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Bliksem---1.12.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SWX207+1 : TPTP v9.3.0. Released v9.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue May  5 06:56:48 PM UTC 2026

% Result   : Theorem 0.70s 1.14s
% Output   : Refutation 0.70s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SWX207+1 : TPTP v9.3.0. Released v9.3.0.
% 0.00/0.12  % Command  : bliksem %s
% 0.16/0.33  % Computer : n010.cluster.edu
% 0.16/0.33  % Model    : x86_64 x86_64
% 0.16/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.33  % Memory   : 8042.1875MB
% 0.16/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.33  % CPULimit : 300
% 0.16/0.33  % DateTime : Tue May  5 11:34:36 EDT 2026
% 0.16/0.34  % CPUTime  : 
% 0.70/1.13  *** allocated 10000 integers for termspace/termends
% 0.70/1.13  *** allocated 10000 integers for clauses
% 0.70/1.13  *** allocated 10000 integers for justifications
% 0.70/1.13  Bliksem 1.12
% 0.70/1.13  
% 0.70/1.13  
% 0.70/1.13  Automatic Strategy Selection
% 0.70/1.13  
% 0.70/1.13  
% 0.70/1.13  Clauses:
% 0.70/1.13  
% 0.70/1.13  { head( cons( X, Y ) ) = X }.
% 0.70/1.13  { tail( cons( X, Y ) ) = Y }.
% 0.70/1.13  { ! nil = cons( X, Y ) }.
% 0.70/1.13  { ! a = b }.
% 0.70/1.13  { proj1AP( aP( X ) ) = X }.
% 0.70/1.13  { proj1BP( bP( X ) ) = X }.
% 0.70/1.13  { ! aP( X ) = bP( Y ) }.
% 0.70/1.13  { ! aP( X ) = pA }.
% 0.70/1.13  { ! aP( X ) = pB }.
% 0.70/1.13  { ! aP( X ) = pE }.
% 0.70/1.13  { ! bP( X ) = pA }.
% 0.70/1.13  { ! bP( X ) = pB }.
% 0.70/1.13  { ! bP( X ) = pE }.
% 0.70/1.13  { ! pA = pB }.
% 0.70/1.13  { ! pA = pE }.
% 0.70/1.13  { ! pB = pE }.
% 0.70/1.13  { proj1C( c2( X, Y ) ) = X }.
% 0.70/1.13  { proj2C( c2( X, Y ) ) = Y }.
% 0.70/1.13  { append( nil, X ) = X }.
% 0.70/1.13  { append( cons( Y, Z ), X ) = cons( Y, append( Z, X ) ) }.
% 0.70/1.13  { linP( aP( X ) ) = append( cons( a, nil ), append( linP( X ), cons( a, nil
% 0.70/1.13     ) ) ) }.
% 0.70/1.13  { linP( bP( X ) ) = append( cons( b, nil ), append( linP( X ), cons( b, nil
% 0.70/1.13     ) ) ) }.
% 0.70/1.13  { linP( pA ) = cons( a, nil ) }.
% 0.70/1.13  { linP( pB ) = cons( b, nil ) }.
% 0.70/1.13  { linP( pE ) = nil }.
% 0.70/1.13  { linC( c2( X, Y ) ) = append( linP( X ), linP( Y ) ) }.
% 0.70/1.13  { ! linC( X ) = linC( Y ), X = Y }.
% 0.70/1.13  
% 0.70/1.13  percentage equality = 1.000000, percentage horn = 1.000000
% 0.70/1.13  This is a pure equality problem
% 0.70/1.13  
% 0.70/1.13  
% 0.70/1.13  
% 0.70/1.13  Options Used:
% 0.70/1.13  
% 0.70/1.13  useres =            1
% 0.70/1.13  useparamod =        1
% 0.70/1.13  useeqrefl =         1
% 0.70/1.13  useeqfact =         1
% 0.70/1.13  usefactor =         1
% 0.70/1.13  usesimpsplitting =  0
% 0.70/1.13  usesimpdemod =      5
% 0.70/1.13  usesimpres =        3
% 0.70/1.13  
% 0.70/1.13  resimpinuse      =  1000
% 0.70/1.13  resimpclauses =     20000
% 0.70/1.13  substype =          eqrewr
% 0.70/1.13  backwardsubs =      1
% 0.70/1.13  selectoldest =      5
% 0.70/1.13  
% 0.70/1.13  litorderings [0] =  split
% 0.70/1.13  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.70/1.13  
% 0.70/1.13  termordering =      kbo
% 0.70/1.13  
% 0.70/1.13  litapriori =        0
% 0.70/1.13  termapriori =       1
% 0.70/1.13  litaposteriori =    0
% 0.70/1.13  termaposteriori =   0
% 0.70/1.13  demodaposteriori =  0
% 0.70/1.13  ordereqreflfact =   0
% 0.70/1.13  
% 0.70/1.13  litselect =         negord
% 0.70/1.13  
% 0.70/1.13  maxweight =         15
% 0.70/1.13  maxdepth =          30000
% 0.70/1.13  maxlength =         115
% 0.70/1.13  maxnrvars =         195
% 0.70/1.13  excuselevel =       1
% 0.70/1.13  increasemaxweight = 1
% 0.70/1.13  
% 0.70/1.13  maxselected =       10000000
% 0.70/1.13  maxnrclauses =      10000000
% 0.70/1.13  
% 0.70/1.13  showgenerated =    0
% 0.70/1.13  showkept =         0
% 0.70/1.13  showselected =     0
% 0.70/1.13  showdeleted =      0
% 0.70/1.13  showresimp =       1
% 0.70/1.13  showstatus =       2000
% 0.70/1.13  
% 0.70/1.13  prologoutput =     0
% 0.70/1.13  nrgoals =          5000000
% 0.70/1.13  totalproof =       1
% 0.70/1.13  
% 0.70/1.13  Symbols occurring in the translation:
% 0.70/1.13  
% 0.70/1.13  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.70/1.13  .  [1, 2]      (w:1, o:36, a:1, s:1, b:0), 
% 0.70/1.13  !  [4, 1]      (w:0, o:21, a:1, s:1, b:0), 
% 0.70/1.13  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.70/1.13  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.70/1.13  cons  [37, 2]      (w:1, o:60, a:1, s:1, b:0), 
% 0.70/1.13  head  [38, 1]      (w:1, o:26, a:1, s:1, b:0), 
% 0.70/1.13  tail  [39, 1]      (w:1, o:27, a:1, s:1, b:0), 
% 0.70/1.13  nil  [40, 0]      (w:1, o:8, a:1, s:1, b:0), 
% 0.70/1.13  a  [41, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.70/1.13  b  [42, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.70/1.13  aP  [43, 1]      (w:1, o:28, a:1, s:1, b:0), 
% 0.70/1.13  proj1AP  [44, 1]      (w:1, o:29, a:1, s:1, b:0), 
% 0.70/1.13  bP  [45, 1]      (w:1, o:30, a:1, s:1, b:0), 
% 0.70/1.13  proj1BP  [46, 1]      (w:1, o:31, a:1, s:1, b:0), 
% 0.70/1.13  pA  [47, 0]      (w:1, o:11, a:1, s:1, b:0), 
% 0.70/1.13  pB  [48, 0]      (w:1, o:12, a:1, s:1, b:0), 
% 0.70/1.13  pE  [49, 0]      (w:1, o:13, a:1, s:1, b:0), 
% 0.70/1.13  c2  [50, 2]      (w:1, o:61, a:1, s:1, b:0), 
% 0.70/1.13  proj1C  [51, 1]      (w:1, o:32, a:1, s:1, b:0), 
% 0.70/1.14  proj2C  [52, 1]      (w:1, o:33, a:1, s:1, b:0), 
% 0.70/1.14  append  [54, 2]      (w:1, o:62, a:1, s:1, b:0), 
% 0.70/1.14  linP  [58, 1]      (w:1, o:34, a:1, s:1, b:0), 
% 0.70/1.14  linC  [60, 1]      (w:1, o:35, a:1, s:1, b:0).
% 0.70/1.14  
% 0.70/1.14  
% 0.70/1.14  Starting Search:
% 0.70/1.14  
% 0.70/1.14  *** allocated 15000 integers for clauses
% 0.70/1.14  *** allocated 22500 integers for clauses
% 0.70/1.14  *** allocated 33750 integers for clauses
% 0.70/1.14  *** allocated 50625 integers for clauses
% 0.70/1.14  *** allocated 15000 integers for termspace/termends
% 0.70/1.14  
% 0.70/1.14  Bliksems!, er is een bewijs:
% 0.70/1.14  % SZS status Theorem
% 0.70/1.14  % SZS output start Refutation
% 0.70/1.14  
% 0.70/1.14  (15) {G0,W3,D2,L1,V0,M1} I { ! pE ==> pB }.
% 0.70/1.14  (17) {G0,W6,D4,L1,V2,M1} I { proj2C( c2( X, Y ) ) ==> Y }.
% 0.70/1.14  (18) {G0,W5,D3,L1,V1,M1} I { append( nil, X ) ==> X }.
% 0.70/1.14  (19) {G0,W11,D4,L1,V3,M1} I { append( cons( Y, Z ), X ) ==> cons( Y, append
% 0.70/1.14    ( Z, X ) ) }.
% 0.70/1.14  (23) {G0,W6,D3,L1,V0,M1} I { cons( b, nil ) ==> linP( pB ) }.
% 0.70/1.14  (24) {G0,W4,D3,L1,V0,M1} I { linP( pE ) ==> nil }.
% 0.70/1.14  (25) {G0,W10,D4,L1,V2,M1} I { append( linP( X ), linP( Y ) ) ==> linC( c2( 
% 0.70/1.14    X, Y ) ) }.
% 0.70/1.14  (26) {G0,W8,D3,L2,V2,M2} I { ! linC( X ) = linC( Y ), X = Y }.
% 0.70/1.14  (40) {G1,W11,D4,L2,V3,M2} P(26,17) { proj2C( Z ) = Y, ! linC( c2( X, Y ) ) 
% 0.70/1.14    = linC( Z ) }.
% 0.70/1.14  (92) {G1,W8,D4,L1,V1,M1} P(23,19);d(18) { append( linP( pB ), X ) ==> cons
% 0.70/1.14    ( b, X ) }.
% 0.70/1.14  (136) {G1,W7,D4,L1,V1,M1} P(24,25);d(18) { linC( c2( pE, X ) ) ==> linP( X
% 0.70/1.14     ) }.
% 0.70/1.14  (470) {G2,W9,D4,L1,V1,M1} P(92,25) { cons( b, linP( X ) ) ==> linC( c2( pB
% 0.70/1.14    , X ) ) }.
% 0.70/1.14  (554) {G3,W7,D4,L1,V0,M1} P(24,470);d(23) { linC( c2( pB, pE ) ) ==> linP( 
% 0.70/1.14    pB ) }.
% 0.70/1.14  (576) {G2,W9,D3,L2,V2,M2} P(136,40) { proj2C( Y ) = X, ! linP( X ) = linC( 
% 0.70/1.14    Y ) }.
% 0.70/1.14  (743) {G4,W8,D3,L2,V1,M2} P(554,576);d(17) { ! linP( X ) = linP( pB ), pE =
% 0.70/1.14     X }.
% 0.70/1.14  (904) {G5,W3,D2,L1,V0,M1} Q(743) { pE ==> pB }.
% 0.70/1.14  (907) {G6,W0,D0,L0,V0,M0} S(904);r(15) {  }.
% 0.70/1.14  
% 0.70/1.14  
% 0.70/1.14  % SZS output end Refutation
% 0.70/1.14  found a proof!
% 0.70/1.14  
% 0.70/1.14  
% 0.70/1.14  Unprocessed initial clauses:
% 0.70/1.14  
% 0.70/1.14  (909) {G0,W6,D4,L1,V2,M1}  { head( cons( X, Y ) ) = X }.
% 0.70/1.14  (910) {G0,W6,D4,L1,V2,M1}  { tail( cons( X, Y ) ) = Y }.
% 0.70/1.14  (911) {G0,W5,D3,L1,V2,M1}  { ! nil = cons( X, Y ) }.
% 0.70/1.14  (912) {G0,W3,D2,L1,V0,M1}  { ! a = b }.
% 0.70/1.14  (913) {G0,W5,D4,L1,V1,M1}  { proj1AP( aP( X ) ) = X }.
% 0.70/1.14  (914) {G0,W5,D4,L1,V1,M1}  { proj1BP( bP( X ) ) = X }.
% 0.70/1.14  (915) {G0,W5,D3,L1,V2,M1}  { ! aP( X ) = bP( Y ) }.
% 0.70/1.14  (916) {G0,W4,D3,L1,V1,M1}  { ! aP( X ) = pA }.
% 0.70/1.14  (917) {G0,W4,D3,L1,V1,M1}  { ! aP( X ) = pB }.
% 0.70/1.14  (918) {G0,W4,D3,L1,V1,M1}  { ! aP( X ) = pE }.
% 0.70/1.14  (919) {G0,W4,D3,L1,V1,M1}  { ! bP( X ) = pA }.
% 0.70/1.14  (920) {G0,W4,D3,L1,V1,M1}  { ! bP( X ) = pB }.
% 0.70/1.14  (921) {G0,W4,D3,L1,V1,M1}  { ! bP( X ) = pE }.
% 0.70/1.14  (922) {G0,W3,D2,L1,V0,M1}  { ! pA = pB }.
% 0.70/1.14  (923) {G0,W3,D2,L1,V0,M1}  { ! pA = pE }.
% 0.70/1.14  (924) {G0,W3,D2,L1,V0,M1}  { ! pB = pE }.
% 0.70/1.14  (925) {G0,W6,D4,L1,V2,M1}  { proj1C( c2( X, Y ) ) = X }.
% 0.70/1.14  (926) {G0,W6,D4,L1,V2,M1}  { proj2C( c2( X, Y ) ) = Y }.
% 0.70/1.14  (927) {G0,W5,D3,L1,V1,M1}  { append( nil, X ) = X }.
% 0.70/1.14  (928) {G0,W11,D4,L1,V3,M1}  { append( cons( Y, Z ), X ) = cons( Y, append( 
% 0.70/1.14    Z, X ) ) }.
% 0.70/1.14  (929) {G0,W14,D5,L1,V1,M1}  { linP( aP( X ) ) = append( cons( a, nil ), 
% 0.70/1.14    append( linP( X ), cons( a, nil ) ) ) }.
% 0.70/1.14  (930) {G0,W14,D5,L1,V1,M1}  { linP( bP( X ) ) = append( cons( b, nil ), 
% 0.70/1.14    append( linP( X ), cons( b, nil ) ) ) }.
% 0.70/1.14  (931) {G0,W6,D3,L1,V0,M1}  { linP( pA ) = cons( a, nil ) }.
% 0.70/1.14  (932) {G0,W6,D3,L1,V0,M1}  { linP( pB ) = cons( b, nil ) }.
% 0.70/1.14  (933) {G0,W4,D3,L1,V0,M1}  { linP( pE ) = nil }.
% 0.70/1.14  (934) {G0,W10,D4,L1,V2,M1}  { linC( c2( X, Y ) ) = append( linP( X ), linP
% 0.70/1.14    ( Y ) ) }.
% 0.70/1.14  (935) {G0,W8,D3,L2,V2,M2}  { ! linC( X ) = linC( Y ), X = Y }.
% 0.70/1.14  
% 0.70/1.14  
% 0.70/1.14  Total Proof:
% 0.70/1.14  
% 0.70/1.14  eqswap: (951) {G0,W3,D2,L1,V0,M1}  { ! pE = pB }.
% 0.70/1.14  parent0[0]: (924) {G0,W3,D2,L1,V0,M1}  { ! pB = pE }.
% 0.70/1.14  substitution0:
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (15) {G0,W3,D2,L1,V0,M1} I { ! pE ==> pB }.
% 0.70/1.14  parent0: (951) {G0,W3,D2,L1,V0,M1}  { ! pE = pB }.
% 0.70/1.14  substitution0:
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (17) {G0,W6,D4,L1,V2,M1} I { proj2C( c2( X, Y ) ) ==> Y }.
% 0.70/1.14  parent0: (926) {G0,W6,D4,L1,V2,M1}  { proj2C( c2( X, Y ) ) = Y }.
% 0.70/1.14  substitution0:
% 0.70/1.14     X := X
% 0.70/1.14     Y := Y
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (18) {G0,W5,D3,L1,V1,M1} I { append( nil, X ) ==> X }.
% 0.70/1.14  parent0: (927) {G0,W5,D3,L1,V1,M1}  { append( nil, X ) = X }.
% 0.70/1.14  substitution0:
% 0.70/1.14     X := X
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (19) {G0,W11,D4,L1,V3,M1} I { append( cons( Y, Z ), X ) ==> 
% 0.70/1.14    cons( Y, append( Z, X ) ) }.
% 0.70/1.14  parent0: (928) {G0,W11,D4,L1,V3,M1}  { append( cons( Y, Z ), X ) = cons( Y
% 0.70/1.14    , append( Z, X ) ) }.
% 0.70/1.14  substitution0:
% 0.70/1.14     X := X
% 0.70/1.14     Y := Y
% 0.70/1.14     Z := Z
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  eqswap: (1032) {G0,W6,D3,L1,V0,M1}  { cons( b, nil ) = linP( pB ) }.
% 0.70/1.14  parent0[0]: (932) {G0,W6,D3,L1,V0,M1}  { linP( pB ) = cons( b, nil ) }.
% 0.70/1.14  substitution0:
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (23) {G0,W6,D3,L1,V0,M1} I { cons( b, nil ) ==> linP( pB ) }.
% 0.70/1.14  parent0: (1032) {G0,W6,D3,L1,V0,M1}  { cons( b, nil ) = linP( pB ) }.
% 0.70/1.14  substitution0:
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  subsumption: (24) {G0,W4,D3,L1,V0,M1} I { linP( pE ) ==> nil }.
% 0.70/1.14  parent0: (933) {G0,W4,D3,L1,V0,M1}  { linP( pE ) = nil }.
% 0.70/1.14  substitution0:
% 0.70/1.14  end
% 0.70/1.14  permutation0:
% 0.70/1.14     0 ==> 0
% 0.70/1.14  end
% 0.70/1.14  
% 0.70/1.14  eqswap: (1083) {G0,W10,D4,L1,V2,M1}  { append( linP( X ), linP( Y ) ) = 
% 0.70/1.14    linC( c2( X, Y ) ) }.
% 0.70/1.14  parent0[0]: (934) {G0,W10,D4,L1,V2,M1}  { linC( c2( X, Y ) ) = append( linP
% 0.70/1.14    ( X ), linP( YTerminated 
% 299.55/300.02  Bliksem ended
%------------------------------------------------------------------------------