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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU886^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:02:35 PM UTC 2025

% Result   : Theorem 3.77s 4.00s
% Output   : Proof 3.77s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SEU886^5 : TPTP v9.2.0. Released v4.0.0.
% 0.11/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n003.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Fri Oct  3 04:19:23 EDT 2025
% 0.13/0.35  % CPUTime    : 
% 3.77/4.00  SZS status Theorem for theBenchmark.p
% 3.77/4.00  SZS output start Proof for theBenchmark.p
% 3.77/4.00  Clause #0 (by assumption #[]): Eq
% 3.77/4.00    (Not
% 3.77/4.00      (∀ (Xx0 : a),
% 3.77/4.00        (Exists fun Xt => And (And (x Xt) (y Xt)) (Eq Xx0 (f Xt))) →
% 3.77/4.00          And (Exists fun Xt => And (x Xt) (Eq Xx0 (f Xt))) (Exists fun Xt => And (y Xt) (Eq Xx0 (f Xt)))))
% 3.77/4.00    True
% 3.77/4.00  Clause #1 (by clausification #[0]): Eq
% 3.77/4.00    (∀ (Xx0 : a),
% 3.77/4.00      (Exists fun Xt => And (And (x Xt) (y Xt)) (Eq Xx0 (f Xt))) →
% 3.77/4.00        And (Exists fun Xt => And (x Xt) (Eq Xx0 (f Xt))) (Exists fun Xt => And (y Xt) (Eq Xx0 (f Xt))))
% 3.77/4.00    False
% 3.77/4.00  Clause #2 (by clausification #[1]): ∀ (a_1 : a),
% 3.77/4.00    Eq
% 3.77/4.00      (Not
% 3.77/4.00        ((Exists fun Xt => And (And (x Xt) (y Xt)) (Eq (skS.0 0 a_1) (f Xt))) →
% 3.77/4.00          And (Exists fun Xt => And (x Xt) (Eq (skS.0 0 a_1) (f Xt)))
% 3.77/4.00            (Exists fun Xt => And (y Xt) (Eq (skS.0 0 a_1) (f Xt)))))
% 3.77/4.00      True
% 3.77/4.00  Clause #3 (by clausification #[2]): ∀ (a_1 : a),
% 3.77/4.00    Eq
% 3.77/4.00      ((Exists fun Xt => And (And (x Xt) (y Xt)) (Eq (skS.0 0 a_1) (f Xt))) →
% 3.77/4.00        And (Exists fun Xt => And (x Xt) (Eq (skS.0 0 a_1) (f Xt)))
% 3.77/4.00          (Exists fun Xt => And (y Xt) (Eq (skS.0 0 a_1) (f Xt))))
% 3.77/4.00      False
% 3.77/4.00  Clause #4 (by clausification #[3]): ∀ (a_1 : a), Eq (Exists fun Xt => And (And (x Xt) (y Xt)) (Eq (skS.0 0 a_1) (f Xt))) True
% 3.77/4.00  Clause #5 (by clausification #[3]): ∀ (a_1 : a),
% 3.77/4.00    Eq
% 3.77/4.00      (And (Exists fun Xt => And (x Xt) (Eq (skS.0 0 a_1) (f Xt)))
% 3.77/4.00        (Exists fun Xt => And (y Xt) (Eq (skS.0 0 a_1) (f Xt))))
% 3.77/4.00      False
% 3.77/4.00  Clause #6 (by clausification #[4]): ∀ (a_1 : a) (a_2 : b),
% 3.77/4.00    Eq (And (And (x (skS.0 1 a_1 a_2)) (y (skS.0 1 a_1 a_2))) (Eq (skS.0 0 a_1) (f (skS.0 1 a_1 a_2)))) True
% 3.77/4.00  Clause #7 (by clausification #[6]): ∀ (a_1 : a) (a_2 : b), Eq (Eq (skS.0 0 a_1) (f (skS.0 1 a_1 a_2))) True
% 3.77/4.00  Clause #8 (by clausification #[6]): ∀ (a_1 : a) (a_2 : b), Eq (And (x (skS.0 1 a_1 a_2)) (y (skS.0 1 a_1 a_2))) True
% 3.77/4.00  Clause #9 (by clausification #[7]): ∀ (a_1 : a) (a_2 : b), Eq (skS.0 0 a_1) (f (skS.0 1 a_1 a_2))
% 3.77/4.00  Clause #10 (by clausification #[8]): ∀ (a_1 : a) (a_2 : b), Eq (y (skS.0 1 a_1 a_2)) True
% 3.77/4.00  Clause #11 (by clausification #[8]): ∀ (a_1 : a) (a_2 : b), Eq (x (skS.0 1 a_1 a_2)) True
% 3.77/4.00  Clause #12 (by clausification #[5]): ∀ (a_1 : a),
% 3.77/4.00    Or (Eq (Exists fun Xt => And (x Xt) (Eq (skS.0 0 a_1) (f Xt))) False)
% 3.77/4.00      (Eq (Exists fun Xt => And (y Xt) (Eq (skS.0 0 a_1) (f Xt))) False)
% 3.77/4.00  Clause #13 (by clausification #[12]): ∀ (a_1 : a) (a_2 : b),
% 3.77/4.00    Or (Eq (Exists fun Xt => And (y Xt) (Eq (skS.0 0 a_1) (f Xt))) False)
% 3.77/4.00      (Eq (And (x a_2) (Eq (skS.0 0 a_1) (f a_2))) False)
% 3.77/4.00  Clause #14 (by clausification #[13]): ∀ (a_1 : b) (a_2 : a) (a_3 : b),
% 3.77/4.00    Or (Eq (And (x a_1) (Eq (skS.0 0 a_2) (f a_1))) False) (Eq (And (y a_3) (Eq (skS.0 0 a_2) (f a_3))) False)
% 3.77/4.00  Clause #15 (by clausification #[14]): ∀ (a_1 : b) (a_2 : a) (a_3 : b),
% 3.77/4.00    Or (Eq (And (y a_1) (Eq (skS.0 0 a_2) (f a_1))) False) (Or (Eq (x a_3) False) (Eq (Eq (skS.0 0 a_2) (f a_3)) False))
% 3.77/4.00  Clause #16 (by clausification #[15]): ∀ (a_1 : b) (a_2 : a) (a_3 : b),
% 3.77/4.00    Or (Eq (x a_1) False)
% 3.77/4.00      (Or (Eq (Eq (skS.0 0 a_2) (f a_1)) False) (Or (Eq (y a_3) False) (Eq (Eq (skS.0 0 a_2) (f a_3)) False)))
% 3.77/4.00  Clause #17 (by clausification #[16]): ∀ (a_1 a_2 : b) (a_3 : a),
% 3.77/4.00    Or (Eq (x a_1) False) (Or (Eq (y a_2) False) (Or (Eq (Eq (skS.0 0 a_3) (f a_2)) False) (Ne (skS.0 0 a_3) (f a_1))))
% 3.77/4.00  Clause #18 (by clausification #[17]): ∀ (a_1 a_2 : b) (a_3 : a),
% 3.77/4.00    Or (Eq (x a_1) False) (Or (Eq (y a_2) False) (Or (Ne (skS.0 0 a_3) (f a_1)) (Ne (skS.0 0 a_3) (f a_2))))
% 3.77/4.00  Clause #19 (by superposition #[18, 11]): ∀ (a_1 : b) (a_2 a_3 : a) (a_4 : b),
% 3.77/4.00    Or (Eq (y a_1) False) (Or (Ne (skS.0 0 a_2) (f (skS.0 1 a_3 a_4))) (Or (Ne (skS.0 0 a_2) (f a_1)) (Eq False True)))
% 3.77/4.00  Clause #20 (by clausification #[19]): ∀ (a_1 : b) (a_2 a_3 : a) (a_4 : b),
% 3.77/4.00    Or (Eq (y a_1) False) (Or (Ne (skS.0 0 a_2) (f (skS.0 1 a_3 a_4))) (Ne (skS.0 0 a_2) (f a_1)))
% 3.77/4.00  Clause #21 (by forward demodulation #[20, 9]): ∀ (a_1 : b) (a_2 a_3 : a), Or (Eq (y a_1) False) (Or (Ne (skS.0 0 a_2) (skS.0 0 a_3)) (Ne (skS.0 0 a_2) (f a_1)))
% 3.77/4.00  Clause #22 (by superposition #[21, 10]): ∀ (a_1 a_2 a_3 : a) (a_4 : b),
% 3.77/4.00    Or (Ne (skS.0 0 a_1) (skS.0 0 a_2)) (Or (Ne (skS.0 0 a_1) (f (skS.0 1 a_3 a_4))) (Eq False True))
% 3.77/4.00  Clause #23 (by clausification #[22]): ∀ (a_1 a_2 a_3 : a) (a_4 : b), Or (Ne (skS.0 0 a_1) (skS.0 0 a_2)) (Ne (skS.0 0 a_1) (f (skS.0 1 a_3 a_4)))
% 3.77/4.00  Clause #24 (by forward demodulation #[23, 9]): ∀ (a_1 a_2 a_3 : a), Or (Ne (skS.0 0 a_1) (skS.0 0 a_2)) (Ne (skS.0 0 a_1) (skS.0 0 a_3))
% 3.77/4.00  Clause #25 (by equality resolution #[24]): ∀ (a_1 a_2 : a), Ne (skS.0 0 a_1) (skS.0 0 a_2)
% 3.77/4.00  Clause #26 (by equality resolution #[25]): False
% 3.77/4.00  SZS output end Proof for theBenchmark.p
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