%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN044+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n009.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:01 PM UTC 2025 % Result : Theorem 3.72s 3.88s % Output : Proof 3.72s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.13/0.13 % Problem : SYN044+1 : TPTP v9.2.0. Released v2.0.0. % 0.13/0.15 % Command : duper %s % 0.15/0.36 % Computer : n009.cluster.edu % 0.15/0.36 % Model : x86_64 x86_64 % 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.15/0.36 % Memory : 8042.1875MB % 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64 % 0.15/0.36 % CPULimit : 300 % 0.15/0.36 % WCLimit : 300 % 0.15/0.36 % DateTime : Thu Oct 2 15:38:23 EDT 2025 % 0.15/0.36 % CPUTime : % 3.72/3.88 SZS status Theorem for theBenchmark.p % 3.72/3.88 SZS output start Proof for theBenchmark.p % 3.72/3.88 Clause #0 (by assumption #[]): Eq (q → r) True % 3.72/3.88 Clause #1 (by assumption #[]): Eq (r → And p q) True % 3.72/3.88 Clause #2 (by assumption #[]): Eq (p → Or q r) True % 3.72/3.88 Clause #3 (by assumption #[]): Eq (Not (Iff p q)) True % 3.72/3.88 Clause #4 (by clausification #[0]): Or (Eq q False) (Eq r True) % 3.72/3.88 Clause #5 (by clausification #[1]): Or (Eq r False) (Eq (And p q) True) % 3.72/3.88 Clause #6 (by clausification #[5]): Or (Eq r False) (Eq q True) % 3.72/3.88 Clause #7 (by clausification #[5]): Or (Eq r False) (Eq p True) % 3.72/3.88 Clause #8 (by clausification #[3]): Eq (Iff p q) False % 3.72/3.88 Clause #9 (by clausification #[8]): Or (Eq p False) (Eq q False) % 3.72/3.88 Clause #10 (by clausification #[8]): Or (Eq p True) (Eq q True) % 3.72/3.88 Clause #12 (by clausification #[2]): Or (Eq p False) (Eq (Or q r) True) % 3.72/3.88 Clause #13 (by clausification #[12]): Or (Eq p False) (Or (Eq q True) (Eq r True)) % 3.72/3.88 Clause #14 (by superposition #[13, 10]): Or (Eq q True) (Or (Eq r True) (Or (Eq False True) (Eq q True))) % 3.72/3.88 Clause #16 (by clausification #[14]): Or (Eq q True) (Or (Eq r True) (Eq q True)) % 3.72/3.88 Clause #17 (by eliminate duplicate literals #[16]): Or (Eq q True) (Eq r True) % 3.72/3.88 Clause #18 (by superposition #[17, 6]): Or (Eq q True) (Or (Eq True False) (Eq q True)) % 3.72/3.88 Clause #21 (by clausification #[18]): Or (Eq q True) (Eq q True) % 3.72/3.88 Clause #22 (by eliminate duplicate literals #[21]): Eq q True % 3.72/3.88 Clause #23 (by backward demodulation #[22, 4]): Or (Eq True False) (Eq r True) % 3.72/3.88 Clause #25 (by backward demodulation #[22, 9]): Or (Eq p False) (Eq True False) % 3.72/3.88 Clause #28 (by clausification #[23]): Eq r True % 3.72/3.88 Clause #29 (by backward demodulation #[28, 7]): Or (Eq True False) (Eq p True) % 3.72/3.88 Clause #30 (by clausification #[29]): Eq p True % 3.72/3.88 Clause #31 (by clausification #[25]): Eq p False % 3.72/3.88 Clause #32 (by superposition #[31, 30]): Eq False True % 3.72/3.88 Clause #33 (by clausification #[32]): False % 3.72/3.88 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------