%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SET883+1 : TPTP v9.2.0. Released v3.2.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n028.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:00:38 PM UTC 2025 % Result : Theorem 3.49s 3.66s % Output : Proof 3.49s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : SET883+1 : TPTP v9.2.0. Released v3.2.0. % 0.03/0.13 % Command : duper %s % 0.13/0.34 % Computer : n028.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Thu Oct 2 13:43:53 EDT 2025 % 0.13/0.34 % CPUTime : % 3.49/3.66 SZS status Theorem for theBenchmark.p % 3.49/3.66 SZS output start Proof for theBenchmark.p % 3.49/3.66 Clause #3 (by assumption #[]): Eq (Not (∀ (A B : Iota), subset (singleton A) (singleton B) → Eq A B)) True % 3.49/3.66 Clause #4 (by assumption #[]): Eq (∀ (A B : Iota), subset (singleton A) (singleton B) → Eq A B) True % 3.49/3.66 Clause #11 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (B : Iota), subset (singleton a) (singleton B) → Eq a B) True % 3.49/3.66 Clause #12 (by clausification #[11]): ∀ (a a_1 : Iota), Eq (subset (singleton a) (singleton a_1) → Eq a a_1) True % 3.49/3.66 Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) (singleton a_1)) False) (Eq (Eq a a_1) True) % 3.49/3.66 Clause #14 (by clausification #[13]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) (singleton a_1)) False) (Eq a a_1) % 3.49/3.66 Clause #17 (by clausification #[3]): Eq (∀ (A B : Iota), subset (singleton A) (singleton B) → Eq A B) False % 3.49/3.66 Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), subset (singleton (skS.0 2 a)) (singleton B) → Eq (skS.0 2 a) B)) True % 3.49/3.66 Clause #19 (by clausification #[18]): ∀ (a : Iota), Eq (∀ (B : Iota), subset (singleton (skS.0 2 a)) (singleton B) → Eq (skS.0 2 a) B) False % 3.49/3.66 Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), % 3.49/3.66 Eq (Not (subset (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1)) → Eq (skS.0 2 a) (skS.0 3 a a_1))) True % 3.49/3.66 Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1)) → Eq (skS.0 2 a) (skS.0 3 a a_1)) False % 3.49/3.66 Clause #22 (by clausification #[21]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1))) True % 3.49/3.66 Clause #23 (by clausification #[21]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 2 a) (skS.0 3 a a_1)) False % 3.49/3.66 Clause #24 (by superposition #[22, 14]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (skS.0 2 a) (skS.0 3 a a_1)) % 3.49/3.66 Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota), Eq (skS.0 2 a) (skS.0 3 a a_1) % 3.49/3.66 Clause #27 (by clausification #[23]): ∀ (a a_1 : Iota), Ne (skS.0 2 a) (skS.0 3 a a_1) % 3.49/3.66 Clause #28 (by forward demodulation #[27, 25]): ∀ (a : Iota), Ne (skS.0 2 a) (skS.0 2 a) % 3.49/3.66 Clause #29 (by eliminate resolved literals #[28]): False % 3.49/3.66 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------