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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU121+1 : TPTP v9.2.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:00:54 PM UTC 2025

% Result   : Theorem 5.33s 5.48s
% Output   : Proof 5.35s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.02/0.11  % Problem    : SEU121+1 : TPTP v9.2.0. Released v3.3.0.
% 0.02/0.12  % Command    : duper %s
% 0.10/0.31  % Computer : n015.cluster.edu
% 0.10/0.31  % Model    : x86_64 x86_64
% 0.10/0.31  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.31  % Memory   : 8042.1875MB
% 0.10/0.31  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.32  % CPULimit   : 300
% 0.10/0.32  % WCLimit    : 300
% 0.10/0.32  % DateTime   : Fri Oct  3 06:37:53 EDT 2025
% 0.10/0.32  % CPUTime    : 
% 5.33/5.48  SZS status Theorem for theBenchmark.p
% 5.33/5.48  SZS output start Proof for theBenchmark.p
% 5.33/5.48  Clause #1 (by assumption #[]): Eq (∀ (A B : Iota), Iff (subset A B) (∀ (C : Iota), in C A → in C B)) True
% 5.33/5.48  Clause #7 (by assumption #[]): Eq (Not (∀ (A B C : Iota), And (subset A B) (subset B C) → subset A C)) True
% 5.33/5.48  Clause #27 (by clausification #[7]): Eq (∀ (A B C : Iota), And (subset A B) (subset B C) → subset A C) False
% 5.33/5.48  Clause #28 (by clausification #[27]): ∀ (a : Iota), Eq (Not (∀ (B C : Iota), And (subset (skS.0 2 a) B) (subset B C) → subset (skS.0 2 a) C)) True
% 5.33/5.48  Clause #29 (by clausification #[28]): ∀ (a : Iota), Eq (∀ (B C : Iota), And (subset (skS.0 2 a) B) (subset B C) → subset (skS.0 2 a) C) False
% 5.33/5.48  Clause #30 (by clausification #[29]): ∀ (a a_1 : Iota),
% 5.33/5.48    Eq (Not (∀ (C : Iota), And (subset (skS.0 2 a) (skS.0 3 a a_1)) (subset (skS.0 3 a a_1) C) → subset (skS.0 2 a) C))
% 5.33/5.48      True
% 5.33/5.48  Clause #31 (by clausification #[30]): ∀ (a a_1 : Iota),
% 5.33/5.48    Eq (∀ (C : Iota), And (subset (skS.0 2 a) (skS.0 3 a a_1)) (subset (skS.0 3 a a_1) C) → subset (skS.0 2 a) C) False
% 5.33/5.48  Clause #32 (by clausification #[31]): ∀ (a a_1 a_2 : Iota),
% 5.33/5.48    Eq
% 5.33/5.48      (Not
% 5.33/5.48        (And (subset (skS.0 2 a) (skS.0 3 a a_1)) (subset (skS.0 3 a a_1) (skS.0 4 a a_1 a_2)) →
% 5.33/5.48          subset (skS.0 2 a) (skS.0 4 a a_1 a_2)))
% 5.33/5.48      True
% 5.33/5.48  Clause #33 (by clausification #[32]): ∀ (a a_1 a_2 : Iota),
% 5.33/5.48    Eq
% 5.33/5.48      (And (subset (skS.0 2 a) (skS.0 3 a a_1)) (subset (skS.0 3 a a_1) (skS.0 4 a a_1 a_2)) →
% 5.33/5.48        subset (skS.0 2 a) (skS.0 4 a a_1 a_2))
% 5.33/5.48      False
% 5.33/5.48  Clause #34 (by clausification #[33]): ∀ (a a_1 a_2 : Iota), Eq (And (subset (skS.0 2 a) (skS.0 3 a a_1)) (subset (skS.0 3 a a_1) (skS.0 4 a a_1 a_2))) True
% 5.33/5.48  Clause #35 (by clausification #[33]): ∀ (a a_1 a_2 : Iota), Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) False
% 5.33/5.48  Clause #36 (by clausification #[34]): ∀ (a a_1 a_2 : Iota), Eq (subset (skS.0 3 a a_1) (skS.0 4 a a_1 a_2)) True
% 5.33/5.48  Clause #37 (by clausification #[34]): ∀ (a a_1 : Iota), Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) True
% 5.33/5.48  Clause #43 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset a B) (∀ (C : Iota), in C a → in C B)) True
% 5.33/5.48  Clause #44 (by clausification #[43]): ∀ (a a_1 : Iota), Eq (Iff (subset a a_1) (∀ (C : Iota), in C a → in C a_1)) True
% 5.33/5.48  Clause #45 (by clausification #[44]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) True) (Eq (∀ (C : Iota), in C a → in C a_1) False)
% 5.33/5.48  Clause #46 (by clausification #[44]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (∀ (C : Iota), in C a → in C a_1) True)
% 5.33/5.48  Clause #47 (by clausification #[45]): ∀ (a a_1 a_2 : Iota),
% 5.33/5.48    Or (Eq (subset a a_1) True) (Eq (Not (in (skS.0 5 a a_1 a_2) a → in (skS.0 5 a a_1 a_2) a_1)) True)
% 5.33/5.48  Clause #48 (by clausification #[47]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 5 a a_1 a_2) a → in (skS.0 5 a a_1 a_2) a_1) False)
% 5.33/5.48  Clause #49 (by clausification #[48]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 5 a a_1 a_2) a) True)
% 5.33/5.48  Clause #50 (by clausification #[48]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 5 a a_1 a_2) a_1) False)
% 5.33/5.48  Clause #56 (by clausification #[46]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) False) (Eq (in a_2 a → in a_2 a_1) True)
% 5.33/5.48  Clause #57 (by clausification #[56]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) False) (Or (Eq (in a_2 a) False) (Eq (in a_2 a_1) True))
% 5.33/5.48  Clause #58 (by superposition #[57, 36]): ∀ (a a_1 a_2 a_3 : Iota),
% 5.33/5.48    Or (Eq (in a (skS.0 3 a_1 a_2)) False) (Or (Eq (in a (skS.0 4 a_1 a_2 a_3)) True) (Eq False True))
% 5.33/5.48  Clause #71 (by superposition #[37, 57]): ∀ (a a_1 a_2 : Iota), Or (Eq (in a (skS.0 2 a_1)) False) (Or (Eq (in a (skS.0 3 a_1 a_2)) True) (Eq False True))
% 5.33/5.48  Clause #78 (by clausification #[71]): ∀ (a a_1 a_2 : Iota), Or (Eq (in a (skS.0 2 a_1)) False) (Eq (in a (skS.0 3 a_1 a_2)) True)
% 5.33/5.48  Clause #79 (by superposition #[78, 49]): ∀ (a a_1 a_2 a_3 : Iota),
% 5.33/5.48    Or (Eq (in (skS.0 5 (skS.0 2 a) a_1 a_2) (skS.0 3 a a_3)) True)
% 5.33/5.48      (Or (Eq (subset (skS.0 2 a) a_1) True) (Eq False True))
% 5.33/5.48  Clause #80 (by clausification #[58]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq (in a (skS.0 3 a_1 a_2)) False) (Eq (in a (skS.0 4 a_1 a_2 a_3)) True)
% 5.35/5.50  Clause #82 (by clausification #[79]): ∀ (a a_1 a_2 a_3 : Iota),
% 5.35/5.50    Or (Eq (in (skS.0 5 (skS.0 2 a) a_1 a_2) (skS.0 3 a a_3)) True) (Eq (subset (skS.0 2 a) a_1) True)
% 5.35/5.50  Clause #83 (by superposition #[82, 80]): ∀ (a a_1 a_2 a_3 a_4 : Iota),
% 5.35/5.50    Or (Eq (subset (skS.0 2 a) a_1) True)
% 5.35/5.50      (Or (Eq True False) (Eq (in (skS.0 5 (skS.0 2 a) a_1 a_2) (skS.0 4 a a_3 a_4)) True))
% 5.35/5.50  Clause #95 (by clausification #[83]): ∀ (a a_1 a_2 a_3 a_4 : Iota),
% 5.35/5.50    Or (Eq (subset (skS.0 2 a) a_1) True) (Eq (in (skS.0 5 (skS.0 2 a) a_1 a_2) (skS.0 4 a a_3 a_4)) True)
% 5.35/5.50  Clause #96 (by superposition #[95, 50]): ∀ (a a_1 a_2 : Iota),
% 5.35/5.50    Or (Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) True)
% 5.35/5.50      (Or (Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) True) (Eq True False))
% 5.35/5.50  Clause #102 (by clausification #[96]): ∀ (a a_1 a_2 : Iota),
% 5.35/5.50    Or (Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) True) (Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) True)
% 5.35/5.50  Clause #103 (by eliminate duplicate literals #[102]): ∀ (a a_1 a_2 : Iota), Eq (subset (skS.0 2 a) (skS.0 4 a a_1 a_2)) True
% 5.35/5.50  Clause #104 (by superposition #[103, 35]): Eq True False
% 5.35/5.50  Clause #106 (by clausification #[104]): False
% 5.35/5.50  SZS output end Proof for theBenchmark.p
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