof 3.50s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.04/0.13 % Problem : PUZ132+1 : TPTP v9.2.0. Released v4.1.0. % 0.14/0.14 % Command : duper %s % 0.14/0.35 % Computer : n024.cluster.edu % 0.14/0.35 % Model : x86_64 x86_64 % 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.35 % Memory : 8042.1875MB % 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.35 % CPULimit : 300 % 0.14/0.35 % WCLimit : 300 % 0.14/0.35 % DateTime : Thu Oct 2 20:53:08 EDT 2025 % 0.21/0.35 % CPUTime : % 3.50/3.69 SZS status Theorem for theBenchmark.p % 3.50/3.69 SZS output start Proof for theBenchmark.p % 3.50/3.69 Clause #2 (by assumption #[]): Eq (∀ (A : Iota), capital A → city A) True % 3.50/3.69 Clause #4 (by assumption #[]): Eq (capital washington) True % 3.50/3.69 Clause #5 (by assumption #[]): Eq (country usa) True % 3.50/3.69 Clause #7 (by assumption #[]): Eq (∀ (X : Iota), city X → has_crime X) True % 3.50/3.69 Clause #8 (by assumption #[]): Eq (Eq (capital_city usa) washington) True % 3.50/3.69 Clause #9 (by assumption #[]): Eq (∀ (X : Iota), country X → beautiful (capital_city X)) True % 3.50/3.69 Clause #10 (by assumption #[]): Eq (Not (And (beautiful washington) (has_crime washington))) True % 3.50/3.69 Clause #11 (by clausification #[2]): ∀ (a : Iota), Eq (capital a → city a) True % 3.50/3.69 Clause #12 (by clausification #[11]): ∀ (a : Iota), Or (Eq (capital a) False) (Eq (city a) True) % 3.50/3.69 Clause #13 (by superposition #[12, 4]): Or (Eq (city washington) True) (Eq False True) % 3.50/3.69 Clause #14 (by clausification #[13]): Eq (city washington) True % 3.50/3.69 Clause #15 (by clausification #[7]): ∀ (a : Iota), Eq (city a → has_crime a) True % 3.50/3.69 Clause #16 (by clausification #[15]): ∀ (a : Iota), Or (Eq (city a) False) (Eq (has_crime a) True) % 3.50/3.69 Clause #17 (by superposition #[16, 14]): Or (Eq (has_crime washington) True) (Eq False True) % 3.50/3.69 Clause #21 (by clausification #[17]): Eq (has_crime washington) True % 3.50/3.69 Clause #25 (by clausification #[9]): ∀ (a : Iota), Eq (country a → beautiful (capital_city a)) True % 3.50/3.69 Clause #26 (by clausification #[25]): ∀ (a : Iota), Or (Eq (country a) False) (Eq (beautiful (capital_city a)) True) % 3.50/3.69 Clause #27 (by superposition #[26, 5]): Or (Eq (beautiful (capital_city usa)) True) (Eq False True) % 3.50/3.69 Clause #28 (by clausification #[27]): Eq (beautiful (capital_city usa)) True % 3.50/3.69 Clause #29 (by clausification #[8]): Eq (capital_city usa) washington % 3.50/3.69 Clause #30 (by backward demodulation #[29, 28]): Eq (beautiful washington) True % 3.50/3.69 Clause #39 (by clausification #[10]): Eq (And (beautiful washington) (has_crime washington)) False % 3.50/3.69 Clause #40 (by clausification #[39]): Or (Eq (beautiful washington) False) (Eq (has_crime washington) False) % 3.50/3.69 Clause #41 (by forward demodulation #[40, 21]): Or (Eq (beautiful washington) False) (Eq True False) % 3.50/3.69 Clause #42 (by clausification #[41]): Eq (beautiful washington) False % 3.50/3.69 Clause #43 (by superposition #[42, 30]): Eq False True % 3.50/3.69 Clause #44 (by clausification #[43]): False % 3.50/3.69 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------