%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SET043^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n015.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:59:28 PM UTC 2025 % Result : Theorem 3.55s 3.72s % Output : Proof 3.55s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : SET043^5 : TPTP v9.2.0. Released v4.0.0. % 0.07/0.14 % Command : duper %s % 0.13/0.35 % Computer : n015.cluster.edu % 0.13/0.35 % Model : x86_64 x86_64 % 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.35 % Memory : 8042.1875MB % 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.35 % CPULimit : 300 % 0.13/0.35 % WCLimit : 300 % 0.13/0.35 % DateTime : Thu Oct 2 13:33:38 EDT 2025 % 0.13/0.35 % CPUTime : % 3.55/3.72 SZS status Theorem for theBenchmark.p % 3.55/3.72 SZS output start Proof for theBenchmark.p % 3.55/3.72 Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun U => ∀ (V : Iota), Iff (cE V U) (Not (cE V V))))) True % 3.55/3.72 Clause #1 (by clausification #[0]): Eq (Not (Exists fun U => ∀ (V : Iota), Iff (cE V U) (Not (cE V V)))) False % 3.55/3.72 Clause #2 (by clausification #[1]): Eq (Exists fun U => ∀ (V : Iota), Iff (cE V U) (Not (cE V V))) True % 3.55/3.72 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (V : Iota), Iff (cE V (skS.0 0 a)) (Not (cE V V))) True % 3.55/3.72 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Iff (cE a (skS.0 0 a_1)) (Not (cE a a))) True % 3.55/3.72 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (cE a (skS.0 0 a_1)) True) (Eq (Not (cE a a)) False) % 3.55/3.72 Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (cE a (skS.0 0 a_1)) False) (Eq (Not (cE a a)) True) % 3.55/3.72 Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Or (Eq (cE a (skS.0 0 a_1)) True) (Eq (cE a a) True) % 3.55/3.72 Clause #8 (by equality factoring #[7]): ∀ (a : Iota), Or (Ne True True) (Eq (cE (skS.0 0 a) (skS.0 0 a)) True) % 3.55/3.72 Clause #9 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (cE a (skS.0 0 a_1)) False) (Eq (cE a a) False) % 3.55/3.72 Clause #13 (by clausification #[8]): ∀ (a : Iota), Or (Eq (cE (skS.0 0 a) (skS.0 0 a)) True) (Or (Eq True False) (Eq True False)) % 3.55/3.72 Clause #15 (by clausification #[13]): ∀ (a : Iota), Or (Eq (cE (skS.0 0 a) (skS.0 0 a)) True) (Eq True False) % 3.55/3.72 Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (cE (skS.0 0 a) (skS.0 0 a)) True % 3.55/3.72 Clause #17 (by superposition #[16, 9]): Or (Eq True False) (Eq True False) % 3.55/3.72 Clause #18 (by clausification #[17]): Eq True False % 3.55/3.72 Clause #19 (by clausification #[18]): False % 3.55/3.72 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------