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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEV122^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:02:51 PM UTC 2025

% Result   : Theorem 3.50s 3.69s
% Output   : Proof 3.50s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : SEV122^5 : TPTP v9.2.0. Released v4.0.0.
% 0.14/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n022.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Oct  3 01:45:08 EDT 2025
% 0.14/0.35  % CPUTime    : 
% 3.50/3.69  SZS status Theorem for theBenchmark.p
% 3.50/3.69  SZS output start Proof for theBenchmark.p
% 3.50/3.69  Clause #0 (by assumption #[]): Eq
% 3.50/3.69    (Not
% 3.50/3.69      (∀ (PROP : (a → a → Prop) → Prop),
% 3.50/3.69        ((a → a → Prop) → Prop) →
% 3.50/3.69          Eq
% 3.50/3.69            (fun Xx Xy =>
% 3.50/3.69              ∀ (Xp : a → a → Prop), And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (PROP Xp) → Xp Xx Xy)
% 3.50/3.69            fun Xx Xy =>
% 3.50/3.69            ∀ (Xp : a → a → Prop), And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (PROP Xp) → Xp Xx Xy))
% 3.50/3.69    True
% 3.50/3.69  Clause #1 (by clausification #[0]): Eq
% 3.50/3.69    (∀ (PROP : (a → a → Prop) → Prop),
% 3.50/3.69      ((a → a → Prop) → Prop) →
% 3.50/3.69        Eq
% 3.50/3.69          (fun Xx Xy =>
% 3.50/3.69            ∀ (Xp : a → a → Prop), And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (PROP Xp) → Xp Xx Xy)
% 3.50/3.69          fun Xx Xy =>
% 3.50/3.69          ∀ (Xp : a → a → Prop), And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (PROP Xp) → Xp Xx Xy)
% 3.50/3.69    False
% 3.50/3.69  Clause #2 (by clausification #[1]): ∀ (a_1 : (a → a → Prop) → Prop),
% 3.50/3.69    Eq
% 3.50/3.69      (Not
% 3.50/3.69        (((a → a → Prop) → Prop) →
% 3.50/3.69          Eq
% 3.50/3.69            (fun Xx Xy =>
% 3.50/3.69              ∀ (Xp : a → a → Prop),
% 3.50/3.69                And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69            fun Xx Xy =>
% 3.50/3.69            ∀ (Xp : a → a → Prop),
% 3.50/3.69              And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy))
% 3.50/3.69      True
% 3.50/3.69  Clause #3 (by clausification #[2]): ∀ (a_1 : (a → a → Prop) → Prop),
% 3.50/3.69    Eq
% 3.50/3.69      (((a → a → Prop) → Prop) →
% 3.50/3.69        Eq
% 3.50/3.69          (fun Xx Xy =>
% 3.50/3.69            ∀ (Xp : a → a → Prop),
% 3.50/3.69              And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69          fun Xx Xy =>
% 3.50/3.69          ∀ (Xp : a → a → Prop),
% 3.50/3.69            And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69      False
% 3.50/3.69  Clause #4 (by clausification #[3]): ∀ (a_1 : (a → a → Prop) → Prop),
% 3.50/3.69    ((a → a → Prop) → Prop) →
% 3.50/3.69      Eq
% 3.50/3.69        (Not
% 3.50/3.69          (Eq
% 3.50/3.69            (fun Xx Xy =>
% 3.50/3.69              ∀ (Xp : a → a → Prop),
% 3.50/3.69                And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69            fun Xx Xy =>
% 3.50/3.69            ∀ (Xp : a → a → Prop),
% 3.50/3.69              And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy))
% 3.50/3.69        True
% 3.50/3.69  Clause #5 (by clausification #[4]): ∀ (a_1 : (a → a → Prop) → Prop),
% 3.50/3.69    Eq
% 3.50/3.69      (Eq
% 3.50/3.69        (fun Xx Xy =>
% 3.50/3.69          ∀ (Xp : a → a → Prop),
% 3.50/3.69            And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69        fun Xx Xy =>
% 3.50/3.69        ∀ (Xp : a → a → Prop),
% 3.50/3.69          And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69      False
% 3.50/3.69  Clause #6 (by clausification #[5]): ∀ (a_1 : (a → a → Prop) → Prop),
% 3.50/3.69    Ne
% 3.50/3.69      (fun Xx Xy =>
% 3.50/3.69        ∀ (Xp : a → a → Prop),
% 3.50/3.69          And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy)
% 3.50/3.69      fun Xx Xy =>
% 3.50/3.69      ∀ (Xp : a → a → Prop), And (∀ (Xx0 Xy0 : a), (Exists fun R => R Xx0 Xy0) → Xp Xx0 Xy0) (skS.0 0 a_1 Xp) → Xp Xx Xy
% 3.50/3.69  Clause #7 (by eliminate resolved literals #[6]): False
% 3.50/3.69  SZS output end Proof for theBenchmark.p
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