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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU884^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:02:35 PM UTC 2025

% Result   : Theorem 3.73s 3.92s
% Output   : Proof 3.73s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SEU884^5 : TPTP v9.2.0. Released v4.0.0.
% 0.07/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n013.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Fri Oct  3 05:09:38 EDT 2025
% 0.13/0.35  % CPUTime    : 
% 3.73/3.92  SZS status Theorem for theBenchmark.p
% 3.73/3.92  SZS output start Proof for theBenchmark.p
% 3.73/3.92  Clause #0 (by assumption #[]): Eq
% 3.73/3.92    (Not
% 3.73/3.92      ((∀ (Xx : a), (Exists fun Xt => And (cR Xt) (Eq Xx Xt)) → Exists fun Xt => And (cS Xt) (Eq Xx Xt)) →
% 3.73/3.92        ∀ (Xx : a), cR Xx → cS Xx))
% 3.73/3.92    True
% 3.73/3.92  Clause #1 (by clausification #[0]): Eq
% 3.73/3.92    ((∀ (Xx : a), (Exists fun Xt => And (cR Xt) (Eq Xx Xt)) → Exists fun Xt => And (cS Xt) (Eq Xx Xt)) →
% 3.73/3.92      ∀ (Xx : a), cR Xx → cS Xx)
% 3.73/3.92    False
% 3.73/3.92  Clause #2 (by clausification #[1]): Eq (∀ (Xx : a), (Exists fun Xt => And (cR Xt) (Eq Xx Xt)) → Exists fun Xt => And (cS Xt) (Eq Xx Xt)) True
% 3.73/3.92  Clause #3 (by clausification #[1]): Eq (∀ (Xx : a), cR Xx → cS Xx) False
% 3.73/3.92  Clause #4 (by clausification #[2]): ∀ (a_1 : a), Eq ((Exists fun Xt => And (cR Xt) (Eq a_1 Xt)) → Exists fun Xt => And (cS Xt) (Eq a_1 Xt)) True
% 3.73/3.92  Clause #5 (by clausification #[4]): ∀ (a_1 : a),
% 3.73/3.92    Or (Eq (Exists fun Xt => And (cR Xt) (Eq a_1 Xt)) False) (Eq (Exists fun Xt => And (cS Xt) (Eq a_1 Xt)) True)
% 3.73/3.92  Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : a), Or (Eq (Exists fun Xt => And (cS Xt) (Eq a_1 Xt)) True) (Eq (And (cR a_2) (Eq a_1 a_2)) False)
% 3.73/3.92  Clause #7 (by clausification #[6]): ∀ (a_1 a_2 a_3 : a),
% 3.73/3.92    Or (Eq (And (cR a_1) (Eq a_2 a_1)) False) (Eq (And (cS (skS.0 0 a_2 a_3)) (Eq a_2 (skS.0 0 a_2 a_3))) True)
% 3.73/3.92  Clause #8 (by clausification #[7]): ∀ (a_1 a_2 a_3 : a),
% 3.73/3.92    Or (Eq (And (cS (skS.0 0 a_1 a_2)) (Eq a_1 (skS.0 0 a_1 a_2))) True) (Or (Eq (cR a_3) False) (Eq (Eq a_1 a_3) False))
% 3.73/3.92  Clause #9 (by clausification #[8]): ∀ (a_1 a_2 a_3 : a), Or (Eq (cR a_1) False) (Or (Eq (Eq a_2 a_1) False) (Eq (Eq a_2 (skS.0 0 a_2 a_3)) True))
% 3.73/3.92  Clause #10 (by clausification #[8]): ∀ (a_1 a_2 a_3 : a), Or (Eq (cR a_1) False) (Or (Eq (Eq a_2 a_1) False) (Eq (cS (skS.0 0 a_2 a_3)) True))
% 3.73/3.92  Clause #11 (by clausification #[9]): ∀ (a_1 a_2 a_3 : a), Or (Eq (cR a_1) False) (Or (Eq (Eq a_2 (skS.0 0 a_2 a_3)) True) (Ne a_2 a_1))
% 3.73/3.92  Clause #12 (by clausification #[11]): ∀ (a_1 a_2 a_3 : a), Or (Eq (cR a_1) False) (Or (Ne a_2 a_1) (Eq a_2 (skS.0 0 a_2 a_3)))
% 3.73/3.92  Clause #13 (by destructive equality resolution #[12]): ∀ (a_1 a_2 : a), Or (Eq (cR a_1) False) (Eq a_1 (skS.0 0 a_1 a_2))
% 3.73/3.92  Clause #14 (by clausification #[3]): ∀ (a_1 : a), Eq (Not (cR (skS.0 1 a_1) → cS (skS.0 1 a_1))) True
% 3.73/3.92  Clause #15 (by clausification #[14]): ∀ (a_1 : a), Eq (cR (skS.0 1 a_1) → cS (skS.0 1 a_1)) False
% 3.73/3.92  Clause #16 (by clausification #[15]): ∀ (a_1 : a), Eq (cR (skS.0 1 a_1)) True
% 3.73/3.92  Clause #17 (by clausification #[15]): ∀ (a_1 : a), Eq (cS (skS.0 1 a_1)) False
% 3.73/3.92  Clause #18 (by superposition #[16, 13]): ∀ (a_1 a_2 : a), Or (Eq True False) (Eq (skS.0 1 a_1) (skS.0 0 (skS.0 1 a_1) a_2))
% 3.73/3.92  Clause #19 (by clausification #[10]): ∀ (a_1 a_2 a_3 : a), Or (Eq (cR a_1) False) (Or (Eq (cS (skS.0 0 a_2 a_3)) True) (Ne a_2 a_1))
% 3.73/3.92  Clause #20 (by destructive equality resolution #[19]): ∀ (a_1 a_2 : a), Or (Eq (cR a_1) False) (Eq (cS (skS.0 0 a_1 a_2)) True)
% 3.73/3.92  Clause #21 (by superposition #[20, 16]): ∀ (a_1 a_2 : a), Or (Eq (cS (skS.0 0 (skS.0 1 a_1) a_2)) True) (Eq False True)
% 3.73/3.92  Clause #22 (by clausification #[21]): ∀ (a_1 a_2 : a), Eq (cS (skS.0 0 (skS.0 1 a_1) a_2)) True
% 3.73/3.92  Clause #23 (by clausification #[18]): ∀ (a_1 a_2 : a), Eq (skS.0 1 a_1) (skS.0 0 (skS.0 1 a_1) a_2)
% 3.73/3.92  Clause #24 (by backward demodulation #[23, 22]): ∀ (a_1 : a), Eq (cS (skS.0 1 a_1)) True
% 3.73/3.92  Clause #25 (by superposition #[24, 17]): Eq True False
% 3.73/3.92  Clause #26 (by clausification #[25]): False
% 3.73/3.92  SZS output end Proof for theBenchmark.p
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