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SPASS---3.9.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG091+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:27 EDT 2022

% Result   : Theorem 0.18s 0.51s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   12 (   8 unt;   0 nHn;  12 RR)
%            Number of literals    :   22 (   0 equ;  12 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   2 prp; 0-2 aty)
%            Number of functors    :   13 (  13 usr;  11 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(25,axiom,
    aElementOf0(sdtpldt0(xk,xm),xI),
    file('RNG091+2.p',unknown),
    [] ).

cnf(26,axiom,
    aElementOf0(sdtpldt0(xl,xn),xJ),
    file('RNG091+2.p',unknown),
    [] ).

cnf(27,axiom,
    aElementOf0(sdtasdt0(xz,xk),xI),
    file('RNG091+2.p',unknown),
    [] ).

cnf(28,axiom,
    aElementOf0(sdtasdt0(xz,xl),xJ),
    file('RNG091+2.p',unknown),
    [] ).

cnf(50,axiom,
    equal(sdtpldt0(sdtpldt0(xk,xm),sdtpldt0(xl,xn)),sdtpldt0(xx,xy)),
    file('RNG091+2.p',unknown),
    [] ).

cnf(51,axiom,
    equal(sdtpldt0(sdtasdt0(xz,xk),sdtasdt0(xz,xl)),sdtasdt0(xz,xx)),
    file('RNG091+2.p',unknown),
    [] ).

cnf(63,axiom,
    ( ~ aElementOf0(u,xI)
    | ~ equal(sdtpldt0(u,v),sdtpldt0(xx,xy))
    | ~ aElementOf0(v,xJ)
    | skC0 ),
    file('RNG091+2.p',unknown),
    [] ).

cnf(66,axiom,
    ( ~ aElementOf0(u,xI)
    | ~ equal(sdtpldt0(u,v),sdtasdt0(xz,xx))
    | ~ aElementOf0(v,xJ)
    | ~ skC0 ),
    file('RNG091+2.p',unknown),
    [] ).

cnf(90,plain,
    ( ~ aElementOf0(sdtpldt0(xk,xm),xI)
    | ~ aElementOf0(sdtpldt0(xl,xn),xJ)
    | skC0 ),
    inference(res,[status(thm),theory(equality)],[50,63]),
    [iquote('0:Res:50.0,63.1')] ).

cnf(103,plain,
    ( ~ aElementOf0(sdtasdt0(xz,xk),xI)
    | ~ aElementOf0(sdtasdt0(xz,xl),xJ)
    | ~ skC0 ),
    inference(res,[status(thm),theory(equality)],[51,66]),
    [iquote('0:Res:51.0,66.1')] ).

cnf(110,plain,
    skC0,
    inference(mrr,[status(thm)],[90,25,26]),
    [iquote('0:MRR:90.0,90.1,25.0,26.0')] ).

cnf(117,plain,
    $false,
    inference(mrr,[status(thm)],[103,27,28,110]),
    [iquote('0:MRR:103.0,103.1,103.2,27.0,28.0,110.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : RNG091+2 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n027.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon May 30 06:10:31 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.51  
% 0.18/0.51  SPASS V 3.9 
% 0.18/0.51  SPASS beiseite: Proof found.
% 0.18/0.51  % SZS status Theorem
% 0.18/0.51  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.51  SPASS derived 20 clauses, backtracked 0 clauses, performed 0 splits and kept 94 clauses.
% 0.18/0.51  SPASS allocated 98788 KBytes.
% 0.18/0.51  SPASS spent	0:00:00.16 on the problem.
% 0.18/0.51  		0:00:00.03 for the input.
% 0.18/0.51  		0:00:00.10 for the FLOTTER CNF translation.
% 0.18/0.51  		0:00:00.00 for inferences.
% 0.18/0.51  		0:00:00.00 for the backtracking.
% 0.18/0.51  		0:00:00.00 for the reduction.
% 0.18/0.51  
% 0.18/0.51  
% 0.18/0.51  Here is a proof with depth 1, length 12 :
% 0.18/0.51  % SZS output start Refutation
% See solution above
% 0.18/0.51  Formulae used in the proof : m__994 m__1021 m__1061 m__1098 m__
% 0.18/0.51  
%------------------------------------------------------------------------------