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Otter---3.3.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET933+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:14:33 EDT 2022

% Result   : Theorem 1.76s 1.94s
% Output   : Refutation 1.76s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    8 (   6 unt;   0 nHn;   4 RR)
%            Number of literals    :   11 (   2 equ;   4 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   1 con; 0-1 aty)
%            Number of variables   :    9 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    ( A != powerset(B)
    | in(C,A)
    | ~ subset(C,B) ),
    file('SET933+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( subset(singleton(A),B)
    | ~ in(A,B) ),
    file('SET933+1.p',unknown),
    [] ).

cnf(8,axiom,
    ~ subset(singleton(dollar_c3),powerset(dollar_c3)),
    file('SET933+1.p',unknown),
    [] ).

cnf(10,axiom,
    A = A,
    file('SET933+1.p',unknown),
    [] ).

cnf(13,axiom,
    subset(A,A),
    file('SET933+1.p',unknown),
    [] ).

cnf(16,plain,
    in(A,powerset(A)),
    inference(hyper,[status(thm)],[13,3,10]),
    [iquote('hyper,13,3,10')] ).

cnf(18,plain,
    subset(singleton(A),powerset(A)),
    inference(hyper,[status(thm)],[16,6]),
    [iquote('hyper,16,6')] ).

cnf(19,plain,
    $false,
    inference(binary,[status(thm)],[18,8]),
    [iquote('binary,18.1,8.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13  % Problem  : SET933+1 : TPTP v8.1.0. Released v3.2.0.
% 0.04/0.13  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n021.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 10:21:23 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.76/1.94  ----- Otter 3.3f, August 2004 -----
% 1.76/1.94  The process was started by sandbox2 on n021.cluster.edu,
% 1.76/1.94  Wed Jul 27 10:21:23 2022
% 1.76/1.94  The command was "./otter".  The process ID is 12820.
% 1.76/1.94  
% 1.76/1.94  set(prolog_style_variables).
% 1.76/1.94  set(auto).
% 1.76/1.94     dependent: set(auto1).
% 1.76/1.94     dependent: set(process_input).
% 1.76/1.94     dependent: clear(print_kept).
% 1.76/1.94     dependent: clear(print_new_demod).
% 1.76/1.94     dependent: clear(print_back_demod).
% 1.76/1.94     dependent: clear(print_back_sub).
% 1.76/1.94     dependent: set(control_memory).
% 1.76/1.94     dependent: assign(max_mem, 12000).
% 1.76/1.94     dependent: assign(pick_given_ratio, 4).
% 1.76/1.94     dependent: assign(stats_level, 1).
% 1.76/1.94     dependent: assign(max_seconds, 10800).
% 1.76/1.94  clear(print_given).
% 1.76/1.94  
% 1.76/1.94  formula_list(usable).
% 1.76/1.94  all A (A=A).
% 1.76/1.94  all A B (in(A,B)-> -in(B,A)).
% 1.76/1.94  all A B (B=powerset(A)<-> (all C (in(C,B)<->subset(C,A)))).
% 1.76/1.94  all A B (subset(singleton(A),B)<->in(A,B)).
% 1.76/1.94  exists A empty(A).
% 1.76/1.94  exists A (-empty(A)).
% 1.76/1.94  all A B subset(A,A).
% 1.76/1.94  -(all A subset(singleton(A),powerset(A))).
% 1.76/1.94  end_of_list.
% 1.76/1.94  
% 1.76/1.94  -------> usable clausifies to:
% 1.76/1.94  
% 1.76/1.94  list(usable).
% 1.76/1.94  0 [] A=A.
% 1.76/1.94  0 [] -in(A,B)| -in(B,A).
% 1.76/1.94  0 [] B!=powerset(A)| -in(C,B)|subset(C,A).
% 1.76/1.94  0 [] B!=powerset(A)|in(C,B)| -subset(C,A).
% 1.76/1.94  0 [] B=powerset(A)|in($f1(A,B),B)|subset($f1(A,B),A).
% 1.76/1.94  0 [] B=powerset(A)| -in($f1(A,B),B)| -subset($f1(A,B),A).
% 1.76/1.94  0 [] -subset(singleton(A),B)|in(A,B).
% 1.76/1.94  0 [] subset(singleton(A),B)| -in(A,B).
% 1.76/1.94  0 [] empty($c1).
% 1.76/1.94  0 [] -empty($c2).
% 1.76/1.94  0 [] subset(A,A).
% 1.76/1.94  0 [] -subset(singleton($c3),powerset($c3)).
% 1.76/1.94  end_of_list.
% 1.76/1.94  
% 1.76/1.94  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 1.76/1.94  
% 1.76/1.94  This ia a non-Horn set with equality.  The strategy will be
% 1.76/1.94  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.76/1.94  deletion, with positive clauses in sos and nonpositive
% 1.76/1.94  clauses in usable.
% 1.76/1.94  
% 1.76/1.94     dependent: set(knuth_bendix).
% 1.76/1.94     dependent: set(anl_eq).
% 1.76/1.94     dependent: set(para_from).
% 1.76/1.94     dependent: set(para_into).
% 1.76/1.94     dependent: clear(para_from_right).
% 1.76/1.94     dependent: clear(para_into_right).
% 1.76/1.94     dependent: set(para_from_vars).
% 1.76/1.94     dependent: set(eq_units_both_ways).
% 1.76/1.94     dependent: set(dynamic_demod_all).
% 1.76/1.94     dependent: set(dynamic_demod).
% 1.76/1.94     dependent: set(order_eq).
% 1.76/1.94     dependent: set(back_demod).
% 1.76/1.94     dependent: set(lrpo).
% 1.76/1.94     dependent: set(hyper_res).
% 1.76/1.94     dependent: set(unit_deletion).
% 1.76/1.94     dependent: set(factor).
% 1.76/1.94  
% 1.76/1.94  ------------> process usable:
% 1.76/1.94  ** KEPT (pick-wt=6): 1 [] -in(A,B)| -in(B,A).
% 1.76/1.94  ** KEPT (pick-wt=10): 2 [] A!=powerset(B)| -in(C,A)|subset(C,B).
% 1.76/1.94  ** KEPT (pick-wt=10): 3 [] A!=powerset(B)|in(C,A)| -subset(C,B).
% 1.76/1.94  ** KEPT (pick-wt=14): 4 [] A=powerset(B)| -in($f1(B,A),A)| -subset($f1(B,A),B).
% 1.76/1.94  ** KEPT (pick-wt=7): 5 [] -subset(singleton(A),B)|in(A,B).
% 1.76/1.94  ** KEPT (pick-wt=7): 6 [] subset(singleton(A),B)| -in(A,B).
% 1.76/1.94  ** KEPT (pick-wt=2): 7 [] -empty($c2).
% 1.76/1.94  ** KEPT (pick-wt=5): 8 [] -subset(singleton($c3),powerset($c3)).
% 1.76/1.94  
% 1.76/1.94  ------------> process sos:
% 1.76/1.94  ** KEPT (pick-wt=3): 10 [] A=A.
% 1.76/1.94  ** KEPT (pick-wt=14): 11 [] A=powerset(B)|in($f1(B,A),A)|subset($f1(B,A),B).
% 1.76/1.94  ** KEPT (pick-wt=2): 12 [] empty($c1).
% 1.76/1.94  ** KEPT (pick-wt=3): 13 [] subset(A,A).
% 1.76/1.94    Following clause subsumed by 10 during input processing: 0 [copy,10,flip.1] A=A.
% 1.76/1.94  
% 1.76/1.94  ======= end of input processing =======
% 1.76/1.94  
% 1.76/1.94  =========== start of search ===========
% 1.76/1.94  
% 1.76/1.94  -------- PROOF -------- 
% 1.76/1.94  
% 1.76/1.94  ----> UNIT CONFLICT at   0.00 sec ----> 19 [binary,18.1,8.1] $F.
% 1.76/1.94  
% 1.76/1.94  Length of proof is 2.  Level of proof is 2.
% 1.76/1.94  
% 1.76/1.94  ---------------- PROOF ----------------
% 1.76/1.94  % SZS status Theorem
% 1.76/1.94  % SZS output start Refutation
% See solution above
% 1.76/1.94  ------------ end of proof -------------
% 1.76/1.94  
% 1.76/1.94  
% 1.76/1.94  Search stopped by max_proofs option.
% 1.76/1.94  
% 1.76/1.94  
% 1.76/1.94  Search stopped by max_proofs option.
% 1.76/1.94  
% 1.76/1.94  ============ end of search ============
% 1.76/1.94  
% 1.76/1.94  -------------- statistics -------------
% 1.76/1.94  clauses given                  5
% 1.76/1.94  clauses generated              7
% 1.76/1.94  clauses kept                  18
% 1.76/1.94  clauses forward subsumed       2
% 1.76/1.94  clauses back subsumed          0
% 1.76/1.94  Kbytes malloced              976
% 1.76/1.94  
% 1.76/1.94  ----------- times (seconds) -----------
% 1.76/1.94  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.76/1.94  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.76/1.94  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.76/1.94  
% 1.76/1.94  That finishes the proof of the theorem.
% 1.76/1.94  
% 1.76/1.94  Process 12820 finished Wed Jul 27 10:21:25 2022
% 1.76/1.94  Otter interrupted
% 1.76/1.94  PROOF FOUND
%------------------------------------------------------------------------------