%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN048+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n007.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:02 PM UTC 2025 % Result : Theorem 3.37s 3.51s % Output : Proof 3.37s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.06/0.13 % Problem : SYN048+1 : TPTP v9.2.0. Released v2.0.0. % 0.06/0.14 % Command : duper %s % 0.14/0.35 % Computer : n007.cluster.edu % 0.14/0.35 % Model : x86_64 x86_64 % 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.35 % Memory : 8042.1875MB % 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.35 % CPULimit : 300 % 0.14/0.35 % WCLimit : 300 % 0.14/0.35 % DateTime : Thu Oct 2 15:46:08 EDT 2025 % 0.14/0.35 % CPUTime : % 3.37/3.51 SZS status Theorem for theBenchmark.p % 3.37/3.51 SZS output start Proof for theBenchmark.p % 3.37/3.51 Clause #0 (by assumption #[]): Eq (Not (Exists fun Y => ∀ (X : Iota), big_f Y → big_f X)) True % 3.37/3.51 Clause #1 (by clausification #[0]): Eq (Exists fun Y => ∀ (X : Iota), big_f Y → big_f X) False % 3.37/3.51 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (X : Iota), big_f a → big_f X) False % 3.37/3.51 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), Eq (Not (big_f a → big_f (skS.0 0 a a_1))) True % 3.37/3.51 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (big_f a → big_f (skS.0 0 a a_1)) False % 3.37/3.51 Clause #5 (by clausification #[4]): ∀ (a : Iota), Eq (big_f a) True % 3.37/3.51 Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (big_f (skS.0 0 a a_1)) False % 3.37/3.51 Clause #7 (by superposition #[6, 5]): Eq False True % 3.37/3.51 Clause #8 (by clausification #[7]): False % 3.37/3.51 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------