%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SEV282^5 : TPTP v6.2.0. Bugfixed v6.2.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n112.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-504.8.1.el6.x86_64 % CPULimit : 300s % DateTime : Tue Apr 21 16:51:41 EDT 2015 % Result : Theorem 0.27s % Output : Proof 0.27s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.02 % Problem : SEV282^5 : TPTP v6.2.0. Bugfixed v6.2.0. % 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.01/1.08 % Computer : n112.star.cs.uiowa.edu % 0.01/1.08 % Model : x86_64 x86_64 % 0.01/1.08 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.01/1.08 % Memory : 32286.75MB % 0.01/1.08 % OS : Linux 2.6.32-504.8.1.el6.x86_64 % 0.01/1.08 % CPULimit : 300 % 0.01/1.08 % DateTime : Thu Apr 16 12:04:27 CDT 2015 % 0.01/1.08 % CPUTime : % 0.01/1.09 Python 2.7.5 % 0.27/1.47 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.27/1.47 FOF formula (<kernel.Constant object at 0x877c20>, <kernel.DependentProduct object at 0x877f80>) of role type named cNAT_type % 0.27/1.47 Using role type % 0.27/1.47 Declaring cNAT:(((fofType->Prop)->Prop)->Prop) % 0.27/1.47 FOF formula (<kernel.Constant object at 0x877d40>, <kernel.DependentProduct object at 0x877320>) of role type named cSUCC_type % 0.27/1.47 Using role type % 0.27/1.47 Declaring cSUCC:(((fofType->Prop)->Prop)->((fofType->Prop)->Prop)) % 0.27/1.47 FOF formula (<kernel.Constant object at 0x8774d0>, <kernel.DependentProduct object at 0x877c20>) of role type named cZERO_type % 0.27/1.47 Using role type % 0.27/1.47 Declaring cZERO:((fofType->Prop)->Prop) % 0.27/1.47 FOF formula (((eq ((fofType->Prop)->Prop)) cZERO) (fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False))) of role definition named cZERO_def % 0.27/1.47 A new definition: (((eq ((fofType->Prop)->Prop)) cZERO) (fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False))) % 0.27/1.47 Defined: cZERO:=(fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False)) % 0.27/1.47 FOF formula (((eq (((fofType->Prop)->Prop)->((fofType->Prop)->Prop))) cSUCC) (fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt))))))))) of role definition named cSUCC_def % 0.27/1.47 A new definition: (((eq (((fofType->Prop)->Prop)->((fofType->Prop)->Prop))) cSUCC) (fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt))))))))) % 0.27/1.47 Defined: cSUCC:=(fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt)))))))) % 0.27/1.47 FOF formula (((eq (((fofType->Prop)->Prop)->Prop)) cNAT) (fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn))))) of role definition named cNAT_def % 0.27/1.47 A new definition: (((eq (((fofType->Prop)->Prop)->Prop)) cNAT) (fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn))))) % 0.27/1.47 Defined: cNAT:=(fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn)))) % 0.27/1.47 FOF formula (cNAT cZERO) of role conjecture named cTTTP6100 % 0.27/1.47 Conjecture to prove = (cNAT cZERO):Prop % 0.27/1.47 Parameter fofType_DUMMY:fofType. % 0.27/1.47 We need to prove ['(cNAT cZERO)'] % 0.27/1.47 Parameter fofType:Type. % 0.27/1.47 Definition cNAT:=(fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn)))):(((fofType->Prop)->Prop)->Prop). % 0.27/1.47 Definition cSUCC:=(fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt)))))))):(((fofType->Prop)->Prop)->((fofType->Prop)->Prop)). % 0.27/1.47 Definition cZERO:=(fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False)):((fofType->Prop)->Prop). % 0.27/1.47 Trying to prove (cNAT cZERO) % 0.27/1.47 Found x0:(Xp cZERO) % 0.27/1.47 Found (fun (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0) as proof of (Xp cZERO) % 0.27/1.47 Found (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->(Xp cZERO)) % 0.27/1.47 Found (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0) as proof of ((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->(Xp cZERO))) % 0.27/1.47 Found (and_rect00 (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0)) as proof of (Xp cZERO) % 0.27/1.47 Found ((and_rect0 (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0)) as proof of (Xp cZERO) % 0.27/1.48 Found (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0)) as proof of (Xp cZERO) % 0.27/1.48 Found (fun (x:((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))))=> (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0))) as proof of (Xp cZERO) % 0.27/1.48 Found (fun (Xp:(((fofType->Prop)->Prop)->Prop)) (x:((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))))=> (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0))) as proof of (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO)) % 0.27/1.48 Found (fun (Xp:(((fofType->Prop)->Prop)->Prop)) (x:((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))))=> (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0))) as proof of (cNAT cZERO) % 0.27/1.48 Got proof (fun (Xp:(((fofType->Prop)->Prop)->Prop)) (x:((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))))=> (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0))) % 0.27/1.48 Time elapsed = 0.037663s % 0.27/1.48 node=9 cost=69.000000 depth=8 % 0.27/1.48:::::::::::::::::::::: % 0.27/1.48 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.27/1.48 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.27/1.48 (fun (Xp:(((fofType->Prop)->Prop)->Prop)) (x:((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))))=> (((fun (P:Type) (x0:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx))))) P) x0) x)) (Xp cZERO)) (fun (x0:(Xp cZERO)) (x1:(forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))=> x0))) % 0.27/1.48 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------