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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : RNG074+1 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:58:53 PM UTC 2025

% Result   : Theorem 4.26s 4.43s
% Output   : Proof 4.26s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13  % Problem    : RNG074+1 : TPTP v9.2.0. Released v4.0.0.
% 0.13/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n012.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Oct  3 11:03:23 EDT 2025
% 0.14/0.36  % CPUTime    : 
% 4.26/4.43  SZS status Theorem for theBenchmark.p
% 4.26/4.43  SZS output start Proof for theBenchmark.p
% 4.26/4.43  Clause #59 (by assumption #[]): Eq (Not (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xR xS))) True
% 4.26/4.43  Clause #60 (by assumption #[]): Eq (sdtlseqdt0 (sdtpldt0 xR xS) (sdtpldt0 xP xP)) True
% 4.26/4.43  Clause #63 (by assumption #[]): Eq (Eq (sdtpldt0 xR xS) (sdtpldt0 xP xP)) True
% 4.26/4.43  Clause #406 (by clausification #[59]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xR xS)) False
% 4.26/4.43  Clause #407 (by clausification #[63]): Eq (sdtpldt0 xR xS) (sdtpldt0 xP xP)
% 4.26/4.43  Clause #408 (by backward demodulation #[407, 60]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xP xP)) True
% 4.26/4.43  Clause #409 (by backward demodulation #[407, 406]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xP xP)) False
% 4.26/4.43  Clause #410 (by superposition #[408, 409]): Eq False True
% 4.26/4.43  Clause #417 (by clausification #[410]): False
% 4.26/4.43  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------