↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEV272^5 : TPTP v9.2.0. Bugfixed v5.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:03:01 PM UTC 2025

% Result   : Theorem 3.88s 4.11s
% Output   : Proof 3.88s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : SEV272^5 : TPTP v9.2.0. Bugfixed v5.2.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n020.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Oct  3 01:48:38 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 3.88/4.11  SZS status Theorem for theBenchmark.p
% 3.88/4.11  SZS output start Proof for theBenchmark.p
% 3.88/4.11  Clause #2 (by assumption #[]): Eq
% 3.88/4.11    (Not
% 3.88/4.11      (Eq
% 3.88/4.11        (fun N =>
% 3.88/4.11          ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P cZERO) (∀ (X : (Iota → Prop) → Prop), P X → P (cSUCC X)) → P N)
% 3.88/4.11        fun Xx =>
% 3.88/4.11        ∀ (S : ((Iota → Prop) → Prop) → Prop), And (S cZERO) (∀ (X : (Iota → Prop) → Prop), S X → S (cSUCC X)) → S Xx))
% 3.88/4.11    True
% 3.88/4.11  Clause #133 (by clausification #[2]): Eq
% 3.88/4.11    (Eq
% 3.88/4.11      (fun N =>
% 3.88/4.11        ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P cZERO) (∀ (X : (Iota → Prop) → Prop), P X → P (cSUCC X)) → P N)
% 3.88/4.11      fun Xx =>
% 3.88/4.11      ∀ (S : ((Iota → Prop) → Prop) → Prop), And (S cZERO) (∀ (X : (Iota → Prop) → Prop), S X → S (cSUCC X)) → S Xx)
% 3.88/4.11    False
% 3.88/4.11  Clause #134 (by clausification #[133]): Ne
% 3.88/4.11    (fun N =>
% 3.88/4.11      ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P cZERO) (∀ (X : (Iota → Prop) → Prop), P X → P (cSUCC X)) → P N)
% 3.88/4.11    fun Xx =>
% 3.88/4.11    ∀ (S : ((Iota → Prop) → Prop) → Prop), And (S cZERO) (∀ (X : (Iota → Prop) → Prop), S X → S (cSUCC X)) → S Xx
% 3.88/4.11  Clause #135 (by eliminate resolved literals #[134]): False
% 3.88/4.11  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------