%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SET045^5 : TPTP v6.1.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n092.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-431.20.3.el6.x86_64 % CPULimit : 300s % DateTime : Thu Jul 17 13:30:03 EDT 2014 % Result : Theorem 0.63s % Output : Proof 0.63s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----ERROR: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % % Problem : SET045^5 : TPTP v6.1.0. Released v4.0.0. % % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % % Computer : n092.star.cs.uiowa.edu % % Model : x86_64 x86_64 % % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % % Memory : 32286.75MB % % OS : Linux 2.6.32-431.20.3.el6.x86_64 % % CPULimit : 300 % % DateTime : Thu Jul 17 08:17:11 CDT 2014 % % CPUTime : 0.63 % Python 2.7.5 % Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % FOF formula (<kernel.Constant object at 0x1d03368>, <kernel.Type object at 0x1d22830>) of role type named b_type % Using role type % Declaring b:Type % FOF formula (<kernel.Constant object at 0x1d03170>, <kernel.Type object at 0x1d22830>) of role type named a_type % Using role type % Declaring a:Type % FOF formula (<kernel.Constant object at 0x1d03368>, <kernel.Constant object at 0x1d03248>) of role type named cA % Using role type % Declaring cA:b % FOF formula ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) of role conjecture named cTTTP5243 % Conjecture to prove = ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))):Prop % Parameter a_DUMMY:a. % We need to prove ['((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))'] % Parameter b:Type. % Parameter a:Type. % Parameter cA:b. % Trying to prove ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Found eq_ref00:=(eq_ref0 (x V)):(((eq b) (x V)) (x V)) % Found (eq_ref0 (x V)) as proof of (((eq b) (x V)) cA) % Found ((eq_ref b) (x V)) as proof of (((eq b) (x V)) cA) % Found ((eq_ref b) (x V)) as proof of (((eq b) (x V)) cA) % Found (fun (V:a)=> ((eq_ref b) (x V))) as proof of (((eq b) (x V)) cA) % Found (fun (V:a)=> ((eq_ref b) (x V))) as proof of (forall (V:a), (((eq b) (x V)) cA)) % Found (ex_intro000 (fun (V:a)=> ((eq_ref b) (x V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Found ((ex_intro00 (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Found (((ex_intro0 (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Found ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Found ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) % Got proof ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) % Time elapsed = 0.317081s % node=67 cost=53.000000 depth=9 % :::::::::::::::::::::: % % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) % % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % EOF %------------------------------------------------------------------------------