%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SEV159^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n003.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:02:53 PM UTC 2025 % Result : Theorem 5.09s 5.34s % Output : Proof 5.09s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.09 % Problem : SEV159^5 : TPTP v9.2.0. Released v4.0.0. % 0.00/0.10 % Command : duper %s % 0.09/0.29 % Computer : n003.cluster.edu % 0.09/0.29 % Model : x86_64 x86_64 % 0.09/0.29 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.09/0.29 % Memory : 8042.1875MB % 0.09/0.29 % OS : Linux 3.10.0-693.el7.x86_64 % 0.09/0.29 % CPULimit : 300 % 0.09/0.29 % WCLimit : 300 % 0.09/0.29 % DateTime : Fri Oct 3 00:59:23 EDT 2025 % 0.09/0.29 % CPUTime : % 5.09/5.34 SZS status Theorem for theBenchmark.p % 5.09/5.34 SZS output start Proof for theBenchmark.p % 5.09/5.34 Clause #0 (by assumption #[]): Eq (Not (a → ∀ (Xy : a), Eq Xy Xy)) True % 5.09/5.34 Clause #1 (by clausification #[0]): Eq (a → ∀ (Xy : a), Eq Xy Xy) False % 5.09/5.34 Clause #2 (by clausification #[1]): a → Eq (Not (∀ (Xy : a), Eq Xy Xy)) True % 5.09/5.34 Clause #3 (by clausification #[2]): Eq (∀ (Xy : a), Eq Xy Xy) False % 5.09/5.34 Clause #4 (by clausification #[3]): ∀ (a_1 : a), Eq (Not (Eq (skS.0 1 a_1) (skS.0 1 a_1))) True % 5.09/5.34 Clause #5 (by clausification #[4]): ∀ (a_1 : a), Eq (Eq (skS.0 1 a_1) (skS.0 1 a_1)) False % 5.09/5.34 Clause #6 (by clausification #[5]): ∀ (a_1 : a), Ne (skS.0 1 a_1) (skS.0 1 a_1) % 5.09/5.34 Clause #7 (by eliminate resolved literals #[6]): False % 5.09/5.34 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------