%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SET913+1 : TPTP v9.2.0. Released v3.2.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n029.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:00:41 PM UTC 2025 % Result : Theorem 3.59s 3.76s % Output : Proof 3.59s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.04/0.12 % Problem : SET913+1 : TPTP v9.2.0. Released v3.2.0. % 0.12/0.13 % Command : duper %s % 0.13/0.34 % Computer : n029.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Thu Oct 2 14:12:38 EDT 2025 % 0.13/0.35 % CPUTime : % 3.59/3.76 SZS status Theorem for theBenchmark.p % 3.59/3.76 SZS output start Proof for theBenchmark.p % 3.59/3.76 Clause #4 (by assumption #[]): Eq (Not (∀ (A B : Iota), Not (And (disjoint (singleton A) B) (in A B)))) True % 3.59/3.76 Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Not (And (disjoint (singleton A) B) (in A B))) True % 3.59/3.76 Clause #17 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (And (disjoint (singleton a) B) (in a B))) True % 3.59/3.76 Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota), Eq (Not (And (disjoint (singleton a) a_1) (in a a_1))) True % 3.59/3.76 Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Eq (And (disjoint (singleton a) a_1) (in a a_1)) False % 3.59/3.76 Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Or (Eq (disjoint (singleton a) a_1) False) (Eq (in a a_1) False) % 3.59/3.76 Clause #21 (by clausification #[4]): Eq (∀ (A B : Iota), Not (And (disjoint (singleton A) B) (in A B))) False % 3.59/3.76 Clause #22 (by clausification #[21]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Not (And (disjoint (singleton (skS.0 2 a)) B) (in (skS.0 2 a) B)))) True % 3.59/3.76 Clause #23 (by clausification #[22]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (And (disjoint (singleton (skS.0 2 a)) B) (in (skS.0 2 a) B))) False % 3.59/3.76 Clause #24 (by clausification #[23]): ∀ (a a_1 : Iota), % 3.59/3.76 Eq (Not (Not (And (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (in (skS.0 2 a) (skS.0 3 a a_1))))) True % 3.59/3.76 Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota), % 3.59/3.76 Eq (Not (And (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (in (skS.0 2 a) (skS.0 3 a a_1)))) False % 3.59/3.76 Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Eq (And (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (in (skS.0 2 a) (skS.0 3 a a_1))) True % 3.59/3.76 Clause #27 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True % 3.59/3.76 Clause #28 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True % 3.59/3.76 Clause #30 (by superposition #[28, 20]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) False) % 3.59/3.76 Clause #33 (by clausification #[30]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) False % 3.59/3.76 Clause #34 (by superposition #[33, 27]): Eq False True % 3.59/3.76 Clause #35 (by clausification #[34]): False % 3.59/3.76 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------