↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU941^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:02:40 PM UTC 2025

% Result   : Theorem 3.58s 3.77s
% Output   : Proof 3.63s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13  % Problem    : SEU941^5 : TPTP v9.2.0. Released v4.0.0.
% 0.14/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n017.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Oct  3 06:29:53 EDT 2025
% 0.14/0.35  % CPUTime    : 
% 3.58/3.77  SZS status Theorem for theBenchmark.p
% 3.58/3.77  SZS output start Proof for theBenchmark.p
% 3.58/3.77  Clause #0 (by assumption #[]): Eq
% 3.58/3.77    (Not
% 3.58/3.77      (∀ (F : a → b) (G : b → c),
% 3.58/3.77        And (∀ (Xx Xy : a), Eq (F Xx) (F Xy) → Eq Xx Xy) (∀ (Xx Xy : b), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.58/3.77          ∀ (Xx Xy : a), Eq (G (F Xx)) (G (F Xy)) → Eq Xx Xy))
% 3.58/3.77    True
% 3.58/3.77  Clause #1 (by clausification #[0]): Eq
% 3.58/3.77    (∀ (F : a → b) (G : b → c),
% 3.58/3.77      And (∀ (Xx Xy : a), Eq (F Xx) (F Xy) → Eq Xx Xy) (∀ (Xx Xy : b), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.58/3.77        ∀ (Xx Xy : a), Eq (G (F Xx)) (G (F Xy)) → Eq Xx Xy)
% 3.58/3.77    False
% 3.58/3.77  Clause #2 (by clausification #[1]): ∀ (a_1 : a → b),
% 3.58/3.77    Eq
% 3.58/3.77      (Not
% 3.58/3.77        (∀ (G : b → c),
% 3.58/3.77          And (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.58/3.77              (∀ (Xx Xy : b), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.58/3.77            ∀ (Xx Xy : a), Eq (G (skS.0 0 a_1 Xx)) (G (skS.0 0 a_1 Xy)) → Eq Xx Xy))
% 3.58/3.77      True
% 3.58/3.77  Clause #3 (by clausification #[2]): ∀ (a_1 : a → b),
% 3.58/3.77    Eq
% 3.58/3.77      (∀ (G : b → c),
% 3.58/3.77        And (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.58/3.77            (∀ (Xx Xy : b), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.58/3.77          ∀ (Xx Xy : a), Eq (G (skS.0 0 a_1 Xx)) (G (skS.0 0 a_1 Xy)) → Eq Xx Xy)
% 3.58/3.77      False
% 3.58/3.77  Clause #4 (by clausification #[3]): ∀ (a_1 : a → b) (a_2 : b → c),
% 3.58/3.77    Eq
% 3.58/3.77      (Not
% 3.58/3.77        (And (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.58/3.77            (∀ (Xx Xy : b), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) →
% 3.58/3.77          ∀ (Xx Xy : a), Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xx)) (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xy)) → Eq Xx Xy))
% 3.58/3.77      True
% 3.58/3.77  Clause #5 (by clausification #[4]): ∀ (a_1 : a → b) (a_2 : b → c),
% 3.58/3.77    Eq
% 3.58/3.77      (And (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.58/3.77          (∀ (Xx Xy : b), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) →
% 3.58/3.77        ∀ (Xx Xy : a), Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xx)) (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xy)) → Eq Xx Xy)
% 3.58/3.77      False
% 3.58/3.77  Clause #6 (by clausification #[5]): ∀ (a_1 : a → b) (a_2 : b → c),
% 3.58/3.77    Eq
% 3.58/3.77      (And (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.58/3.77        (∀ (Xx Xy : b), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy))
% 3.58/3.77      True
% 3.58/3.77  Clause #7 (by clausification #[5]): ∀ (a_1 : a → b) (a_2 : b → c),
% 3.58/3.77    Eq (∀ (Xx Xy : a), Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xx)) (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xy)) → Eq Xx Xy) False
% 3.58/3.77  Clause #8 (by clausification #[6]): ∀ (a_1 : a → b) (a_2 : b → c), Eq (∀ (Xx Xy : b), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) True
% 3.58/3.77  Clause #9 (by clausification #[6]): ∀ (a_1 : a → b), Eq (∀ (Xx Xy : a), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy) True
% 3.58/3.77  Clause #10 (by clausification #[8]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 : b), Eq (∀ (Xy : b), Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 Xy) → Eq a_3 Xy) True
% 3.58/3.77  Clause #11 (by clausification #[10]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : b), Eq (Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4) → Eq a_3 a_4) True
% 3.58/3.77  Clause #12 (by clausification #[11]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : b),
% 3.58/3.77    Or (Eq (Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4)) False) (Eq (Eq a_3 a_4) True)
% 3.58/3.77  Clause #13 (by clausification #[12]): ∀ (a_1 a_2 : b) (a_3 : a → b) (a_4 : b → c), Or (Eq (Eq a_1 a_2) True) (Ne (skS.0 1 a_3 a_4 a_1) (skS.0 1 a_3 a_4 a_2))
% 3.58/3.77  Clause #14 (by clausification #[13]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : b), Or (Ne (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4)) (Eq a_3 a_4)
% 3.58/3.77  Clause #16 (by clausification #[9]): ∀ (a_1 : a → b) (a_2 : a), Eq (∀ (Xy : a), Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 Xy) → Eq a_2 Xy) True
% 3.58/3.77  Clause #17 (by clausification #[16]): ∀ (a_1 : a → b) (a_2 a_3 : a), Eq (Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3) → Eq a_2 a_3) True
% 3.58/3.77  Clause #18 (by clausification #[17]): ∀ (a_1 : a → b) (a_2 a_3 : a), Or (Eq (Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3)) False) (Eq (Eq a_2 a_3) True)
% 3.58/3.77  Clause #19 (by clausification #[18]): ∀ (a_1 a_2 : a) (a_3 : a → b), Or (Eq (Eq a_1 a_2) True) (Ne (skS.0 0 a_3 a_1) (skS.0 0 a_3 a_2))
% 3.63/3.79  Clause #20 (by clausification #[19]): ∀ (a_1 : a → b) (a_2 a_3 : a), Or (Ne (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3)) (Eq a_2 a_3)
% 3.63/3.79  Clause #22 (by clausification #[7]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 : a),
% 3.63/3.79    Eq
% 3.63/3.79      (Not
% 3.63/3.79        (∀ (Xy : a),
% 3.63/3.79          Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xy)) →
% 3.63/3.79            Eq (skS.0 2 a_1 a_2 a_3) Xy))
% 3.63/3.79      True
% 3.63/3.79  Clause #23 (by clausification #[22]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 : a),
% 3.63/3.79    Eq
% 3.63/3.79      (∀ (Xy : a),
% 3.63/3.79        Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) (skS.0 1 a_1 a_2 (skS.0 0 a_1 Xy)) →
% 3.63/3.79          Eq (skS.0 2 a_1 a_2 a_3) Xy)
% 3.63/3.79      False
% 3.63/3.79  Clause #24 (by clausification #[23]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a),
% 3.63/3.79    Eq
% 3.63/3.79      (Not
% 3.63/3.79        (Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))
% 3.63/3.79            (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4))) →
% 3.63/3.79          Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.63/3.79      True
% 3.63/3.79  Clause #25 (by clausification #[24]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a),
% 3.63/3.79    Eq
% 3.63/3.79      (Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))
% 3.63/3.79          (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4))) →
% 3.63/3.79        Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4))
% 3.63/3.79      False
% 3.63/3.79  Clause #26 (by clausification #[25]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a),
% 3.63/3.79    Eq
% 3.63/3.79      (Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4))))
% 3.63/3.79      True
% 3.63/3.79  Clause #27 (by clausification #[25]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a), Eq (Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)) False
% 3.63/3.79  Clause #28 (by clausification #[26]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a),
% 3.63/3.79    Eq (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.63/3.79  Clause #29 (by superposition #[28, 14]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 : a) (a_4 : b) (a_5 : a),
% 3.63/3.79    Or (Ne (skS.0 1 a_1 a_2 (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) (skS.0 1 a_1 a_2 a_4))
% 3.63/3.79      (Eq (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_5)) a_4)
% 3.63/3.79  Clause #31 (by clausification #[27]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a), Ne (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)
% 3.63/3.79  Clause #32 (by equality resolution #[29]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a),
% 3.63/3.79    Eq (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))
% 3.63/3.79  Clause #37 (by superposition #[32, 20]): ∀ (a_1 : a → b) (a_2 : a) (a_3 : b → c) (a_4 a_5 : a),
% 3.63/3.79    Or (Ne (skS.0 0 a_1 a_2) (skS.0 0 a_1 (skS.0 2 a_1 a_3 a_4))) (Eq a_2 (skS.0 3 a_1 a_3 a_4 a_5))
% 3.63/3.79  Clause #38 (by equality resolution #[37]): ∀ (a_1 : a → b) (a_2 : b → c) (a_3 a_4 : a), Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)
% 3.63/3.79  Clause #40 (by forward contextual literal cutting #[38, 31]): False
% 3.63/3.79  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------