↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SET045+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:59:28 PM UTC 2025

% Result   : Theorem 3.46s 3.64s
% Output   : Proof 3.46s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem    : SET045+1 : TPTP v9.2.0. Released v2.0.0.
% 0.04/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n004.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Oct  2 14:11:23 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 3.46/3.64  SZS status Theorem for theBenchmark.p
% 3.46/3.64  SZS output start Proof for theBenchmark.p
% 3.46/3.64  Clause #0 (by assumption #[]): Eq (∀ (Z : Iota), Exists fun Y => ∀ (X : Iota), Iff (element X Y) (And (element X Z) (Not (element X X)))) True
% 3.46/3.64  Clause #1 (by assumption #[]): Eq (Not (Not (Exists fun Z => ∀ (X : Iota), element X Z))) True
% 3.46/3.64  Clause #2 (by clausification #[1]): Eq (Not (Exists fun Z => ∀ (X : Iota), element X Z)) False
% 3.46/3.64  Clause #3 (by clausification #[2]): Eq (Exists fun Z => ∀ (X : Iota), element X Z) True
% 3.46/3.64  Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (∀ (X : Iota), element X (skS.0 0 a)) True
% 3.46/3.64  Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (element a (skS.0 0 a_1)) True
% 3.46/3.64  Clause #6 (by clausification #[0]): ∀ (a : Iota), Eq (Exists fun Y => ∀ (X : Iota), Iff (element X Y) (And (element X a) (Not (element X X)))) True
% 3.46/3.64  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (∀ (X : Iota), Iff (element X (skS.0 1 a a_1)) (And (element X a) (Not (element X X)))) True
% 3.46/3.64  Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Eq (Iff (element a (skS.0 1 a_1 a_2)) (And (element a a_1) (Not (element a a)))) True
% 3.46/3.64  Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Eq (And (element a a_1) (Not (element a a))) False)
% 3.46/3.64  Clause #10 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (And (element a a_1) (Not (element a a))) True)
% 3.46/3.64  Clause #11 (by clausification #[9]): ∀ (a a_1 a_2 : Iota),
% 3.46/3.64    Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Or (Eq (element a a_1) False) (Eq (Not (element a a)) False))
% 3.46/3.64  Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Or (Eq (element a a_1) False) (Eq (element a a) True))
% 3.46/3.64  Clause #13 (by superposition #[12, 5]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 (skS.0 0 a_1) a_2)) True) (Or (Eq (element a a) True) (Eq False True))
% 3.46/3.64  Clause #14 (by clausification #[10]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (Not (element a a)) True)
% 3.46/3.64  Clause #16 (by clausification #[14]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (element a a) False)
% 3.46/3.64  Clause #17 (by clausification #[13]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 (skS.0 0 a_1) a_2)) True) (Eq (element a a) True)
% 3.46/3.64  Clause #21 (by superposition #[17, 16]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.46/3.64    Or (Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True) (Or (Eq True False) (Eq True False))
% 3.46/3.64  Clause #26 (by clausification #[21]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True) (Eq True False)
% 3.46/3.64  Clause #27 (by clausification #[26]): ∀ (a a_1 a_2 a_3 : Iota), Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True
% 3.46/3.64  Clause #28 (by superposition #[27, 16]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (element (skS.0 1 a a_1) (skS.0 1 a a_1)) False)
% 3.46/3.64  Clause #32 (by clausification #[28]): ∀ (a a_1 : Iota), Eq (element (skS.0 1 a a_1) (skS.0 1 a a_1)) False
% 3.46/3.64  Clause #33 (by superposition #[32, 27]): Eq False True
% 3.46/3.64  Clause #35 (by clausification #[33]): False
% 3.46/3.64  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------