↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN051^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:03 PM UTC 2025

% Result   : Theorem 3.56s 3.71s
% Output   : Proof 3.56s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SYN051^5 : TPTP v9.2.0. Released v4.0.0.
% 0.11/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n021.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Thu Oct  2 15:16:23 EDT 2025
% 0.14/0.35  % CPUTime    : 
% 3.56/3.71  SZS status Theorem for theBenchmark.p
% 3.56/3.71  SZS output start Proof for theBenchmark.p
% 3.56/3.71  Clause #0 (by assumption #[]): Eq (Not (And (Exists fun Xx => p → cF Xx) (Exists fun Xx => cF Xx → p) → Exists fun Xx => And (p → cF Xx) (cF Xx → p)))
% 3.56/3.71    True
% 3.56/3.71  Clause #1 (by clausification #[0]): Eq (And (Exists fun Xx => p → cF Xx) (Exists fun Xx => cF Xx → p) → Exists fun Xx => And (p → cF Xx) (cF Xx → p)) False
% 3.56/3.71  Clause #2 (by clausification #[1]): Eq (And (Exists fun Xx => p → cF Xx) (Exists fun Xx => cF Xx → p)) True
% 3.56/3.71  Clause #3 (by clausification #[1]): Eq (Exists fun Xx => And (p → cF Xx) (cF Xx → p)) False
% 3.56/3.71  Clause #4 (by clausification #[2]): Eq (Exists fun Xx => cF Xx → p) True
% 3.56/3.71  Clause #5 (by clausification #[2]): Eq (Exists fun Xx => p → cF Xx) True
% 3.56/3.71  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (cF (skS.0 0 a) → p) True
% 3.56/3.71  Clause #7 (by clausification #[6]): ∀ (a : Iota), Or (Eq (cF (skS.0 0 a)) False) (Eq p True)
% 3.56/3.71  Clause #8 (by clausification #[5]): ∀ (a : Iota), Eq (p → cF (skS.0 1 a)) True
% 3.56/3.71  Clause #9 (by clausification #[8]): ∀ (a : Iota), Or (Eq p False) (Eq (cF (skS.0 1 a)) True)
% 3.56/3.71  Clause #10 (by clausification #[3]): ∀ (a : Iota), Eq (And (p → cF a) (cF a → p)) False
% 3.56/3.71  Clause #11 (by clausification #[10]): ∀ (a : Iota), Or (Eq (p → cF a) False) (Eq (cF a → p) False)
% 3.56/3.71  Clause #12 (by clausification #[11]): ∀ (a : Iota), Or (Eq (cF a → p) False) (Eq p True)
% 3.56/3.71  Clause #13 (by clausification #[11]): ∀ (a : Iota), Or (Eq (cF a → p) False) (Eq (cF a) False)
% 3.56/3.71  Clause #14 (by clausification #[12]): ∀ (a : Iota), Or (Eq p True) (Eq (cF a) True)
% 3.56/3.71  Clause #16 (by superposition #[14, 7]): Or (Eq p True) (Or (Eq True False) (Eq p True))
% 3.56/3.71  Clause #18 (by clausification #[13]): ∀ (a : Iota), Or (Eq (cF a) False) (Eq p False)
% 3.56/3.71  Clause #19 (by clausification #[16]): Or (Eq p True) (Eq p True)
% 3.56/3.71  Clause #20 (by eliminate duplicate literals #[19]): Eq p True
% 3.56/3.71  Clause #22 (by backward demodulation #[20, 9]): ∀ (a : Iota), Or (Eq True False) (Eq (cF (skS.0 1 a)) True)
% 3.56/3.71  Clause #24 (by forward demodulation #[18, 20]): ∀ (a : Iota), Or (Eq (cF a) False) (Eq True False)
% 3.56/3.71  Clause #25 (by clausification #[24]): ∀ (a : Iota), Eq (cF a) False
% 3.56/3.71  Clause #26 (by clausification #[22]): ∀ (a : Iota), Eq (cF (skS.0 1 a)) True
% 3.56/3.71  Clause #27 (by superposition #[26, 25]): Eq True False
% 3.56/3.71  Clause #28 (by clausification #[27]): False
% 3.56/3.71  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------