%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SEU923^5 : TPTP v6.1.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n105.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-431.20.3.el6.x86_64 % CPULimit : 300s % DateTime : Thu Jul 17 13:33:23 EDT 2014 % Result : Theorem 0.42s % Output : Proof 0.42s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----ERROR: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % % Problem : SEU923^5 : TPTP v6.1.0. Released v4.0.0. % % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % % Computer : n105.star.cs.uiowa.edu % % Model : x86_64 x86_64 % % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % % Memory : 32286.75MB % % OS : Linux 2.6.32-431.20.3.el6.x86_64 % % CPULimit : 300 % % DateTime : Thu Jul 17 11:42:56 CDT 2014 % % CPUTime : 0.42 % Python 2.7.5 % Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % FOF formula (<kernel.Constant object at 0x29ded88>, <kernel.Type object at 0x2984488>) of role type named b_type % Using role type % Declaring b:Type % FOF formula (<kernel.Constant object at 0x29de248>, <kernel.Type object at 0x2984488>) of role type named a_type % Using role type % Declaring a:Type % FOF formula (<kernel.Constant object at 0x29ded88>, <kernel.DependentProduct object at 0x2984950>) of role type named cF % Using role type % Declaring cF:(b->a) % FOF formula ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))) of role conjecture named cTHM54_pme % Conjecture to prove = ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))):Prop % Parameter b_DUMMY:b. % Parameter a_DUMMY:a. % We need to prove ['((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))'] % Parameter b:Type. % Parameter a:Type. % Parameter cF:(b->a). % Trying to prove ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))) % Found x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))) % Found (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) as proof of (forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))) % Found (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) as proof of ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))) % Got proof (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) % Time elapsed = 0.109077s % node=1 cost=2.000000 depth=1 % :::::::::::::::::::::: % % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) % % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % EOF %------------------------------------------------------------------------------