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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU889^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:02:36 PM UTC 2025

% Result   : Theorem 4.02s 4.20s
% Output   : Proof 4.02s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem    : SEU889^5 : TPTP v9.2.0. Released v4.0.0.
% 0.07/0.14  % Command    : duper %s
% 0.15/0.35  % Computer : n021.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35  % CPULimit   : 300
% 0.15/0.35  % WCLimit    : 300
% 0.15/0.35  % DateTime   : Fri Oct  3 05:02:08 EDT 2025
% 0.15/0.36  % CPUTime    : 
% 4.02/4.20  SZS status Theorem for theBenchmark.p
% 4.02/4.20  SZS output start Proof for theBenchmark.p
% 4.02/4.20  Clause #0 (by assumption #[]): Eq
% 4.02/4.20    (Not
% 4.02/4.20      (∀ (Xx : a),
% 4.02/4.20        (Exists fun Xt => And (Exists fun Xt0 => And (cS Xt0) (Eq Xt (cG Xt0))) (Eq Xx (cF Xt))) →
% 4.02/4.20          Exists fun Xt => And (cS Xt) (Eq Xx (cF (cG Xt)))))
% 4.02/4.20    True
% 4.02/4.20  Clause #1 (by clausification #[0]): Eq
% 4.02/4.20    (∀ (Xx : a),
% 4.02/4.20      (Exists fun Xt => And (Exists fun Xt0 => And (cS Xt0) (Eq Xt (cG Xt0))) (Eq Xx (cF Xt))) →
% 4.02/4.20        Exists fun Xt => And (cS Xt) (Eq Xx (cF (cG Xt))))
% 4.02/4.20    False
% 4.02/4.20  Clause #2 (by clausification #[1]): ∀ (a_1 : a),
% 4.02/4.20    Eq
% 4.02/4.20      (Not
% 4.02/4.20        ((Exists fun Xt => And (Exists fun Xt0 => And (cS Xt0) (Eq Xt (cG Xt0))) (Eq (skS.0 0 a_1) (cF Xt))) →
% 4.02/4.20          Exists fun Xt => And (cS Xt) (Eq (skS.0 0 a_1) (cF (cG Xt)))))
% 4.02/4.20      True
% 4.02/4.20  Clause #3 (by clausification #[2]): ∀ (a_1 : a),
% 4.02/4.20    Eq
% 4.02/4.20      ((Exists fun Xt => And (Exists fun Xt0 => And (cS Xt0) (Eq Xt (cG Xt0))) (Eq (skS.0 0 a_1) (cF Xt))) →
% 4.02/4.20        Exists fun Xt => And (cS Xt) (Eq (skS.0 0 a_1) (cF (cG Xt))))
% 4.02/4.20      False
% 4.02/4.20  Clause #4 (by clausification #[3]): ∀ (a_1 : a), Eq (Exists fun Xt => And (Exists fun Xt0 => And (cS Xt0) (Eq Xt (cG Xt0))) (Eq (skS.0 0 a_1) (cF Xt))) True
% 4.02/4.20  Clause #5 (by clausification #[3]): ∀ (a_1 : a), Eq (Exists fun Xt => And (cS Xt) (Eq (skS.0 0 a_1) (cF (cG Xt)))) False
% 4.02/4.20  Clause #6 (by clausification #[4]): ∀ (a_1 : a) (a_2 : b),
% 4.02/4.20    Eq (And (Exists fun Xt0 => And (cS Xt0) (Eq (skS.0 1 a_1 a_2) (cG Xt0))) (Eq (skS.0 0 a_1) (cF (skS.0 1 a_1 a_2))))
% 4.02/4.20      True
% 4.02/4.20  Clause #7 (by clausification #[6]): ∀ (a_1 : a) (a_2 : b), Eq (Eq (skS.0 0 a_1) (cF (skS.0 1 a_1 a_2))) True
% 4.02/4.20  Clause #8 (by clausification #[6]): ∀ (a_1 : a) (a_2 : b), Eq (Exists fun Xt0 => And (cS Xt0) (Eq (skS.0 1 a_1 a_2) (cG Xt0))) True
% 4.02/4.20  Clause #9 (by clausification #[7]): ∀ (a_1 : a) (a_2 : b), Eq (skS.0 0 a_1) (cF (skS.0 1 a_1 a_2))
% 4.02/4.20  Clause #10 (by clausification #[5]): ∀ (a_1 : c) (a_2 : a), Eq (And (cS a_1) (Eq (skS.0 0 a_2) (cF (cG a_1)))) False
% 4.02/4.20  Clause #11 (by clausification #[10]): ∀ (a_1 : c) (a_2 : a), Or (Eq (cS a_1) False) (Eq (Eq (skS.0 0 a_2) (cF (cG a_1))) False)
% 4.02/4.20  Clause #12 (by clausification #[11]): ∀ (a_1 : c) (a_2 : a), Or (Eq (cS a_1) False) (Ne (skS.0 0 a_2) (cF (cG a_1)))
% 4.02/4.20  Clause #13 (by clausification #[8]): ∀ (a_1 : a) (a_2 : b) (a_3 : c),
% 4.02/4.20    Eq (And (cS (skS.0 2 a_1 a_2 a_3)) (Eq (skS.0 1 a_1 a_2) (cG (skS.0 2 a_1 a_2 a_3)))) True
% 4.02/4.20  Clause #14 (by clausification #[13]): ∀ (a_1 : a) (a_2 : b) (a_3 : c), Eq (Eq (skS.0 1 a_1 a_2) (cG (skS.0 2 a_1 a_2 a_3))) True
% 4.02/4.20  Clause #15 (by clausification #[13]): ∀ (a_1 : a) (a_2 : b) (a_3 : c), Eq (cS (skS.0 2 a_1 a_2 a_3)) True
% 4.02/4.20  Clause #16 (by clausification #[14]): ∀ (a_1 : a) (a_2 : b) (a_3 : c), Eq (skS.0 1 a_1 a_2) (cG (skS.0 2 a_1 a_2 a_3))
% 4.02/4.20  Clause #17 (by superposition #[15, 12]): ∀ (a_1 a_2 : a) (a_3 : b) (a_4 : c), Or (Eq True False) (Ne (skS.0 0 a_1) (cF (cG (skS.0 2 a_2 a_3 a_4))))
% 4.02/4.20  Clause #18 (by clausification #[17]): ∀ (a_1 a_2 : a) (a_3 : b) (a_4 : c), Ne (skS.0 0 a_1) (cF (cG (skS.0 2 a_2 a_3 a_4)))
% 4.02/4.20  Clause #19 (by forward demodulation #[18, 16]): ∀ (a_1 a_2 : a) (a_3 : b), Ne (skS.0 0 a_1) (cF (skS.0 1 a_2 a_3))
% 4.02/4.20  Clause #20 (by forward demodulation #[19, 9]): ∀ (a_1 a_2 : a), Ne (skS.0 0 a_1) (skS.0 0 a_2)
% 4.02/4.20  Clause #21 (by equality resolution #[20]): False
% 4.02/4.20  SZS output end Proof for theBenchmark.p
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