%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SET043+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n013.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:59:28 PM UTC 2025 % Result : Theorem 4.23s 4.42s % Output : Proof 4.23s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.14 % Problem : SET043+1 : TPTP v9.2.0. Released v2.0.0. % 0.11/0.15 % Command : duper %s % 0.14/0.36 % Computer : n013.cluster.edu % 0.14/0.36 % Model : x86_64 x86_64 % 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.36 % Memory : 8042.1875MB % 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.37 % CPULimit : 300 % 0.14/0.37 % WCLimit : 300 % 0.14/0.37 % DateTime : Thu Oct 2 14:42:23 EDT 2025 % 0.14/0.37 % CPUTime : % 4.23/4.42 SZS status Theorem for theBenchmark.p % 4.23/4.42 SZS output start Proof for theBenchmark.p % 4.23/4.42 Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y))))) True % 4.23/4.42 Clause #1 (by clausification #[0]): Eq (Not (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y)))) False % 4.23/4.42 Clause #2 (by clausification #[1]): Eq (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y))) True % 4.23/4.42 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y : Iota), Iff (element Y (skS.0 0 a)) (Not (element Y Y))) True % 4.23/4.42 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Iff (element a (skS.0 0 a_1)) (Not (element a a))) True % 4.23/4.42 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) True) (Eq (Not (element a a)) False) % 4.23/4.42 Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) False) (Eq (Not (element a a)) True) % 4.23/4.42 Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) True) (Eq (element a a) True) % 4.23/4.42 Clause #8 (by equality factoring #[7]): ∀ (a : Iota), Or (Ne True True) (Eq (element (skS.0 0 a) (skS.0 0 a)) True) % 4.23/4.42 Clause #9 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) False) (Eq (element a a) False) % 4.23/4.42 Clause #13 (by clausification #[8]): ∀ (a : Iota), Or (Eq (element (skS.0 0 a) (skS.0 0 a)) True) (Or (Eq True False) (Eq True False)) % 4.23/4.42 Clause #15 (by clausification #[13]): ∀ (a : Iota), Or (Eq (element (skS.0 0 a) (skS.0 0 a)) True) (Eq True False) % 4.23/4.42 Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (element (skS.0 0 a) (skS.0 0 a)) True % 4.23/4.42 Clause #17 (by superposition #[16, 9]): Or (Eq True False) (Eq True False) % 4.23/4.42 Clause #18 (by clausification #[17]): Eq True False % 4.23/4.42 Clause #19 (by clausification #[18]): False % 4.23/4.42 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------