%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SEV160^5 : TPTP v6.1.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n095.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-431.20.3.el6.x86_64 % CPULimit : 300s % DateTime : Thu Jul 17 13:33:49 EDT 2014 % Result : Theorem 0.42s % Output : Proof 0.42s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----ERROR: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % % Problem : SEV160^5 : TPTP v6.1.0. Released v4.0.0. % % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % % Computer : n095.star.cs.uiowa.edu % % Model : x86_64 x86_64 % % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % % Memory : 32286.75MB % % OS : Linux 2.6.32-431.20.3.el6.x86_64 % % CPULimit : 300 % % DateTime : Thu Jul 17 08:16:21 CDT 2014 % % CPUTime : 0.42 % Python 2.7.5 % Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % FOF formula (<kernel.Constant object at 0x259e680>, <kernel.Type object at 0x259ef38>) of role type named a_type % Using role type % Declaring a:Type % FOF formula (<kernel.Constant object at 0x259eab8>, <kernel.Constant object at 0x259e518>) of role type named y % Using role type % Declaring y:a % FOF formula (<kernel.Constant object at 0x246ccf8>, <kernel.Constant object at 0x259e518>) of role type named x % Using role type % Declaring x:a % FOF formula (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) of role conjecture named cTHM186_pme % Conjecture to prove = (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))):Prop % We need to prove ['(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))'] % Parameter a:Type. % Parameter y:a. % Parameter x:a. % Trying to prove (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Found eta_expansion000:=(eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))):(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (x0:(a->(a->a)))=> ((x0 x) y))) % Found (eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Found ((eta_expansion0 a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Got proof (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % Time elapsed = 0.115466s % node=11 cost=-282.000000 depth=3 % :::::::::::::::::::::: % % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) % % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % EOF %------------------------------------------------------------------------------