↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SET199^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:59:48 PM UTC 2025

% Result   : Theorem 4.20s 4.39s
% Output   : Proof 4.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SET199^5 : TPTP v9.2.0. Released v4.0.0.
% 0.11/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n019.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Thu Oct  2 13:54:23 EDT 2025
% 0.12/0.34  % CPUTime    : 
% 4.20/4.39  SZS status Theorem for theBenchmark.p
% 4.20/4.39  SZS output start Proof for theBenchmark.p
% 4.20/4.39  Clause #0 (by assumption #[]): Eq
% 4.20/4.39    (Not
% 4.20/4.39      (∀ (X Y Z : a → Prop),
% 4.20/4.39        And (∀ (Xx : a), Z Xx → X Xx) (∀ (Xx : a), Z Xx → Y Xx) → ∀ (Xx : a), Z Xx → Or (X Xx) (Y Xx)))
% 4.20/4.39    True
% 4.20/4.39  Clause #1 (by clausification #[0]): Eq (∀ (X Y Z : a → Prop), And (∀ (Xx : a), Z Xx → X Xx) (∀ (Xx : a), Z Xx → Y Xx) → ∀ (Xx : a), Z Xx → Or (X Xx) (Y Xx))
% 4.20/4.39    False
% 4.20/4.39  Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (Not
% 4.20/4.39        (∀ (Y Z : a → Prop),
% 4.20/4.39          And (∀ (Xx : a), Z Xx → skS.0 0 a_1 Xx) (∀ (Xx : a), Z Xx → Y Xx) →
% 4.20/4.39            ∀ (Xx : a), Z Xx → Or (skS.0 0 a_1 Xx) (Y Xx)))
% 4.20/4.39      True
% 4.20/4.39  Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (∀ (Y Z : a → Prop),
% 4.20/4.39        And (∀ (Xx : a), Z Xx → skS.0 0 a_1 Xx) (∀ (Xx : a), Z Xx → Y Xx) → ∀ (Xx : a), Z Xx → Or (skS.0 0 a_1 Xx) (Y Xx))
% 4.20/4.39      False
% 4.20/4.39  Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (Not
% 4.20/4.39        (∀ (Z : a → Prop),
% 4.20/4.39          And (∀ (Xx : a), Z Xx → skS.0 0 a_1 Xx) (∀ (Xx : a), Z Xx → skS.0 1 a_1 a_2 Xx) →
% 4.20/4.39            ∀ (Xx : a), Z Xx → Or (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx)))
% 4.20/4.39      True
% 4.20/4.39  Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (∀ (Z : a → Prop),
% 4.20/4.39        And (∀ (Xx : a), Z Xx → skS.0 0 a_1 Xx) (∀ (Xx : a), Z Xx → skS.0 1 a_1 a_2 Xx) →
% 4.20/4.39          ∀ (Xx : a), Z Xx → Or (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx))
% 4.20/4.39      False
% 4.20/4.39  Clause #6 (by clausification #[5]): ∀ (a_1 a_2 a_3 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (Not
% 4.20/4.39        (And (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 0 a_1 Xx)
% 4.20/4.39            (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 1 a_1 a_2 Xx) →
% 4.20/4.39          ∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → Or (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx)))
% 4.20/4.39      True
% 4.20/4.39  Clause #7 (by clausification #[6]): ∀ (a_1 a_2 a_3 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (And (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 0 a_1 Xx)
% 4.20/4.39          (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 1 a_1 a_2 Xx) →
% 4.20/4.39        ∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → Or (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx))
% 4.20/4.39      False
% 4.20/4.39  Clause #8 (by clausification #[7]): ∀ (a_1 a_2 a_3 : a → Prop),
% 4.20/4.39    Eq
% 4.20/4.39      (And (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 0 a_1 Xx)
% 4.20/4.39        (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 1 a_1 a_2 Xx))
% 4.20/4.39      True
% 4.20/4.39  Clause #9 (by clausification #[7]): ∀ (a_1 a_2 a_3 : a → Prop), Eq (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → Or (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx)) False
% 4.20/4.39  Clause #10 (by clausification #[8]): ∀ (a_1 a_2 a_3 : a → Prop), Eq (∀ (Xx : a), skS.0 2 a_1 a_2 a_3 Xx → skS.0 1 a_1 a_2 Xx) True
% 4.20/4.39  Clause #12 (by clausification #[10]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 2 a_1 a_2 a_3 a_4 → skS.0 1 a_1 a_2 a_4) True
% 4.20/4.39  Clause #13 (by clausification #[12]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Or (Eq (skS.0 2 a_1 a_2 a_3 a_4) False) (Eq (skS.0 1 a_1 a_2 a_4) True)
% 4.20/4.39  Clause #16 (by clausification #[9]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 4.20/4.39    Eq
% 4.20/4.39      (Not
% 4.20/4.39        (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4) →
% 4.20/4.39          Or (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4))))
% 4.20/4.39      True
% 4.20/4.39  Clause #17 (by clausification #[16]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 4.20/4.39    Eq
% 4.20/4.39      (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4) →
% 4.20/4.39        Or (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)))
% 4.20/4.39      False
% 4.20/4.39  Clause #18 (by clausification #[17]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) True
% 4.20/4.39  Clause #19 (by clausification #[17]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 4.20/4.39    Eq (Or (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4))) False
% 4.20/4.39  Clause #20 (by superposition #[18, 13]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Or (Eq True False) (Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) True)
% 4.20/4.39  Clause #23 (by clausification #[20]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) True
% 4.20/4.39  Clause #24 (by clausification #[19]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) False
% 4.20/4.39  Clause #26 (by superposition #[24, 23]): Eq False True
% 4.20/4.39  Clause #27 (by clausification #[26]): False
% 4.20/4.39  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------