%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : RNG072+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 20:41:23 EDT 2022
% Result : Theorem 0.16s 0.41s
% Output : Refutation 0.16s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 8
% Syntax : Number of clauses : 14 ( 7 unt; 0 nHn; 14 RR)
% Number of literals : 36 ( 0 equ; 28 neg)
% Maximal clause size : 8 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 10 ( 10 usr; 8 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(15,axiom,
aScalar0(xR),
file('RNG072+1.p',unknown),
[] ).
cnf(16,axiom,
aScalar0(xP),
file('RNG072+1.p',unknown),
[] ).
cnf(17,axiom,
aScalar0(xS),
file('RNG072+1.p',unknown),
[] ).
cnf(36,axiom,
sdtlseqdt0(sz0z00,sdtpldt0(xR,xS)),
file('RNG072+1.p',unknown),
[] ).
cnf(47,axiom,
sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)),
file('RNG072+1.p',unknown),
[] ).
cnf(59,axiom,
( ~ aScalar0(u)
| ~ aScalar0(v)
| aScalar0(sdtpldt0(v,u)) ),
file('RNG072+1.p',unknown),
[] ).
cnf(73,axiom,
~ sdtlseqdt0(sdtasdt0(sdtpldt0(xR,xS),sdtpldt0(xR,xS)),sdtasdt0(sdtpldt0(xP,xP),sdtpldt0(xP,xP))),
file('RNG072+1.p',unknown),
[] ).
cnf(89,axiom,
( ~ aScalar0(u)
| ~ aScalar0(v)
| ~ aScalar0(w)
| ~ aScalar0(x)
| ~ sdtlseqdt0(x,w)
| ~ sdtlseqdt0(v,u)
| ~ sdtlseqdt0(sz0z00,v)
| sdtlseqdt0(sdtasdt0(x,v),sdtasdt0(w,u)) ),
file('RNG072+1.p',unknown),
[] ).
cnf(95,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sz0z00,sdtpldt0(xR,xS))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)) ),
inference(res,[status(thm),theory(equality)],[89,73]),
[iquote('0:Res:89.7,73.0')] ).
cnf(99,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sz0z00,sdtpldt0(xR,xS))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)) ),
inference(obv,[status(thm),theory(equality)],[95]),
[iquote('0:Obv:95.5')] ).
cnf(100,plain,
( ~ aScalar0(sdtpldt0(xP,xP))
| ~ aScalar0(sdtpldt0(xR,xS)) ),
inference(mrr,[status(thm)],[99,36,47]),
[iquote('0:MRR:99.2,99.3,36.0,47.0')] ).
cnf(177,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(xP)
| ~ aScalar0(xP) ),
inference(sor,[status(thm)],[100,59]),
[iquote('0:SoR:100.0,59.2')] ).
cnf(183,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(xP) ),
inference(obv,[status(thm),theory(equality)],[177]),
[iquote('0:Obv:177.1')] ).
cnf(184,plain,
$false,
inference(ssi,[status(thm)],[183,16,59,15,17]),
[iquote('0:SSi:183.1,183.0,16.0,59.0,15.2,17.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.11 % Problem : RNG072+1 : TPTP v8.1.0. Released v4.0.0.
% 0.09/0.11 % Command : run_spass %d %s
% 0.11/0.31 % Computer : n019.cluster.edu
% 0.11/0.31 % Model : x86_64 x86_64
% 0.11/0.31 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.31 % Memory : 8042.1875MB
% 0.11/0.31 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.31 % CPULimit : 300
% 0.11/0.31 % WCLimit : 600
% 0.11/0.31 % DateTime : Mon May 30 16:48:25 EDT 2022
% 0.15/0.31 % CPUTime :
% 0.16/0.41
% 0.16/0.41 SPASS V 3.9
% 0.16/0.41 SPASS beiseite: Proof found.
% 0.16/0.41 % SZS status Theorem
% 0.16/0.41 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.16/0.41 SPASS derived 77 clauses, backtracked 0 clauses, performed 0 splits and kept 103 clauses.
% 0.16/0.41 SPASS allocated 97880 KBytes.
% 0.16/0.41 SPASS spent 0:00:00.09 on the problem.
% 0.16/0.41 0:00:00.03 for the input.
% 0.16/0.41 0:00:00.03 for the FLOTTER CNF translation.
% 0.16/0.41 0:00:00.00 for inferences.
% 0.16/0.41 0:00:00.00 for the backtracking.
% 0.16/0.41 0:00:00.01 for the reduction.
% 0.16/0.41
% 0.16/0.41
% 0.16/0.41 Here is a proof with depth 2, length 14 :
% 0.16/0.41 % SZS output start Refutation
% See solution above
% 0.16/0.41 Formulae used in the proof : m__1892 m__1911 m__1930 m__2628 m__2610 mSumSc m__ mLEMonM
% 0.16/0.41
%------------------------------------------------------------------------------